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# DESIGN OF EXPERIMENTS - PowerPoint PPT Presentation

DESIGN OF EXPERIMENTS. M. Piczak November 2005. THE ANALYST’S PURPOSES. UNDERSTANDING (a command of general cause and effect relationships associated with a particular phenomenon) EXPLANATION (application of selected relationships to a particular observation)

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### DESIGN OF EXPERIMENTS

M. Piczak

November 2005

• UNDERSTANDING (a command of general cause and effect relationships associated with a particular phenomenon)

• EXPLANATION (application of selected relationships to a particular observation)

• PREDICTION (extending knowledge of relationships to a future event)

• CONTROL (intervening with the intent of either stimulating or preventing a particular event)

• GYPSIES

• BOOKIES

• TAROT CARDS

• FARMER’S ALMANAC

• HOROSCOPE

• EQUATIONS

• To establish a causal link between selected independent variables X’s and particular dependent Y variables

• To isolate or disentangle the independent effect being exerted on a response variable

• Ho: That there exists no relationship between the X and Y variable (assumes that the value of the coefficient for Xi = 0)

• Ha: That there exists a relationship between the X and Y variable

The challenge is to disprove Ho and thus, accept Ha

• REGRESSION METHODS

• TAGUCHI METHODS

• SHAININ METHODS

• 6 SIGMA METHODS

• CLASSIC DESIGN OF EXPERIMENTS

• Start with a uniformity, regularity or anomaly worthy of examination (See ‘What is Worth Studying’)

• Establish the research questions

• Undertake a literature review to identify other key explanatory variables (See ‘Weird Predictors’)

• Explicate the relevant theory for each X variable as it relates to Y, a priori

• Establish the measures for X and Y

• Choose an experimental design using Minitab

• Execute the experiment

• Gather the data

• Analyze the data

• Draw conclusions

• Repeat as necessary to cumulate knowledge

F = M * A

Where:

F = Force

M = Mass

A = Acceleration

F = M * A

F = M * A

F = M * A

CODED DATA

Thus, the actual model:

or Ma = 7.5 + 2.5Mc

Therefore

or Aa = 150 + 50 Ac

Therefore

• http://www.statease.com/pubs/popcorn.pdf

• http://thequalityportal.com/q_know02.htm

• http://www.hq.nasa.gov/office/hqlibrary/ppm/ppm35.htm

• http://www.isixsigma.com/tt/doe/

M. Piczak

November 2005

THE END