1 / 28

Splash Screen

Splash Screen. Five-Minute Check (over Chapter 1) CCSS Then/Now New Vocabulary Key Concept: Functions Example 1: Domain and Range Key Concept: Vertical Line Test Example 2: Real-World Example Example 3: Graph a Relation Example 4: Evaluate a Function. Lesson Menu.

pearljames
Download Presentation

Splash Screen

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Splash Screen

  2. Five-Minute Check (over Chapter 1) CCSS Then/Now New Vocabulary Key Concept: Functions Example 1: Domain and Range Key Concept: Vertical Line Test Example 2: Real-World Example Example 3: Graph a Relation Example 4: Evaluate a Function Lesson Menu

  3. Name the property illustrated by –15b + 15b = 0. A. Additive Identity B. Multiplicative Inverse C. Inverse Property of Addition D. Symmetry 5-Minute Check 2

  4. Solve 2(c – 5) – 2 = 8 + c. A. –4 B. 4 C. 10 D. 20 5-Minute Check 3

  5. A. {b | b ≤ 2} B. {b | b < 2} C. {b | b≥ 2} D. {b | b > 2} Solve 2b – 5 ≤ –1. Graph the solution set on a number line. 5-Minute Check 5

  6. A. eans B. eans C. eans D. eans Which algebraic equation shows the sentence four plus a number divided by six is equal to the product of twelve and the same number? 5-Minute Check 6

  7. Content Standards F.IF.4 For a function that models a relationship between two quantities, interpret key features of graphs and tables in terms of the quantities, and sketch graphs showing key features given a verbal description of the relationship. F.IF.5 Relate the domain of a function to its graph and, where applicable, to the quantitative relationship it describes. Mathematical Practices 1 Make sense of problems and persevere in solving them. 7 Look for and make use of structure. CCSS

  8. You identified domains and ranges for given situations. • Analyze relations and functions. • Use equations of relations and functions. Then/Now

  9. one-to-one function • onto function • discrete relation • continuous relation • vertical line test • independent variable • dependent variable • function notation Vocabulary

  10. Concept 1

  11. Domain and Range State the domain and range of the relation. Then determine whether the relation is a function. If it is a function, determine if it is one-to-one, onto, both, or neither. The relation is {(1, 2), (3, 3), (0, –2), (–4, –2), (–3, 1)}. Answer: The domain is {–4, –3, 0, 1, 3}. The range is {–2, 1, 2, 3}. Each member of the domain is paired with one member of the range, so this relation is a function. It is onto, but not one-to-one. Example 1

  12. State the domain and range of the relation shown in the graph. Is the relation a function? A. domain: {–2, –1, 0, 1} range: {–3, 0, 2, 3}Yes, it is a function. B. domain: {–3, 0, 2, 3} range: {–2, –1, 0, 1}Yes, it is a function. C. domain: {–2, –1, 0, 1} range: {–3, 0, 2, 3}No, it is not a function. D. domain: {–3, 0, 2, 3} range: {–2, –1, 0, 1}No, it is not a function. Example 1

  13. Concept 2

  14. TRANSPORTATION The table shows the average fuel efficiency in miles per gallon for SUVs for several years. Graph this information and determine whether it represents a function. Is this relation discrete or continuous? Example 2

  15. Use the vertical line test. Notice that no vertical line can be drawn that contains more than one of the data points. Example 2

  16. Answer:Yes, this relation is a function. Because the graph consists of distinct points, the relation is discrete. Example 2

  17. HEALTH The table shows the average weight of a baby for several months during the first year. Graph this information and determine whether it represents a function. Example 2

  18. A. Yes, this relation is a B. No, this function. relation is not a function. C. Yes, this relation is a D. No, this function. relation is not a function. Example 2

  19. Graph a Relation Graph y = 3x – 1 and determine the domain and range. Then determine whether the equation is a function, is one-to-one, onto, both, or neither. State whether it is discrete or continuous. Make a table of values to find ordered pairs that satisfy the equation. Choose values for x and find the corresponding values for y. Then graph the ordered pairs. Example 3

  20. Graph a Relation Find the domain and range. Since x can be any real number, there is an infinite number of ordered pairs that can be graphed. All of them lie on the line shown. Notice that every real number is the x-coordinate of some point on the line. Also, every real number is the y-coordinate of some point on the line. Answer: The domain and range are both allreal numbers. Example 3

  21. Graph a Relation Determine whether the relation is a function and state whether it is discrete or continuous. Thisgraph passes the vertical line test. Every x-value is paired with exactly one unique y-value, and every y-value corresponds to an x-value. Answer: Yes, the equation y = 3x – 1 represents a function. The function is both one-to-one and onto. Since the domain and range are both all real numbers, the relation is continuous. Example 3

  22. A. B. C. D. Graph y = 2x + 5. Example 3

  23. Evaluate a Function A. Given f(x) = x3 – 3, find f(–2). f(x) = x3 – 3 Original function f(–2) = (–2)3 – 3 Substitute. = –8 – 3 or –11 Simplify. Answer:f(–2) = –11 Example 4A

  24. Evaluate a Function B. Given f(x) = x3 – 3, find f(2t). f(x) = x3 – 3 Original function f(2t) = (2t)3 – 3 Substitute. = 8t3 – 3 (2t)3 = 8t3 Answer:f(2t) = 8t3 – 3 Example 4B

  25. A. Given f(x) = x2 + 5, find f(–1). A. –4 B. –3 C. 3 D. 6 Example 4A

  26. B. Given f(x) = x2 + 5, find f(3a). A. 3a2 + 5 B.a2 + 8 C. 6a2 + 5 D. 9a2 + 5 Example 4B

  27. End of the Lesson

  28. Pages 65 – 67 #11 – 31 odd, 35, 45, 50, 53, 55

More Related