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Computational Protein Design: A problem in combinatorial optimization

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Computational Protein Design:A problem in combinatorial optimization

CSE 549 Guest Lecture

September 17, 2009

David Green

Applied Mathematics & Statistics

- Polymers (chains) of amino acids.
- There are 20 different amino acids that can be part of the chain.

- Machines of the cell.
- It’s proteins that do most of the work involved in life!

- Amino acids link to form polypeptides.
- There is a backbone of constant composition.
- There are side chains that vary.

- AA side chains vary from:
- Big to small.
- Non-polar (all C and H) to polar.
- Positive to negative.
- Flexible to rigid.

- Protein sensors (receptors) are responsible for all the senses (sight, smell, taste, touch, hearing).
- Enzymes are proteins the catalyze chemical reactions, like the ones that convert food to energy.
- Specialized structural proteins make skin elastic, and make the lens of the eye work.
- Muscles are primarily composed of proteins that combine structural and enzymatic parts to make a machine.

- New sensors based on biology.
- Proteins have been engineered to detect TNT (explosive) and sarin (nerve gas).

- Proteins are used as treatments for many diseases.
- Protein engineering has helped improve proteins that are given to cancer patients on radiation or chemo-therapy.
- Work in the Green lab is on-going to design proteins for use as anti-HIV prophylatics.

- Many nanotechnology applications that haven’t even been considered yet!

- The genome contains instructions for every protein in a cell.
- A few HUGE molecules of DNA.

- Each gene is the code for one protein.
- There are ~30,000 genes in humans.

- Genes are expressed through an intermediate molecule, RNA.
- Many copies of each protein can be made.

- Then proteins do the work!

- Proteins fold into a unique 3-dimensional structure.
- The amino acid sequence of a protein dictates it’s structure.
- The function of a protein is controlled by it’s structure.

- Polyethylene
- Is made of long chains of the same monomers.
- Adopts a random mesh of inter-weaving strands.
- This structure gives us PLASTIC!

- The “double-helix” is a great structure for storing and replication information.

- One chain or many.
- Elongated or globular.
- Many forms of symmetry (or none).

- Cyanovirin – A protein that inhibits the entry of HIV into human cell.

- The atoms of a protein form a compact, well-packed cluster.

- A protein can be thought of as a nearly solid object.

- Simplified cartoons make the structure easier to see.

- The path of the backbone of a protein is called it’s “fold”.

- Different types of amino acids are found all along the protein chain.

- Each amino acid has a side chain that protrudes from the backbone.

- Many proteins bind other molecules, like the sugar molecules here.

- Binding interfaces are usually a close fit of two complementary surfaces.

- The core of a protein is key in keeping a stable structure.

- A protein is a complicated three-dimensional structure, made up by an amazing 3-D jigsaw puzzle of interlocking amino acids.
- Amino acids pack together not just geometrically, but with complementary chemical groups as well.
- Proteins move too, but we’ll ignore that for now.

- Choose a fold (path of the backbone).
- Pack the core with the right set of amino acids to achieve the desired fold.
- Choose other amino acids to achieve the desired function (such as binding to a target molecule, or getting the right molecular motions).

- Given a protein sequence, what is the structure that it will adopt (fold to)?
- This is a VERY hard problem, and it not yet fully solved.
- Prediction is difficult because you are stuck with what nature gives you.

- Given a desired 3-dimensional protein structure, what is a sequence that will fold to that structure?
- We have the freedom to add constraints that simplify the problem.
- As a result, methods for protein design have had many successes.

- Pabo. Nature301: 200 (1981).
- Drexler. PNAS 78: 5275-5278 (1981).

- ANY sequence which folds to the correct target structure (and carries out the desired function) can be considered a successful design
- There is more than one right answer, unlike in prediction!

- The structure dictates the function, and a big part of structure is the fold.
- We still don’t really know how to choose the “best” fold.
- Instead, we just borrow from nature – redesign a natural protein to do something new.

- The protein will not fold if zinc is not present.
- The protein only binds DNA when it is folded.
- A group at Caltech set out to design a zinc finger that doesn’t need zinc!

- Dahiyat and Mayo. Science287: 82-87 (1997).

- Making a molecule bind is like designing a the core – we want to make the interface between the two pieces complementary.
- Other functions are a lot trickier … and we don’t have good ways to solve them yet, but we’re on our way.

- Looger, Dwyer, Smith and Hellinga. Nature423: 185-190 (2003).

