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# Tutorial 3 solutions PowerPoint PPT Presentation

Tutorial 3 solutions. Lecturer: Miss Anis Atikah Ahmad Tel: +604 976 3245 Email: anisatikah@unimap.edu.my. Questions. Write the rate laws for the following reactions assuming each reaction follows an elementary rate laws . C 2 H 6 → C 2 H 4 + H 2

Tutorial 3 solutions

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## Tutorial 3 solutions

Tel: +604 976 3245

Email: anisatikah@unimap.edu.my

### Questions

• Write the rate laws for the following reactions assuming each reaction follows an elementary rate laws.

• C2H6 → C2H4 + H2

• (CH3)3COOC(CH3)3 ⇌ C2H6 + 2CH3COCH3

• Write the rate law for the reaction:

2A + B → C

if the reaction

• is second order in B and overall third order,

• is zero order in A and first order in B

• is zero order in both A and B

• is first order in A and overall zero order

• The formation of ortho-nitroanilineis formed from the reaction of ortho-nitrochlorobenzene(ONCB) and aqueous ammonia.

The liquid-phase reaction is first order in both ONCB and ammonia with k= 0.0017 m3/kmol-min at 188°C with E = 11,273 cal/mol. The initial entering concentration of ONCB and ammonia are 1.8 kmol/m3 and 6.6 kmol/m3 respectively.

• Write the rate law for the rate of disappearance of ONCB in terms of concentration.

• Set up stoichiometric table for this reaction for a flow system.

• Explain how part (a) and (b) would be different for a batch system.

• Write –rAsolely as a function of conversion.

• What is the initial rate of reaction (X=0) at 188°C and at 25°C?

• What is the rate of reaction when X = 0.9 at 188°C and at 25°C?

• What would be the corresponding CSTR volume at 25°C to achieve 90% conversion at 188°C for a feed rate of 2 dm3/min

• Write the rate laws for the following reactions assuming each reaction follows an elementary rate laws.

• C2H6 → C2H4 + H2

• (CH3)3COOC(CH3)3 ⇌ C2H6 + 2CH3COCH3

### Question (1)

(a)

(b)

• C2H6 → C2H4 + H2

• A → B + C

• (CH3)3COOC(CH3)3 ⇌ C2H6 + 2CH3COCH3

• A ⇌ B + 2C

• Write the rate law for the reaction:

2A + B → C

if the reaction

• is second order in B and overall third order

• is zero order in A and first order in B

• is zero order in both A and B

• is first order in A and overall zero order

(a)

(b)

(c)

(d)

### Question (3)(a)

The formation of ortho-nitroanilineis formed from the reaction of ortho-nitrochlorobenzene(ONCB) and aqueous ammonia.

The liquid-phase reaction is first order in both ONCB and ammonia with k= 0.0017 m3/kmol-min at 188°C with E = 11,273 cal/mol. The initial entering concentration of ONCB and ammonia are 1.8 kmol/m3 and 6.6 kmol/m3 respectively.

• Write the rate law for the rate of disappearance of ONCB in terms of concentration.

Let A = ONCB, B = NH3, C = Nitroaniline , D = NH4Cl

### Question (3)(b)

A + 2B → C + D

• Set up stoichiometric table for this reaction for a flow system

### Question (3)(c)

• Explain how part (a) and (b) would be different for a batch system

For batch system,

### Question (3)(d)

• Write –rAsolely as a function of conversion.

For liquid phase rxn, υ= υ0

### Question (3)(d)

Substituting the concentration of A & B;

### Question (3)(e)

---(1)

• What is the initial rate of reaction (X=0) at 188°C and at 25°C

i) At T= 188°C, k =0.017m3/kmol-min

Substituting X=0 and k =0.017m3/kmol-min into (1);

### Question (3)(e)

---(1)

• What is the initial rate of reaction (X=0) at 188°C and at 25°C

ii) At T= 25°C (298.15 K), k =? m3/kmol-min

Find k at T =25°C first

k at initial T is

k at any temperature is

Taking the ratio;

### Question (3)(e)

---(1)

• What is the initial rate of reaction (X=0) at 188°C and at 25°C

ii) Now we know that, at T= 25°C (298.15 K), k = 2.039 x 10-6 m3/kmol-min

Therefore, we can calculate –rA at 25° by susbtituting

k= 2.039 x 10-6m3/kmol-min, and X = 0 in eq (1).

### Question (3)(f)

---(1)

• What is the rate of reaction when X = 0.9 at 188°C and at 25°C?

(i) At T= 188°C, k =0.0017m3/kmol-min

Substituting X=0.9 and k =0.017m3/kmol-min into (1);

### Question (3)(f)

---(1)

• What is the rate of reaction when X = 0.9 at 188°C and at 25°C?

(ii) From part (e) when T= 25°C, k = 2.039 x 10-6 m3/kmol-min

Substituting X=0.9 and k = k = 2.039 x 10-6 m3/kmol-min into (1);

### Question (3)(g)

• What would be the corresponding CSTR volume at 25°C to achieve 90% conversion at 188°C for a feed rate of 2 dm3/min?

Substituting the value of CA0, υ0 and –rA(at 288°C & X=0.9);