- 568 Views
- Uploaded on

Download Presentation
## PowerPoint Slideshow about 'TI 84 Calculator: Part II' - sanjiv

**An Image/Link below is provided (as is) to download presentation**

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -

Presentation Transcript

### TI 84 Calculator: Part II

Macon State College

Mary Dwyer Wolfe, Ph.D.

Gaston Brouwer, Ph.D.

July 2009

http://calculator.maconstate.edu

TI 84 Calculator

- Solving equations using the Intersection of Graphs Method
- Scatterplots and Line Graphs
- Linear Regression
- Applications
- Quadratic Equations and the Vertex
- Maximum/Minimum Applications

Solving by the Intersections of Graphs Method

The Intersections of Graphs method of solving equations is an alternate method of solving equations (not a replacement method). This method sometimes leads to approximate solutions whereas traditional symbolic methods can usually produce exact solutions. The Intersections of Graphs method is particularly useful when symbolic solutions are not possible.

Solving by the Intersections of Graphs Method

- Step 1: Enter the left side of the equation for Y1 and the right side of the equation for Y2 (Under Y=)
- Step 2: Graph the equations in a window where the Intersection is visible.
- Step 3: Compute the Intersection (2nd CALC 5)
- Step 4: The x coordinate of the intersection point is the solution to the equation

Solve: 2 – (3x + 5) = 8x + 17

Solving by the Intersections of Graphs Method

Solve: 2 – (3x + 5) = 8x + 17

Step 1:

Step 2:

Step 3:

Step 3: continued …

Step 4:

The solution is approximately x = -1.818182 or x = -1.82 to the nearest hundredth

Solving a Linear Inequality Graphically: Example 1

- Solve

[2, 15, 1] by [2, 15, 1]

S

T

E

P

1

S

T

E

P

2

First we find the intersection of the left and right side just as we do with equations. Note that the graphs intersect at the point (8.20, 7.59).

Since this is an inequality, we must now determine if the correct sign is > or it flips to <.

S

T

E

P

3

Solving a Linear Inequality Graphically: Example 1 -- continued

- Solve

Y1

Y2

S

T

E

P

4

Note that the graphs intersect at the point (8.20, 7.59). So we center an x-value of 8.

When x < 8.20, Y1 < Y2, but when x > 8.20, Y1 > Y2.

Since our original equation was Y1 > Y2 , we know x > 8.20. Thus in interval notation the solution set is (8.20, ∞).

Solving a Linear Inequality Graphically: Example 2

- Solve

[10, 10, 1] by [10, 10, 1]

S

T

E

P

1

S

T

E

P

2

Note that the graphs intersect at the point (1.36, 2.72).

Since this is an inequality, we must now determine if the correct sign is > or it flips to <.

S

T

E

P

3

Solving a Linear Inequality Graphically: Example 2

- Solve

Y1

Y2

S

T

E

P

4

Note that the graphs intersect at the point (1.36, 2.72).

We find that x ≤ 1.36 when Y1 > Y2.

Thus in interval notation the solution set is ( ∞, 1.36].

Solving Compound Inequalities

Example: Suppose the Fahrenheit temperature x miles

above the ground level is given by T(x) = 88 – 32 x.

Determine the altitudes where the air temp is from 300 to 400.

- We must solve the inequality

30 < 88 – 32 x < 40

- Graph all three parts in the same window

Solving Compound Inequalities

- We must solve the inequality -- continued

30 < 88 – 32 x < 40

- Find the 2 intersection points

Note: Use the down arrow to switch to the 2nd two equations.

Symbolically,

Between 1.5 and 1.8125 miles above ground level, the air temperature is between 30 and 40 degrees Fahrenheit.

Scatterplots and Line Graphs

Graph the set of data:

Least Squares Regression (Line of Best Fit)

Note that this data appears to be linear:

Least Squares Regression (Line of Best Fit)

f(x) = 2x - 3

Least Squares Regression (Line of Best Fit)

Using this regression equation, f(x) = 2x - 3, what y (or f(x)) is paired with x = 10?

That is, find f(10).

f(10) = 17

Least Squares Regression (Line of Best Fit)

Using this regression equation, f(x) = 2x - 3, what x is paired with y = f(x) = 10?

That is, solve 10 = 2x - 3.

x = 6.5 is paired with y = 10

More Linear Regression

Find the equation of the line that passes through the points (2, -3) and (-5, -4).

We could use point-slope form and find the equation symbolically or …

We could use linear regression.

Nearly Linear Data – An Application

From NCTM.org:

Predict the maximum height for a bike that weighs 21.5 pounds if all other factors are held constant.

Nearly Linear Data – An Application

Predict the maximum height for a bike that weighs 21.5 pounds if all other factors are held constant.

A height of 9.994 inches is expected for a weight of 21.5 pounds.

Nearly Linear Data – An Application

Your turn! You already have the model in your calculator!

Predict the maximum weight for a bike that so that it can reach a height of 10.5 inches if all other factors are held constant.

Nearly Linear Data – An Application

Predict the maximum weight for a bike that so that it can reach a height of 10.5 inches if all other factors are held constant.

A weight of about 18.3 pounds is expected for a height of 10.5 inches.

Finding a Vertex (Max/Min Point)

Find the vertex of y = 2x2 – 7x - 1

The vertex is approximately (1.75, -7.125)

Find the Vertex

Your Turn!

Find the vertex of y = -3x2 + 5x - 4

The vertex is approximately (0.833, -1.912)

Application – Find a Maximum

A home owner has 200 feet of fencing to make a rectangular garden in his yard that is protected from the rabbits and deer. He decides to use the long side of the house as one side of the fenced area so a larger area can be obtained as less fencing is needed. That way he can walk out the back door into the garden. What of the dimensions of garden that maximize the area for planting?

200 – 2x

x

x

The house!

A(x) = x(200 – 2x)

Application – Find a Maximum

A(x) = x(200 – 2x)

X = 50

200 – 2x = 200 – 2(50) = 100

The dimensions are 50 by 100 feet.

Download Presentation

Connecting to Server..