Hardy weinberg
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Hardy-Weinberg. In a species of fish, a single gene controls color. In a population of 100 fish, there are 60 red fish, 30 purple fish, and 10 blue fish. What is the allele frequency of the allele for red color? What is the allele frequency of the blue allele?.

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Hardy-Weinberg

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Hardy weinberg

Hardy-Weinberg

In a species of fish, a single gene controls color. In a population of 100 fish, there are 60 red fish, 30 purple fish, and 10 blue fish.

What is the allele frequency of the allele for red color?

What is the allele frequency of the blue allele?


P f rr rr q f rr rr

  • PR = f(RR) + ½ f(Rr) = .60 + ½ (.30) = .75

  • Qr = f(rr) + ½ f(Rr) = .10 + ½ f(.30) = .25

P = f(RR) + ½ (Rr)Q = f(rr) + ½ (Rr)


Hardy weinberg principle

  • The Hardy-Weinberg principle is often stated as:

    • In the absence of other influences, phenotype and allele frequencies in a population remain constant over time

  • Thus, the principle describes the behavior of alleles in a large, stable population

Hardy-Weinberg Principle


Here s what it s good for

  • There were 2 types of candy you will chose from the bag at random – no peeking or trading!

  • The two different colors represent 2 different alleles, and the bag represents a gene pool.

  • The silver chocolates which we will call “A” has a frequency of .47

  • The gold chocolates, “a” has a frequency of .53

  • Here’s the bet: If I know the frequencies of alleles in the bag, I can predict how many of you got two silvers, how many got 1 of each, and how many got 2 golds.

Here’s What It’s Good For


My hypothesis

  • About 22% of you selected 2 silver chocolates.

  • About 50% of you selected 1 of each color.

  • About 28% of you got 2 gold chocolates.

My hypothesis


How it works

How it works…


Remember p q 1

  • Consider the following Punnet square, showing a cross between 2 heterozygous individuals for allele A:

Remember, P + Q = 1


Defining p 2 and q 2

  • In the population as a whole, the chance of a new individual receiving an “A” allele is equal to that allele’s frequency in the population, represented as p.

  • Thus, the chance of receiving 2 “A” alleles is p x p, or p2, and the chance of receiving two “a” alleles is q2.

Defining P2 and Q2


Heterozygotes

  • The probability for producing a heterozygote = p x q, or pq.

  • Since there are 2 possible ways to produce a heterozygote, the total probability is 2pq

Heterozygotes


The hardy weinberg equation

  • In any population in equilibrium,

  • p + q = 1

  • Therefore, (p + q)2 = 1

  • Expanded… p2 + 2pq + q2 = 1

The Hardy-Weinberg Equation


Relationships between allele frequency and phenotype frequency

  • In a population in equilibrium,

  • f(AA) = p2

  • f(Aa) = 2pq

  • f(aa) = q2

  • Remember: p = f(A) and q = f(a)

Relationships between allele frequency and phenotype frequency


Simple application

  • Like any formula with 2 variables, if one is known, the other can be determined.

  • For this type of problem, use the simple form P + Q = 1

  • Example: The allele for tongue rolling has a frequency of .95. What is the frequency of the allele for non-tongue rolling?

Simple Application


Predictive ability

  • A more useful way to use the Hardy-Weinberg equation is to convert between phenotype frequencies in a population and allele frequencies in a gene pool.

  • Use p2 + 2pq + q2 = 1

  • Remember that:

    • p2 = f(AA)

    • 2pq = f(Aa)

    • q2 = f(aa)

Predictive ability


Determining heterozygote frequencies

  • Example problem:

  • In chickens, having brown feathers is dominant to having white feathers. In a population of 200 birds, 180 have brown feathers. What are the allele frequencies of B and b in the population?

  • Step 1 – figure out the value of p and q

Determining heterozygote frequencies


Finding allele frequencies

  • Q2 = f(bb) these are the white birds

  • Q2 = 20/200

  • Q2 = .10

  • Q = .32

  • Since P + Q = 1 P = 1 – Q

  • P = 1 - .32 = .68

Finding Allele Frequencies


Hidden heterozygotes

  • In the same population of birds, how many of the brown birds are heterozygous for the trait?

  • What term in the Harvey-Weinberg equation gives us the frequency of heterozygotes?

  • 2pq

Hidden Heterozygotes


Genotype frequency

  • Since

    • f(Bb) = 2pq

    • p = .68

    • q = .32

  • f(Bb) = 2(.68)(.32)

  • f(Bb) = .44

  • 44% of the birds are heterozygotes!

Genotype frequency


Completing the bird

  • So… in our population of 200 birds, 44% are Bb, 10% are bb, and the remainder, 46% should be BB!

  • Let’s check the equation. Since f(BB) = p2, do we get the same answer from the equation and subtraction?

  • P2 should = .44 (the frequency of BB)

  • .682 = .46

  • It works!

Completing the Bird


Love the symmetric beauty

Love the Symmetric Beauty…


Another example

  • If 9% of an African population is born with a severe form of sickle-cell anemia (ss), what percentage of the population will be more resistant to malaria because they are heterozygous(Ss) for the sickle-cell gene?

Another example…


Why sickle cell

  • f(ss) = .09 = q2

  • Q2 = .09

  • Q = .3

  • Therefore, P = 1 – Q = 1 - .3 = .7

  • f(Ss) = 2pq = 2(.7)(.3) = .42

  • 42% have increased resistance to malaria (Ss)

Why Sickle Cell?


Your problems

  • When solving problems:

    • Identify what you know, remembering

      • P2 = f(AA)

      • 2pq = f(Aa)

      • Q2 = f(aa)

    • Then, solve for what you don’t know – there’s only 5 different quantities listed above: 3 genotype frequencies, and 2 allele frequencies

    • p2 + 2pq + q2 = 1

Your Problems


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