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PRESS F5 TO START. This presentation contains Intermediate 2 past paper questions complete with solutions for the year 2003. The questions are sorted into topics based on the specific outcomes for the Intermediate 2 course.

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Main Grid

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  1. PRESS F5 TO START This presentation contains Intermediate 2 past paper questions complete with solutions for the year 2003. The questions are sorted into topics based on the specific outcomes for the Intermediate 2 course. To access a particular question from the main grid click on the question number. To get the solution for a question press the space bar. To access the formula sheet press the button To begin click on Main Grid button. F Main Grid

  2. Formulae List START Page

  3. This is the formula that we use

  4. 2003 Paper 1 Main Grid Solution

  5. Main Grid Solution

  6. 2 (a) (b) Main Grid

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  10. a = 3 (amplitude 3x ‘normal’ height) b = 2 ( period = 360 ÷ 2 = 180 Main Grid Solution

  11. Cancelling by (x + 1) Main Grid Solution

  12. 6cm 8cm Main Grid Solution

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  14. 8 (a) 7 + 6x – x2 factorises to (7 – x)(1 + x) (b) Roots are; x = 7 and x = -1 (c Turning Point halfway between –1 and 7. i.e. x = 3 So y = 7 + (6 x 3) – (32) = 7 + 18 – 9 = 16 Coords of Max T.P. (3,16) Main Grid

  15. Main Grid Solution

  16. OLN = 90° (tangent) PLJ = 90° – 47° = 43° PKL = 90° (angle in a semi circle) PLK = 180° – (90° + 31°) = 59° KLJ = PLK + PLJ = 43° + 59° = 102° Main Grid

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  20. x + y = 130 eq 1 x 50 • 30x + 50y = 6000 eq 2 • 50x + 50y = 6500 • 30x + 50y = 6000 • Subtract 20x = 500 • x = 25 • Sub into eq 1 25 + y = 130 • y = 105 • 25 tickets at £30 • 105 tickets at £50 Main Grid

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  23. Yes. Mean temperature of 19°C is within range of 15°C to 25°C • Standard deviation of 3.65 °C is less than 5 °C so less variation should mean good growth. Main Grid

  24. (4) (3) Main Grid Solution

  25. 6(a) Total area of cross section = area of rectangle + area of circle =(30 x 46) + (3.14 x 15²) =2086.5 cm² Volume of prism = Ah = area of cross section x height = 2086.5 x 25 = 52162.5 cm³ = 52 000 cm³ (2 sig figs) (b) So volume of quarter of a cylinder. Vol = ¼πr2h 30 000 = ¼ x 3.14 x r2 x 20 r2 = 30 000 x 4 3.14 x 20 r = √1910.8 = 43.7cm Main Grid

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  31. 10 (a) (b) Main Grid

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  33. √ (a) S A T C (b) = 1 √ Main Grid Solution

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