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Speeding Up Algorithms for Hidden Markov Models by Exploiting Repetitions

Speeding Up Algorithms for Hidden Markov Models by Exploiting Repetitions. Yuri Lifshits (Caltech) Shay Mozes (Brown Uni.) Oren Weimann (MIT) Michal Ziv-Ukelson (Ben-Gurion Uni.). Hidden Markov Models (HMMs). Sunny. Rainy. Cloudy.

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Speeding Up Algorithms for Hidden Markov Models by Exploiting Repetitions

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  1. Speeding Up Algorithms for Hidden Markov Models by Exploiting Repetitions Yuri Lifshits (Caltech) Shay Mozes (Brown Uni.) Oren Weimann (MIT) Michal Ziv-Ukelson (Ben-Gurion Uni.)

  2. Hidden Markov Models (HMMs) Sunny Rainy Cloudy Transition probabilities: the probability of the weather given the previous day's weather.Pi←j = the probability to make a transition to state i from state j Hidden States: sunny, rainy, cloudy. q1 , … ,qk

  3. Hidden Markov Models (HMMs) Observable states : the states of the process that are `visible‘ Σ ={soggy, damp, dryish, dry} Humidity in IBM Emission probabilities : the probability of observing a particular observable state given that we are in a particular hidden state. ei(σ) = the probability to observe σєΣ given that the state is i

  4. Shortly: • HiddenMarkov Models are extensively used to model processes in many fields (error-correction, speech recognition, computational linguistics, bioinformatics) • We show how to exploit repetitions to obtain speedup of HMM algorithms • Can use different compression schemes • Applies to several decoding and training algorithms

  5. HMM Decoding and Training • Decoding: Given the model (emission and transition probabilities) and an observed sequence X, find the hidden sequence of states that is most likely to have generated the observed sequence. • X = dry,dry,damp,soggy… • Training: Given the number of hidden states and an observed sequence estimate emission and transition probabilities Pi←j , ei(σ)

  6. Decoding time 1 1 1 1 2 2 2 2 states k k k k xn x1 x2 x3 observed string • Decoding: Given the model and the observed string find the hidden sequence of states that is most likely to have generated the observed string

  7. Decoding – Viterbi’s Algorithm (VA) time states v6[4]=maxj{e4(c)·P4←j·v5[j]} v6[4]= e4(c)·P4←2·v5[2] v5[2] v6[4]= P4←2·v5[2] v6[4]= v5[2] probability of best sequence of states that emits first 5 chars and ends in state 2 probability of best sequence of states that emits first 5 chars and ends in state j

  8. Outline • Overview • Exploiting repetitions • Using Four-Russions speedup • Using LZ78 • Using Run-Length Encoding • Training • Summary of results

  9. VA in Matrix Notation j j i k i v1[i]=maxj{ei(x1)·Pi←j · v0[j]} Mij(σ) = ei (σ)·Pi←j 1 1 1 1 1 2 2 2 2 2 v1[i]=maxj{Mij(x1) · v0[j]} (A⊗B)ij= maxk{Aik ·Bkj} k k k k k σ Viterbi’s algorithm: O(k2n) v1= M(x1) ⊗v0 vn=M(xn) ⊗ M(xn-1) ⊗ ··· ⊗ M(x1) ⊗v0 v2= M(x2) ⊗ M(x1) ⊗v0 x1 x2 O(k3n)

  10. Exploiting Repetitions c a t g a a c t g a a c vn=M(c)⊗M(a)⊗M(a)⊗M(g)⊗M(t)⊗M(c)⊗M(a)⊗M(a)⊗M(g)⊗M(t)⊗M(a)⊗M(c)⊗v0 12 steps • compute M(W) = M(c)⊗M(a)⊗M(a)⊗M(g) once • use it twice! vn=M(W)⊗M(t)⊗M(W)⊗M(t)⊗M(a)⊗M(c) ⊗v0 6 steps

  11. Exploiting repetitions ℓ - length of repetition W λ – number of times W repeats in string computing M(W) costs (ℓ -1)k3 each time W appears we save (ℓ -1)k2 W is good if λ(ℓ -1)k2 > (ℓ -1)k3 number of repeats = λ > k = number of states matrix-matrix multiplication > matrix-vector multiplication

  12. Offline General Scheme • dictionary selection: choose the set D={Wi } of good substrings • encoding: compute M(Wi ) for every Wi in D • parsing: partition the input X into good substringsX’ = Wi1Wi2 … Win’ • propagation: run Viterbi’s Algorithm on X’ using M(Wi)

