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For any function f ( x,y ), the first partial derivatives are represented by  f  f

For any function f ( x,y ), the first partial derivatives are represented by  f  f — = f x and — = f y  x  y. For example, if f ( x,y ) = log( x sin y ), the first partial derivatives are  f  f — = f x = and — = f y =  x  y. 1 — x. cos y

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For any function f ( x,y ), the first partial derivatives are represented by  f  f

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  1. For any function f(x,y), the first partial derivatives are represented by ff — = fxand — = fy xy For example, if f(x,y) = log(x sin y), the first partial derivatives are ff — = fx = and — = fy = xy 1 — x cos y —— = cot y sin y If a function f from Rn to R1 has continuous partial derivatives, we say that f belongs to class C1. We can see that f(x,y) = log(x sin y) belongs to class C1 when its domain is defined so that x sin y > 0. If each of the partial derivatives of f belongs to class C1, then we say that f belongs to class C2.

  2. f 1 f f(x,y) = log(x sin y), — = fx = —and — = fy = cot y xxy We can calculate higher order (and mixed) partial derivatives:  f — ( — ) = — ( fx) = ( fx)x = fxx = x xx 1 – — x2  f — ( — ) = — ( fy) = ( fy)y = fyy = y yy 1 – —— = – csc2y sin2y  f — ( — ) = — ( fx) = ( fx)y = fxy = y xy 0  f — ( — ) = — ( fy) = ( fy)x = fyx = x yx 0

  3. Let f(x,y) = sin(xy) fx = fy = fxx = fyy = fxy = fyx = y cos(xy) x cos(xy) – y2 sin(xy) – x2 sin(xy) cos(xy) – xy sin(xy) cos(xy) – xy sin(xy)

  4. f(x+x , y) – f(x , y) ————————— x (x0 , y0+y) (x0+x , y0+y) fx(x , y)  f(x , y+y) – f(x , y) ————————— y fy(x , y)  Consider fxy(x0 , y0)  (x0+x , y0) (x0 , y0) fx(x0 , y0+y) – fx(x0 , y0) —————————— y f(x0+x , y0) – f(x0 , y0) Substitute ————————— in place of fx(x0 , y0) , and x f(x0+x , y0+y) – f(x0 , y0+y) substitute ————————————— in place of fx(x0 , y0+y) . x

  5. Now consider fy(x0+x , y0) – fy(x0 , y0) fyx(x0 , y0)  —————————— x f(x0 , y0+y) – f(x0 , y0) Substitute ————————— in place of fy(x0 , y0) , and y f(x0+x , y0+y) – f(x0+x, y0) substitute ————————————— in place of fy(x0+x , y0) . y Note that the results are the same in both cases suggesting that fxy = fyx . Look at Theorem 1 on page 183 (and note how this result can be extended to partial derivatives of any order).

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