This presentation is the property of its rightful owner.
Sponsored Links
1 / 85

第 5 章 数字光纤通信系统 5.1 两种传输体制 5.2 系统的性能指标  5.3 系统的设计 PowerPoint PPT Presentation


  • 33 Views
  • Uploaded on
  • Presentation posted in: General

第 5 章 数字光纤通信系统 5.1 两种传输体制 5.2 系统的性能指标  5.3 系统的设计. 第 5 章 数字光纤通信系统. 5.1 两种传输体制 光纤大容量数字传输目前都采用同步时分复用 (TDM) 技术, 复用又分为若干等级,因而先后有两种传输体制:准同步数字系列 (PDH) 和同步数字系列 (SDH) 。 PDH 早在 1976 年就实现了标准化,目前还大量使用。随着光纤通信技术和网络的发展, PDH 遇到了许多困难。

Download Presentation

第 5 章 数字光纤通信系统 5.1 两种传输体制 5.2 系统的性能指标  5.3 系统的设计

An Image/Link below is provided (as is) to download presentation

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.


- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -

Presentation Transcript


5 5 1 5 2 5 3

5

5.1

5.2

5.3


5 5 1 5 2 5 3

5

5.1

(TDM) (PDH)(SDH) PDH1976PDH

(SONET)1988ITUT(CCITT)SONET(SDH)


5 5 1 5 2 5 3

SDHPDH


5 5 1 5 2 5 3

5.1.1PDH

1.544 Mb/s()2.048 Mb/s() 5.1PDH2.048 Mb/s44 1.544 Mb/s3


5 5 1 5 2 5 3

PDH141976 PDH PDH (1)


5 5 1 5 2 5 3

(2)

(3) /


5 5 1 5 2 5 3

5.1.2SDH

1. SDH

SDH5.1SDHSDH(SDHTM)ADMDXC()SDH/E1STM1SDHADMDXC


5 5 1 5 2 5 3

5.1 SDH


5 5 1 5 2 5 3

TMADMDXC5.2(a)#, (b)#, (c)DXCSDH5.3(a)5.3(b)(Path)(Line)(Section)

PDH SDH

(1) SDH STM1155.520 Mb/s 4STM1 STM44155.52 Mb/s=622.080 Mb/s 16STM1 STM16, 2488.320 Mb/s


5 5 1 5 2 5 3

5.2SDH

(a) TM (b) ADM(Add/Drop Multiplexer); (c) DXC


5 5 1 5 2 5 3

5.3

(a) (b)


5 5 1 5 2 5 3

(2) SDH A (3) SDH ()

(4)


5 5 1 5 2 5 3

5.4 PDHSDHPDH 140 Mb/s2 Mb/s140/34 Mb/s, 34/8 Mb/s8/2 Mb/s SDH(ADM) 2 Mb/s

(5) DXCSDHDXC


5 5 1 5 2 5 3

5.4


5 5 1 5 2 5 3

2. SDH

SDH 5.5 SDHSTMN9270N 9270N 8 bit 125 s 8000STM1 927088000=155.520 Mb/s

SDH

(1) (SOH) SDH(64 kb/s)


5 5 1 5 2 5 3

5.5 SDH


5 5 1 5 2 5 3

STM1 SOH98(4)=72 Byte576 bit8000 SOH5768000=4.608 Mb/s

5.3(a)(SOH)(LOH)359

(2) (Payload)SDHSTM1Payload9261=2349 Byte, 234988000=150.336 Mb/s

Payload (POH)


5 5 1 5 2 5 3

(3) (AU PTR) Payload()STM1 AU PTR9(4) 988000=0.576 Mb/s

SDH(VC)

3.


