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Entry Task: Nov 2 nd Friday. Question: What is the rms speed of NO 2 at 45°C? You have 5 minutes!!. Agenda:. Discuss Graham’s Law ws Graham’s Law Lab HW: Pre-Lab Molar Mass of a volatile Liquid.

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Entry task nov 2 nd friday
Entry Task: Nov 2nd Friday

Question:

What is the rms speed of NO2at 45°C?

You have 5 minutes!!


Agenda
Agenda:

  • Discuss Graham’s Law ws

  • Graham’s Law Lab

  • HW: Pre-Lab Molar Mass of a volatile Liquid


10.61 Provide the following gases in order of increasing average molecular speed at 300K : CO2, N2O, HF, F2, H2. B) Calculate and compare the rms speeds of H2 and CO2 at 300K.

Convert g to kg

3*8.314 kg-m2/s2-mol-K * 300K

0.044 kg/mol

= 7482.6

0.044

= 412 or 4.12 x 102m/s of CO2


10.61 Provide the following gases in order of increasing average molecular speed at 300K : CO, N2O, HF, F2, H2. B) Calculate and compare the rms speeds of H2 and CO2 at 300K.

Convert g to kg

3*8.314 kg-m2/s2-mol-K * 300K

0.044 kg/mol

= 7482.6

0.044

= 412 or 4.12 x 102m/s of N2O


10.61 Provide the following gases in order of increasing average molecular speed at 300K : CO, N2O, HF, F2, H2. B) Calculate and compare the rms speeds of H2 and CO2 at 300K.

Convert g to kg

3*8.314 kg-m2/s2-mol-K * 300K

0.020 kg/mol

= 7482.6

0.020

= 612 or 6.12 x 102m/s of HF


10.61 Provide the following gases in order of increasing average molecular speed at 300K : CO, N2O, HF, F2, H2. B) Calculate and compare the rms speeds of H2 and CO2 at 300K.

Convert g to kg

3*8.314 kg-m2/s2-mol-K * 300K

0.0378 kg/mol

= 7482.6

0.0378

= 445 or 4.45 x 102m/s of F2


10.61 Provide the following gases in order of increasing average molecular speed at 300K : CO, N2O, HF, F2, H2. B) Calculate and compare the rms speeds of H2 and CO2 at 300K.

Convert g to kg

3*8.314 kg-m2/s2-mol-K * 300K

0.002 kg/mol

= 7482.6

0.002

= 1934 or 1.93 x 103 m/s of H2


10.61 Provide the following gases in order of increasing average molecular speed at 300K : CO, N2O, HF, F2, H2. B) Calculate and compare the rms speeds of H2 and CO2 at 300K.

= 1934 or 1.93 x 103 m/s of H2

= 412 or 4.12 x 102m/s of CO2

CO2 is WAY slow because its molecule is HUGE compared to hydrogen gas


Graham s law
Graham’s Law

A sample of hydrogen gas effuse through a porous container 9 times faster than an unknown gas. Estimate the molar mass of the unknown gas.

Set up problem so x is in the numerator on the right hand side of equation

Square both sides to get rid of the square root sign.


Graham s law1
Graham’s Law

If CO2has an effusion rate of 0.00601moles/sec. What would the effusion rate for Xe be in moles/sec?

Set up problem so x is in the numerator on the left hand side of equation

3.48 x 10 -3 mols/sec


Graham s law2
Graham’s Law

  • NH3 has an effusion rate of 0.00314mol/sec. Which of the gases (listed in 10. 61) below would have an effusion rate of 0.00245mol/sec?

Set up problem so x is in the numerator on the right hand side of equation

Square both sides to get rid of the square root sign.

28.0 molar mass


Graham s law3
Graham’s Law

In a given period of time, 0.214 moles of Ne effuses. How many moles of CO would effuse in to the same period of time?

Set up problem so x is in the numerator on the right hand side of equation

Square both sides to get rid of the square root sign.

0.182 moles of CO


Grahams lab
Grahams Lab

  • At a given temperature, the speed at which a gas molecule moves depends on its mass. This relationship, first discovered by Thomas Graham, is a result of the definition of kinetic energy. Graham studied two properties of gases that are related to the molecular speed: the rate of effusion (the escape of gas particles through a small hole) and diffusion (the spread of gas particles from an area of high concentration to low concentration).


Grahams lab1
Grahams Lab

  • His experiments showed that these properties were related to the molecular mass of the gas molecules. What type of relation did he find? How is it related to the formula for kinetic energy? In this lab we will find the answers.


1 what is the formula relating kinetic energy to particle velocity identify the variables
1. What is the formula relating kinetic energy to particle velocity? Identify the variables.

Convert g to kg

8.314kg-m2/s2-mol-K * Temp in K

molar mass


2 distinguish between effusion and diffusion which are we studying in this lab
2. Distinguish between effusion and diffusion. Which are we studying in this lab?

  • Effusion is the movement of gas through a tiny hole.

  • Diffusion is the movement of gas from a high concentration to a low concentration.

  • We are studying the rate of diffusion


3. How studying in this lab?does the average kinetic energy of different gases compare when they are at the same temperature?

  • All gases have the same average kinetic energy at the same temperature.


4 what are the molar masses of hcl and nh 3 use these values to complete calculations questions 4
4. What studying in this lab?are the molar masses of HCl and NH3? Use these values to complete Calculations/questions #4.

  • HCl has a molar mass of 36.45 g/mol

  • NH3 has a molar mass of 17.0 g/mol


This lab is dangerous
THIS LAB IS DANGEROUS!! studying in this lab?

Concentrated HCl

Concentrated NH4OH

DO NOT TOUCH OR breathe IT IN !!!


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