- The zinc finger is one of the smallest protein domains … about 30 amino acids long.
- How many different 30 amino acid polypeptides are there?
- Choose from any of 20 amino acids at each position.
- Total sequences = 2030 = 1x1039
- Mass of earth = 6x1027 g
- Mass of a grain of sand ~ 1x10-3 g
- A billion earths’ worth of sand grains

- Enumeration of possible states is beyond impossible — must take advantage of need to achieve complementary interactions between amino acids.

- An arginine and a glutamate interact.

- An arginine and a glutamate interact.

- An arginine and a glutamate interact.

- An arginine and a glutamate interact in several different conformations.

- Amino-acid side chains are flexible.
- But not every shape (conformation) is equal.
- Each amino acid has a set of preferred conformations (rotamers).
- 1 to 80 per amino acid.

- Instead of choosing from 20 amino acids … we need to choose from ~400 (at least) amino acid rotamers!
- Total structures = 40030 = 1x1078
- (approx. number of atoms in the universe!!!!!)

- Total structures = 40030 = 1x1078

- How do you solve a jigsaw puzzle?
- Impossible to try all combinations of piece placement
- Unique ways of placing N pieces on a grid is (4N)(N!)
- For N=100, (1.6x1060)(9.3x10157)= 1.5x10218

- Unique ways of placing N pieces on a grid is (4N)(N!)
- Trying each piece one by one is better, but still infeasible
- Number of iterative tries for a N piece puzzle is:
- For N=100, 1.37x106

- Number of iterative tries for a N piece puzzle is:

- How do you solve a jigsaw puzzle?
- Group pieces by colors and patterns.
- Iterate over matching of pieces that are complementary
- Shape is important.
- The pattern must also match.

- What does it mean for two amino acids in the core of a protein to “match”?
- Must fit close together (but not too close) Steric complementarity.
- Neighboring atoms must have complementary charges (neutral likes neutral, positive likes negative) Electrostatic complementarity.

- Van der Waals attraction between atoms at moderate distances.
- Repulsion of atoms from one another at short distances.
- If atoms are not nearby, the energy between them will be very close to zero.

- The total score of the “goodness” of fit in a molecule is the sum of the energy for every pair of atoms.

- Atoms in molecules can be thought of as having tiny charges on them, even if the total charge on a molecule is zero.
- Coulomb’s Law describes the energy of how two charges interact.
- The overall electrostatic fit is calculated by adding up the energy of all pairs of atoms.
- Like charges give a positive value.
- Opposite charges give a negative.
- Neutral (zero charge) groups don’t matter.

- Van der Waals + Coulomb’s Law, for every pair of atoms, and all added up.
- Negative energies are favorable, positive energies unfavorable.
- Nature works to MINIMIZE energy.

Position 1

Position 2

Position 3

Conformational states of system

- Molecular Mechanics energy
- Van der Waals
- Coulombic
- Bond, angle, dihedral

i , j are positions in sequence

Riis rotamer choice at position i

The Dead-end Elimination Theorem

Given two rotamer choices X, and Y at position I, if the best energy of X (with any choice of rotamers at other positions) is worse than the worst energy of Y, then X can not be part of the global energy minimum.

Need to make the comparison,

but the min and max functions require evaluating all states.

* Ri is used to replace Xi in the first equation.

Last sum is invariant with respect to our choice at position i, and thus:

But note that:

This gives a sufficient condition for the DEE theorem to hold:

min and max are evaluated over rotamers at a single position, so entirely feasible!

Original problem statement was to compare the best structure with Xi at position I to the worst with Yi; it is a easier to satisfy, but still sufficient, criterion to find the single set of choices at all other positions with the minimum difference between choice Xi and Yi.

Again, we use the same trick to bound the minimum in a feasible manner:

This gives a alternate sufficient condition for the DEE theorem to hold:

This is a tighter bound on the “true” desired comparison, since:

As rotamers are flagged as incompatible with the global minimum solution, the min/max functions are evaluated over a smaller and smaller set of choices, and so additional iterations of the comparison can eliminate more possibilities.

Thus, the algorithm can be outlined as:

While (any rotamers eliminated ) {

For each position in the sequence (i){

For each rotamer choice (X) at position i {

For each rotamer choice (Y ne X) at position i {

If DEE criterion is satisfied {

Eliminate choice X at position I

}

}

}

}

}

The order of each cycle is ~N*R2, where N is the number of positions, and R is the number of choices at each position. However, as R decreases with iteration, each subsequent cycle costs less.