5 5 1 5 2 5 3

PDHSDHSDH

5.6 STM1

ITUTSDH


5 5 1 5 2 5 3

5.6 SDH


5 5 1 5 2 5 3

PDHSDH5.7SDHCn PDH C11#, C12#, C2#, C3C41.5 Mb/s#, 2Mb/s#, 6 Mb/s#, 34 Mb/s#, 45 Mb/s140Mb/s (POH)VCVCVC


5 5 1 5 2 5 3

5.7 SDH


5 5 1 5 2 5 3

VC (AU PTR) (AU)(TU)AUVC(VC4)AU TUVCTUTU (TUG)AU3AU43AU31AU4(AUG)SOHSTM1 NSTM1 STMN


5 5 1 5 2 5 3

PDH4SDHSTM1 139.264 Mb/sC4149.760 Mb/s; VC4POH(9 Byte, 0.576 Mb/s)150.336 Mb/sAU4 AU PTR(9 Byte, 0.576 Mb/s)150.912 Mb/s; 1AUGSOH(72 Byte, 4.608 Mb/s), 155.520 Mb/s, STM1


5 5 1 5 2 5 3

4.

(DXC)5.2 SDHDXC(PDH)()m()

DXCX/YDXCXY


5 5 1 5 2 5 3

064 kb/s1234 PDH1 4 4 SDH STM1 5 6 SDHSTM4 STM

DXC 1/0 (E1: 2.048 Mb/s), 64 kb/s; DXC 4/1 155.52 Mb/s(SDH)140 Mb/s(PDH)2.048 Mb/sDXC 1/0DXC 4/1DXC 4/4


5 5 1 5 2 5 3

(1) DXC

(2)

DXC ()()PDHSDHPDHSDH


5 5 1 5 2 5 3

5. SDH

SDH(5.8) (5.9)(5.10)

SDH SDH

SDHADMDXC( 5.1 )SDHDXC


5 5 1 5 2 5 3

5.8 SDH


5 5 1 5 2 5 3

5.9 SDH


5 5 1 5 2 5 3

5.10 SDH()


5 5 1 5 2 5 3

5.2

5.2.1

ITUT(CCITT)(HRX)5.11 HRX(ISDN)64 kb/s

5.11 HRX27 500 km, (HRDL)HRX HRDL


5 5 1 5 2 5 3

5.11 HRX


5 5 1 5 2 5 3

HRDL2500 km, HRDL5000 km6400 km 2500 kmHRDL(HRDS)(5-12)HRDS280 km, HRDS50 km HRDS420 km()280 km()


5 5 1 5 2 5 3

5.12 HRDS


5 5 1 5 2 5 3

5.2.2

1. (BER)

BERPCM 5.2

5.13 TL


5 5 1 5 2 5 3

5.13


5 5 1 5 2 5 3

10 sBER110-3 10 sBER110-3 64 kb/s BER=110-364T0BERthBERBERth

PCM 64 kb/sHRX 5.3


5 5 1 5 2 5 3

(DM) 110-6BERth35 min, T0 1 min

TL1 110-6(DM)HRX()10%(SES)


5 5 1 5 2 5 3

TL1T01 s 110-3(SES)HRX0.2%

(ES) TL1T01s BERth=0(1 bit)(ES)HRX8%(EFS) 92%

5.3HRX(27 500 km)


5 5 1 5 2 5 3

5.14HRX 5.4 HRX

5.51 24 h CCITT25 000 kmBERav110-7BERav=410-12/km280 km420 kmBERav1.1210-91.6810-9 110-9


5 5 1 5 2 5 3

5.14 HRX


5 5 1 5 2 5 3

420 km 110-9420 km 1 420 kmBERav=110-1050 kmBERav=110-11

2.

(JPP)(F) 5.15


5 5 1 5 2 5 3

5.15


5 5 1 5 2 5 3

02 kHzUINRZ1UI1bit fb

5.65.7 5.6 5.7 5.16


5 5 1 5 2 5 3

5.16 5.65.7


5 5 1 5 2 5 3

5.2.3

1.


5 5 1 5 2 5 3

(1) R R

R=exp(- t) (5.1)

t()10-9/h, (fit), 1 fit109 h

n Rs

Rs=R1R2Rn=exp(-s t) (5.2)


5 5 1 5 2 5 3

, Riii

(2) MTBF

(3) APFA


5 5 1 5 2 5 3

MTTR()

PF

(5.4)(5.5)

PF=(1-A)100% (5.6)

PF= (5.7)

mnP=MTTR/MTBF


5 5 1 5 2 5 3

2.

