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TI 84 Calculator: Part II. Macon State College Mary Dwyer Wolfe, Ph.D. Gaston Brouwer, Ph.D. July 2009 http://calculator.maconstate.edu. TI 84 Calculator . Solving equations using the Intersection of Graphs Method Scatterplots and Line Graphs Linear Regression Applications

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Ti 84 calculator part ii

TI 84 Calculator: Part II

Macon State College

Mary Dwyer Wolfe, Ph.D.

Gaston Brouwer, Ph.D.

July 2009

http://calculator.maconstate.edu


Ti 84 calculator
TI 84 Calculator

  • Solving equations using the Intersection of Graphs Method

  • Scatterplots and Line Graphs

  • Linear Regression

    • Applications

  • Quadratic Equations and the Vertex

    • Maximum/Minimum Applications


Solving by the intersections of graphs method
Solving by the Intersections of Graphs Method

The Intersections of Graphs method of solving equations is an alternate method of solving equations (not a replacement method). This method sometimes leads to approximate solutions whereas traditional symbolic methods can usually produce exact solutions. The Intersections of Graphs method is particularly useful when symbolic solutions are not possible.


Solving by the intersections of graphs method1
Solving by the Intersections of Graphs Method

  • Step 1: Enter the left side of the equation for Y1 and the right side of the equation for Y2 (Under Y=)

  • Step 2: Graph the equations in a window where the Intersection is visible.

  • Step 3: Compute the Intersection (2nd CALC 5)

  • Step 4: The x coordinate of the intersection point is the solution to the equation

Solve: 2 – (3x + 5) = 8x + 17


Solving by the intersections of graphs method2
Solving by the Intersections of Graphs Method

Solve: 2 – (3x + 5) = 8x + 17

Step 1:

Step 2:

Step 3:

Step 3: continued …

Step 4:

The solution is approximately x = -1.818182 or x = -1.82 to the nearest hundredth


Solving by the intersections of graphs method3
Solving by the Intersections of Graphs Method

Try this one: Solve 2x2 – 5x = 12

x = -1.5 or x = 4


Solving by the intersections of graphs method4
Solving by the Intersections of Graphs Method

Try this one:

Solve: ex+2= 52x for x


Solving a linear inequality graphically example 1
Solving a Linear Inequality Graphically: Example 1

  • Solve

[2, 15, 1] by [2, 15, 1]

S

T

E

P

1

S

T

E

P

2

First we find the intersection of the left and right side just as we do with equations. Note that the graphs intersect at the point (8.20, 7.59).

Since this is an inequality, we must now determine if the correct sign is > or it flips to <.

S

T

E

P

3


Solving a linear inequality graphically example 1 continued
Solving a Linear Inequality Graphically: Example 1 -- continued

  • Solve

Y1

Y2

S

T

E

P

4

Note that the graphs intersect at the point (8.20, 7.59). So we center an x-value of 8.

When x < 8.20, Y1 < Y2, but when x > 8.20, Y1 > Y2.

Since our original equation was Y1 > Y2 , we know x > 8.20. Thus in interval notation the solution set is (8.20, ∞).


Solving a linear inequality graphically example 2
Solving a Linear Inequality Graphically: Example 2 continued

  • Solve

[10, 10, 1] by [10, 10, 1]

S

T

E

P

1

S

T

E

P

2

Note that the graphs intersect at the point (1.36, 2.72).

Since this is an inequality, we must now determine if the correct sign is > or it flips to <.

S

T

E

P

3


Solving a linear inequality graphically example 21
Solving a Linear Inequality Graphically: Example 2 continued

  • Solve

Y1

Y2

S

T

E

P

4

Note that the graphs intersect at the point (1.36, 2.72).

We find that x ≤ 1.36 when Y1 > Y2.

Thus in interval notation the solution set is ( ∞, 1.36].


Solving compound inequalities
Solving Compound Inequalities continued

Example: Suppose the Fahrenheit temperature x miles

above the ground level is given by T(x) = 88 – 32 x.

Determine the altitudes where the air temp is from 300 to 400.

  • We must solve the inequality

    30 < 88 – 32 x < 40

  • Graph all three parts in the same window


Solving compound inequalities1
Solving Compound Inequalities continued

  • We must solve the inequality -- continued

    30 < 88 – 32 x < 40

  • Find the 2 intersection points

Note: Use the down arrow to switch to the 2nd two equations.

Symbolically,

Between 1.5 and 1.8125 miles above ground level, the air temperature is between 30 and 40 degrees Fahrenheit.


Scatterplots and line graphs
Scatterplots and Line Graphs continued

Graph the set of data:


Scatterplots and line graphs1
Scatterplots and Line Graphs continued

Scatterplot

Line Graph


Least squares regression line of best fit
Least Squares Regression (Line of Best Fit) continued

Note that this data appears to be linear:



Least squares regression line of best fit2
Least Squares Regression (Line of Best Fit) continued

Using this regression equation, f(x) = 2x - 3, what y (or f(x)) is paired with x = 10?

That is, find f(10).

f(10) = 17


Least squares regression line of best fit3
Least Squares Regression (Line of Best Fit) continued

Using this regression equation, f(x) = 2x - 3, what x is paired with y = f(x) = 10?

That is, solve 10 = 2x - 3.

x = 6.5 is paired with y = 10


More linear regression
More Linear Regression continued

Find the equation of the line that passes through the points (2, -3) and (-5, -4).

We could use point-slope form and find the equation symbolically or …

We could use linear regression.


Nearly linear data an application
Nearly Linear Data – An Application continued

From NCTM.org:

Predict the maximum height for a bike that weighs 21.5 pounds if all other factors are held constant.


Nearly linear data an application1
Nearly Linear Data – An Application continued

Predict the maximum height for a bike that weighs 21.5 pounds if all other factors are held constant.

A height of 9.994 inches is expected for a weight of 21.5 pounds.


Nearly linear data an application2
Nearly Linear Data – An Application continued

Your turn! You already have the model in your calculator!

Predict the maximum weight for a bike that so that it can reach a height of 10.5 inches if all other factors are held constant.


Nearly linear data an application3
Nearly Linear Data – An Application continued

Predict the maximum weight for a bike that so that it can reach a height of 10.5 inches if all other factors are held constant.

A weight of about 18.3 pounds is expected for a height of 10.5 inches.


Finding a vertex max min point
Finding a Vertex (Max/Min Point) continued

Find the vertex of y = 2x2 – 7x - 1

The vertex is approximately (1.75, -7.125)


Find the vertex
Find the Vertex continued

Your Turn!

Find the vertex of y = -3x2 + 5x - 4

The vertex is approximately (0.833, -1.912)


Application find a maximum
Application – Find a Maximum continued

A home owner has 200 feet of fencing to make a rectangular garden in his yard that is protected from the rabbits and deer. He decides to use the long side of the house as one side of the fenced area so a larger area can be obtained as less fencing is needed. That way he can walk out the back door into the garden. What of the dimensions of garden that maximize the area for planting?

200 – 2x

x

x

The house!

A(x) = x(200 – 2x)


Application find a maximum1
Application – Find a Maximum continued

A(x) = x(200 – 2x)

X = 50

200 – 2x = 200 – 2(50) = 100

The dimensions are 50 by 100 feet.


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