Position 1

Position 2

Position 3

Conformational states of system

Position 1

Position 2

Position 3

Conformational states of system

Example of a 5-position design, with 306 choices per position, done in a simple MATLAB script:

Iteration 0: 306 306 306 306 306

Iteration 0: Structures = 2.682916e+12

Iteration 1: 143 198 145 42 33

Iteration 1: Structures = 5.690265e+09 from 2.682916e+12

Iteration 1: Elapsed time is 96.461053 seconds.

Iteration 2: 52 83 55 11 8

Iteration 2: Structures = 20889440 from 5.690265e+09

Iteration 2: Elapsed time is 11.604577 seconds.

Iteration 3: 4 12 36 6 5

Iteration 3: Structures = 51840 from 20889440

Iteration 3: Elapsed time is 0.625266 seconds.

Iteration 4: 4 12 35 6 5

Iteration 4: Structures = 50400 from 51840

Iteration 4: Elapsed time is 0.148598 seconds.

Iteration 5: 4 12 35 6 5

Iteration 5: Structures = 50400 from 50400

Iteration 5: Elapsed time is 0.045631 seconds.

Dead-end elimination is not guaranteed not to eliminate any choices … in this case computational expense is used at zero gain. However, experience suggests that in the case of protein design, the algorithm is highly efficient.

For large design problems, even a highly efficient pruning can leave a tree which is too large to be searched by enumeration (such as depth-first search); for example, consider an original space of 10100 states, reduced to 1020.

An efficient bounding heuristic can be defined using similar tricks as discussed here; this can be used in the A* algorithm to find the global minimum within the remaining space.

The DEE criterion can be extended to pairs, triples, and n-tuples of positions. Most applications use only singles and pairs.

How to choose a path through a tree, which the goal of reaching the global minimum state?

First, define an energy to be associated with each step through the tree:

This is the energy of placing rotamer choice R at position i, given that all positions in the tree above i have been selected.

Note this is similar, but not identical, to the definition used with DEE.

At the leaf node, the state energy is then the sum of all individual path energies:

Thus, we wish to find the path with the lowest total.

Challenge is that we do not know the total until we have traversed the tree to a leaf!

Assume we have some heuristic, that estimates the best possible energy that we can achieve down some path. For choice R at position I, we will call this

When choosing a path to take at a given node, we know the path we have already taken, and thus the true cost. We thus combine this information with the heuristic in deciding what step to take:

At a leaf node, the heuristic is 0, and this gives the total energy.

However, if we only use the heuristic, how do we know we get the correct solution?

1. Allow backtracking.

At every step, not only choose between the possible paths from the current node, but also the paths from all nodes which have been visited in the past.

In this way, if the heuristic turned out to be poor for a given path (and the true energy became large), a new path is chosen.

2. Use a heuristic that bounds the true solution.

Consider a heuristic that is guaranteed to be lower than the true best energy down a path (an optimistic prediction of the best energy). When a leaf is reached, a comparison between the true energy of that leaf and the heuristic energy of the un-followed choice can be made. Since the heuristic is an optimistic guess, if the true energy is lower than the heuristic for all other choices, it must be the global minimum.

Thus, it is possible to have a guarantee that the solution found is the true global minimum!

Recall our energy definitions:

The optimal heuristic is:

Now, we bound the second term:

Initialize a list of traveled nodes with the root.

While (no mininum leaf in list) {

Select minimum f* of all paths from nodes in list.

Add this new node to list.

If (new node is leaf) {

Compare leaf energy to minimum f* from list.

If (Leaf energy < min(f*)) {

Leaf is global minimum.

}

}

Our final heuristic is:

The second term involves a minimum over each choice at following position, which is order (N-i)*R, with an inner minimum over the same, order (N-j)*R. Thus, the cost is less than (N-j)2*R2.

Performance of A* is not guaranteed — in the worst case, the entire tree must be enumerated to find the solution. Again, however, experience suggests that the algorithm is highly efficient for protein design.

In many cases, we wish not only to have the global minimum, but all solutions within a cutoff of the minimum.

A* can be adapted to solve this problem as well, but care must be taken in the first step of pruning with DEE — the elimination criterion must be modified to prevent elimination of low, but not minimum, energy states.

- Protein design as an inverse problem:

- Examples of successful protein design:

- Development of the Dead-End Elimination algorithm:

- Formulation of A* for protein design: