1 / 15

# Equations of Uniform Accelerated Motion - PowerPoint PPT Presentation

Equations of Uniform Accelerated Motion . AP Physics C Mrs. Coyle . Uniform Accelerated Motion. Motion with constant acceleration Straight line Same direction. Equations for Uniform Accelerated Motion. Velocity v= v o + at Position x= x o + v o t + ½ at 2

Related searches for Equations of Uniform Accelerated Motion

I am the owner, or an agent authorized to act on behalf of the owner, of the copyrighted work described.

## PowerPoint Slideshow about 'Equations of Uniform Accelerated Motion' - neka

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -
Presentation Transcript

### Equations of Uniform Accelerated Motion

AP Physics CMrs. Coyle

• Motion with constant acceleration

• Straight line

• Same direction

• Velocity v= vo+ at

• Position x= xo + vot + ½ at2

• v2 = vo2 + 2a(x-xo)

Remember:

Displacement= Dx = x-xo

MoreEquations of Motion for Uniform Accelerated Motion

• vavg= ½ (vo+v)

• Dx = ½ (vo+ v)t

• Assume that ti=0

Position (m)

x= xo + vot + ½ at2

Parabola

o

Time (s)

Slope of Tangent at a given time= Instantaneous Velocity at that time

v= vo+ at

Velocity (m/s)

o

Time (s)

Slope of Line= Acceleration

Area Under Line=Displacement

Acceleration (m/s2)

o

Time (s)

Area under line = Change in Velocity

How do we derive Dx = ½ (vo+ v)t

from the graph?

v

Velocity (m/s)

vo

o

Time (s)

t

Hint: Area Under the Line=Displacement Δx

Position (m)

Parabola

o

Time (s)

Velocity (m/s)

o

Time (s)

Slope of Line= Acceleration

Area Under Line=Displacement

Acceleration (m/s2)

o

Time (s)

Area under line = Change in Velocity

How do we derive x= xo + vot + ½ at2?

and then substitute for vthat v= vo+at.

How do we derive v2 = vo2 + 2a(x-xo)?

then substitute for t= (v– vo) /a

A ball initially stationary, accelerates at 0.25m/s2 down a 2m inclined plane. It then rolls up another incline, where it comes to rest after rolling up 1m.

a) What is the speed of the ball at the bottom of the incline and how much time did this take?

b) What is the acceleration along the second plane?

Answer: a) 1m/s, 4sec, b) -0.5m/s2

A Mustang travelling with a constant velocity of 35m/s, passes a stationary police car.

The reaction time of the officer was 2.5sec and he then accelerates at 5.0 m/s2 to catch the Mustang. How long does it take for the police car to catch the Mustang?