1 / 5

Persamaan Differensial Homogin dengan Koef. Konstan

Persamaan Differensial Homogin dengan Koef. Konstan. Bentuk :. Operator Differensial Linier: f(D) = y Persamaan karakteristik: f(m) = 0. Akar f(m) semua riil dan berlainan. Misalkan akar-akar f(m) = 0 adalah m 1 ≠ m 2 ≠ m 3 ≠ m 4

rue
Download Presentation

Persamaan Differensial Homogin dengan Koef. Konstan

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Persamaan Differensial Homogin dengan Koef. Konstan Bentuk :

  2. Operator Differensial Linier: f(D) = y Persamaan karakteristik: f(m) = 0

  3. Akar f(m) semua riil dan berlainan • Misalkan akar-akar f(m) = 0 adalah m1≠ m2 ≠ m3 ≠ m4 Penyelesaian umum:

  4. Akar f(m) semua riil dan ada yang sama • Misalkan akar-akar f(m) = 0 adalah m1 = m2 ≠ m3 = m4. • Penyelesaian umum:

  5. Akar f(m) kompleks berlainan • Misalkan akar f(m) = 0 adalah m = a + bi • Penyelesaian umum:

More Related