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TI 84 Calculator: Part II. Macon State College Mary Dwyer Wolfe, Ph.D. Gaston Brouwer, Ph.D. July 2009 http://calculator.maconstate.edu. TI 84 Calculator . Solving equations using the Intersection of Graphs Method Scatterplots and Line Graphs Linear Regression Applications

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TI 84 Calculator: Part II

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Ti 84 calculator part ii

TI 84 Calculator: Part II

Macon State College

Mary Dwyer Wolfe, Ph.D.

Gaston Brouwer, Ph.D.

July 2009

http://calculator.maconstate.edu


Ti 84 calculator

TI 84 Calculator

  • Solving equations using the Intersection of Graphs Method

  • Scatterplots and Line Graphs

  • Linear Regression

    • Applications

  • Quadratic Equations and the Vertex

    • Maximum/Minimum Applications


Solving by the intersections of graphs method

Solving by the Intersections of Graphs Method

The Intersections of Graphs method of solving equations is an alternate method of solving equations (not a replacement method). This method sometimes leads to approximate solutions whereas traditional symbolic methods can usually produce exact solutions. The Intersections of Graphs method is particularly useful when symbolic solutions are not possible.


Solving by the intersections of graphs method1

Solving by the Intersections of Graphs Method

  • Step 1: Enter the left side of the equation for Y1 and the right side of the equation for Y2 (Under Y=)

  • Step 2: Graph the equations in a window where the Intersection is visible.

  • Step 3: Compute the Intersection (2nd CALC 5)

  • Step 4: The x coordinate of the intersection point is the solution to the equation

Solve: 2 – (3x + 5) = 8x + 17


Solving by the intersections of graphs method2

Solving by the Intersections of Graphs Method

Solve: 2 – (3x + 5) = 8x + 17

Step 1:

Step 2:

Step 3:

Step 3: continued …

Step 4:

The solution is approximately x = -1.818182 or x = -1.82 to the nearest hundredth


Solving by the intersections of graphs method3

Solving by the Intersections of Graphs Method

Try this one: Solve 2x2 – 5x = 12

x = -1.5 or x = 4


Solving by the intersections of graphs method4

Solving by the Intersections of Graphs Method

Try this one:

Solve: ex+2= 52x for x


Solving a linear inequality graphically example 1

Solving a Linear Inequality Graphically: Example 1

  • Solve

[2, 15, 1] by [2, 15, 1]

S

T

E

P

1

S

T

E

P

2

First we find the intersection of the left and right side just as we do with equations. Note that the graphs intersect at the point (8.20, 7.59).

Since this is an inequality, we must now determine if the correct sign is > or it flips to <.

S

T

E

P

3


Solving a linear inequality graphically example 1 continued

Solving a Linear Inequality Graphically: Example 1 -- continued

  • Solve

Y1

Y2

S

T

E

P

4

Note that the graphs intersect at the point (8.20, 7.59). So we center an x-value of 8.

When x < 8.20, Y1 < Y2, but when x > 8.20, Y1 > Y2.

Since our original equation was Y1 > Y2 , we know x > 8.20. Thus in interval notation the solution set is (8.20, ∞).


Solving a linear inequality graphically example 2

Solving a Linear Inequality Graphically: Example 2

  • Solve

[10, 10, 1] by [10, 10, 1]

S

T

E

P

1

S

T

E

P

2

Note that the graphs intersect at the point (1.36, 2.72).

Since this is an inequality, we must now determine if the correct sign is > or it flips to <.

S

T

E

P

3


Solving a linear inequality graphically example 21

Solving a Linear Inequality Graphically: Example 2

  • Solve

Y1

Y2

S

T

E

P

4

Note that the graphs intersect at the point (1.36, 2.72).

We find that x ≤ 1.36 when Y1 > Y2.

Thus in interval notation the solution set is ( ∞, 1.36].


Solving compound inequalities

Solving Compound Inequalities

Example: Suppose the Fahrenheit temperature x miles

above the ground level is given by T(x) = 88 – 32 x.

Determine the altitudes where the air temp is from 300 to 400.

  • We must solve the inequality

    30 < 88 – 32 x < 40

  • Graph all three parts in the same window


Solving compound inequalities1

Solving Compound Inequalities

  • We must solve the inequality -- continued

    30 < 88 – 32 x < 40

  • Find the 2 intersection points

Note: Use the down arrow to switch to the 2nd two equations.

Symbolically,

Between 1.5 and 1.8125 miles above ground level, the air temperature is between 30 and 40 degrees Fahrenheit.


Scatterplots and line graphs

Scatterplots and Line Graphs

Graph the set of data:


Scatterplots and line graphs1

Scatterplots and Line Graphs

Scatterplot

Line Graph


Least squares regression line of best fit

Least Squares Regression (Line of Best Fit)

Note that this data appears to be linear:


Least squares regression line of best fit1

Least Squares Regression (Line of Best Fit)

f(x) = 2x - 3


Least squares regression line of best fit2

Least Squares Regression (Line of Best Fit)

Using this regression equation, f(x) = 2x - 3, what y (or f(x)) is paired with x = 10?

That is, find f(10).

f(10) = 17


Least squares regression line of best fit3

Least Squares Regression (Line of Best Fit)

Using this regression equation, f(x) = 2x - 3, what x is paired with y = f(x) = 10?

That is, solve 10 = 2x - 3.

x = 6.5 is paired with y = 10


More linear regression

More Linear Regression

Find the equation of the line that passes through the points (2, -3) and (-5, -4).

We could use point-slope form and find the equation symbolically or …

We could use linear regression.


Nearly linear data an application

Nearly Linear Data – An Application

From NCTM.org:

Predict the maximum height for a bike that weighs 21.5 pounds if all other factors are held constant.


Nearly linear data an application1

Nearly Linear Data – An Application

Predict the maximum height for a bike that weighs 21.5 pounds if all other factors are held constant.

A height of 9.994 inches is expected for a weight of 21.5 pounds.


Nearly linear data an application2

Nearly Linear Data – An Application

Your turn! You already have the model in your calculator!

Predict the maximum weight for a bike that so that it can reach a height of 10.5 inches if all other factors are held constant.


Nearly linear data an application3

Nearly Linear Data – An Application

Predict the maximum weight for a bike that so that it can reach a height of 10.5 inches if all other factors are held constant.

A weight of about 18.3 pounds is expected for a height of 10.5 inches.


Finding a vertex max min point

Finding a Vertex (Max/Min Point)

Find the vertex of y = 2x2 – 7x - 1

The vertex is approximately (1.75, -7.125)


Find the vertex

Find the Vertex

Your Turn!

Find the vertex of y = -3x2 + 5x - 4

The vertex is approximately (0.833, -1.912)


Application find a maximum

Application – Find a Maximum

A home owner has 200 feet of fencing to make a rectangular garden in his yard that is protected from the rabbits and deer. He decides to use the long side of the house as one side of the fenced area so a larger area can be obtained as less fencing is needed. That way he can walk out the back door into the garden. What of the dimensions of garden that maximize the area for planting?

200 – 2x

x

x

The house!

A(x) = x(200 – 2x)


Application find a maximum1

Application – Find a Maximum

A(x) = x(200 – 2x)

X = 50

200 – 2x = 200 – 2(50) = 100

The dimensions are 50 by 100 feet.


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