  13. Outline • Overview • Exploiting repetitions • Using Four-Russions speedup • Using LZ78 • Using Run-Length Encoding • Training • Summary of results

  14. Using the Four-Russians Method Cost • dictionary selection:D = all strings over Σ of length < l • encoding: incremental constructionM(Wσ)= M(W) ⊗M(σ) • parsing:X’ = split X to words of lengthl • propagation: run VA on X’ using M(Wi ) • Speedup: k2n O(2|Σ|lk3 + k2n/ l) • O(1) • O(2|Σ|lk3) • O(n) • O(k2n/ l) = Θ(log n)

  15. Outline • Overview • Exploiting repetitions • Using Four-Russions speedup • Using LZ78 • Using Run-Length Encoding • Training • Summary of results

  16. Lempel Ziv 78 • The next LZ-word is the longest LZ-word previously seen plus one character • Use a trie • Number of LZ-words is asymptotically < n ∕ log n g a c aacgacg g

  17. Using LZ78 Cost • dictionary selection:D = all LZ-words in X • encoding: use incremental nature of LZM(Wσ)= M(W) ⊗M(σ) • parsing:X’ = LZ parse of X • propagation: run VA on X’ using M(Wi ) • Speedup: k2n log n k3n ∕ log n k • O(n) • O(k3n ∕ log n) • O(n) • O(k2n∕ log n)

  18. Improvement a g c g • Remember speedup condition: λ > k • Use just LZ-words that appear more than k times • These words are represented by trie nodes with more than k descendants • Now must parse X (step III) differently • Ensures graceful degradation with increasing k:Speedup: min(1,log n∕ k)

  19. Experimental Results – CpG Islands ~x5 faster: • Short - 1.5Mbp chromosome 4 of S. Cerevisiae (yeast) • Long - 22Mbp human Y-chromosome

  20. Outline • Overview • Exploiting repetitions • Using Four-Russions speedup • Using LZ78 • Using Run-Length Encoding • Training • Summary of results

  21. Offline Run Length Encoding aaaccggggg → a3c2g5 || aaaccggggg → a2a1c2g4g1

  22. Path traceback • In VA, easy to do in O(n) time by keeping track of maximizing states during computation • The problem: we only get the states on the boundaries of good substrings of X • Solution: keep track of maximizing states when computing the matrices M(W)=M(W1) ⊗ M(W2). Takes O(n) time and O(n’k2) space

  23. Outline • Overview • Exploiting repetitions • Using Four-Russions speedup • Using LZ78 • Using Run-Length Encoding • Training • Summary of results

  24. Training • Estimate model θ = {Pi←j, ei(σ)}given X. • find θ that maximize P(X | θ). • Use Expectation Maximization: • Decoding using current θ • Use decoding result to update θ

  25. VA Training • Aij= #of times state i follows state j in the most likely sequence of states. • Ei(σ) = #of times the letter σis emitted by the state i in the most likely sequence. • Each iteration costs O( VA + n + k2) path traceback + update Pi←j , ei(σ) Decoding (bottleneck) speedup!

  26. The Forward-Backward Algorithm • The forward algorithm calculates ft[i] the probability to observe the sequence x1, x2, …, xt requiring that the t’th state is i. • The backward algorithm calculates bt[i] the probability to observe the sequence xt+1, xt+2, …, xngiven that the t’th state is i. ft=M(xt) ●M(xt-1) ● … ●M(x1) ●f0 bt= bn ●M(xn) ●M(xn-1) ● … ●M(xt+2) ● M(xt+1)

  27. Baum Welch Training (in a nutshell) Σ t • Aij= ft [j]●Pi←j ● ei(xt+1)●bt+1[i] • each iteration costs: O( FB + nk2) • If substring W has length l and repeats λ times satisfies:then can speed up the entire process by precalculation path traceback + update Pi←j , ei(σ) Decoding O(nk2)

  28. Outline • Overview • Exploiting repetitions • Using Four-Russions speedup • Using LZ78 • Using Run-Length Encoding • Training • Summary of results

  29. Summary of results • General framework • Four-Russians log(n) • LZ78 log(n) ∕ k • RLE r ∕ log(r) • Byte-Pair Encoding r • SLP, LZ77 r/k • Path reconstruction O(n) • Forward-Backward same speedups • Viterbi training same speedups • Baum-Welch training speedup, many details • Parallelization

  30. Thank you!

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