5000 km4420 km280 km3151100 km, 450 km1LD10104 h, PINFET50104 h, APD50104 h

5000 km5.8MTTR=6 h5.9


5 5 1 5 2 5 3

5.3

()


5 5 1 5 2 5 3

() ()() 100% ()


5 5 1 5 2 5 3

5.3.1

5.17

T, T:

Tx:

Rx:

C1, C2:

S: TxC1

R: RxC2

SR:


5 5 1 5 2 5 3

5.17

(a) (b)


5 5 1 5 2 5 3

SR

L(f+s+m)Pt-Pr-2c-Me

L

Pt (dBm)Pr(dBm)c (dB/) Me (dB)f(dB/km), skm(dB/km), mkm(dB/km), L (km)


5 5 1 5 2 5 3

(5.8)PtLD-3-9dBm, LED-20-25 dBmPr 5.10BERav110-10Pr

0.31 dB/Me Me3 dB


5 5 1 5 2 5 3

f1310 nm, f0.40.45 dB/km; 1550 nm, f0.220.25 dB/kmm0.10.2 dB/km, 5 dB 0.05 dB/s

ITUT(CCITT)G.955LD(G.652)SR5.11


5 5 1 5 2 5 3

5.3.2()

() ()


5 5 1 5 2 5 3

fb=1/T(RZ) 5.18

g(t)=exp (5.9)

(rms)/T=arms5.18(5.9)5.18

(5.10)a 5.12


5 5 1 5 2 5 3

5.18


5 5 1 5 2 5 3

BellS.D.Personick

a=0.250.034% a=0.513.5%78dBa=0.250.352 dB

() (FWHM)


5 5 1 5 2 5 3

, =/0.4247, =aT, armsT=1/fbfbf(FWHM)

3dB(2.47b)f=0.44/B, BLB=B1/LB11 km=0.51, (5.11)a=0.250.35Bfb

B=(0.830.56)fb (5.12)


5 5 1 5 2 5 3

L1kmB1B1=BL,

L=1.211.781/fb1/ (5.13)

Lfb=(1.211.78)B1 (5.14)

fbB1L5.19, /T=0.3 =0.75Lfb1 km()


5 5 1 5 2 5 3

5.19 1kmB1L


5 5 1 5 2 5 3

f=2.355f, frms(2.55b)f=|C0|L, C0=C(0)0(ps/(nmkm))(nm)L(km)(5.11)a=/T=0.25

L=

CCITTL


5 5 1 5 2 5 3

, Fb(Mb/s)C0(ps/(nmkm))(nm)(MLMLD)rms(SLMLD), 20 dB MLMLD, =0.115, SLMLD=0.306


5 5 1 5 2 5 3

G.65212851330 nmC3.5 ps/(nmkm))12701340 nm, C6 ps/(nmkm)SRCL(ps/nm)5.11140 Mb/s


5 5 1 5 2 5 3

5.3.3

(5.8)(5.13)()(5.15)(5.16)()

140 Mb/sPt=-3 dBm, Pr=-42 dBmMe=3 dBc=0.3dB/f=0.35 dB/km, m=0.1 dB/kmkms=0.03 dB/km(5.8)


5 5 1 5 2 5 3

5B6B, b=140(6/5)=168 Mb/s, |C0|=3.0 ps/(nmkm)=2.5 nm(5.16)

74 km

|C0|=3.5 ps/(nmkm)=3 nm(5.16)L65 km 65 km


5 5 1 5 2 5 3

5.20

5.200.85 m20 kmSIFGIF0.1 Gb/s 100200 km1.31m1 Gb/s 1.55 m5 Gb/s 2 Gb/s20 Gb/s


5 5 1 5 2 5 3

5.20


5 5 1 5 2 5 3

(fbL)

0.85m,SIFfbL0.011=0.01 (Gb/s)km

0.85m, GIFfbL0.120=2.0 (Gb/s)km

1.31 m, SMFfbL1125=125 (Gb/s)km

1.55m, SMFfbL275=150 (Gb/s)km

1.55m, DSFfbL2080=1600 (Gb/s)km


  • Login