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Course 2. Solving Multiplication Equations. Objectives. Review vocabulary Review solving equations by adding or subtracting Solve multiplication equations using Algebra tiles and paper and pencil Solve practical problems. Review. Use the following to answer the questions:

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course 2

Course 2

Solving Multiplication Equations

objectives
Objectives
  • Review vocabulary
  • Review solving equations by adding or subtracting
  • Solve multiplication equations using Algebra tiles and paper and pencil
  • Solve practical problems
review
Review
  • Use the following to answer the questions:
      • 6x + 5 – 3y = 12
  • Is it an equation, expression or an inequality? How do you know?
  • Identify the term(s).
  • Identify the variable(s).
  • Identify the constant(s).
  • Identify the coefficient(s).

Equation, it has an equals sign

6x, 5, 3y and 12

x and y

5 and 12

6 and -3

review1
Review

Remember: Equations must be in balance, like a scale.

  • How would you solve this equation?
    • x – 4 = 12
  • Use the opposite operation to undo the subtraction.
    • x – 4 + 4 = 12 + 4
    • x = 16
division property of equality
Division Property of Equality
  • If you divide each side of an equation by the same nonzero number, the two sides remain equal.
let s try it
Let’s Try It!
  • 1) 2x = -8
  • What is the coefficient in this equation?
  • What is the opposite (inverse) of multiplying by 2?

2

Dividing by 2

slide8
2x = -8
  • Use the division property of equality:
    • Divide both sides of the equation by 2
      • 2x = -8
      • 2x = -8

2 2

  • x = -4
slide9
2x = -8
  • Check: 2x = -8
  • Replace the variable with the solution:
    • 2(-4) = -8
    • -8 = -8
2 5m 40
2) -5m = 40
  • What is the coefficient in this equation?
  • What is the opposite (inverse) of multiplying by -5?
  • Divide both sides of the equation by -5?
    • -5m = 40
    • -5m = 40

-5 -5

  • m = -8

-5

Dividing by -5

5m 40
-5m = 40
  • Check -5m = 40
  • Replace the variable with the solution:
  • -5(-8) = 40
  • 40 = 40
3 30 6n
3) 30 = 6n
  • What is the coefficient in this equation?
  • What is the opposite (inverse) of multiplying by 6?
  • Divide both sides of the equation by 6.
    • 30 = 6n
    • 30 = 6n

6 6

  • 5 = n

6

Dividing by 6

30 6n
30 = 6n
  • Check 30 = 6n
  • Replace the variable with the solution:
  • 30 = 6(5)
  • 30 = 30
4 1 2x 4 8
4) 1.2x = -4.8

1.2

  • What is the coefficient in this equation?
  • What is the opposite (inverse) of multiplying by 1.2?
  • Divide both sides of the equation by 1.2.
    • 1.2x = -4.8
    • 1.2x = -4.8

1.2 1.2

  • x = -4

Dividing by 1.2

1 2x 4 8
1.2x = -4.8
  • Check 1.2x = -4.8
  • Replace the variable with the solution:
  • 1.2(-4) = -4.8
  • -4.8 = -4.8
5 3y 2
5) -3y = 2
  • What is the coefficient in this equation?
  • What is the opposite (inverse) of multiplying by -3?
  • Divide both sides of the equation by -3.
    • -3y = 2
    • -3y = 2

-3 -3

  • y =

-3

Dividing by -3

slide17
-3y = 2
  • Check -3y = 2
  • Replace the variable with the solution:
  • -3( ) = 2
  • 2 = 2
using an equation to solve a problem
Using an Equation to Solve a Problem
  • 1) Sarah earns $5 per hour when she baby-sits. How many hours does she need to work to earn $75?
  • Write an equation:
    • 5h = 75
  • Solve the equation:
    • 5h = 75

5 5

h = 15

  • Sarah must work 15 hours to earn $75.00.
using an equation to solve a problem1
Using an Equation to Solve a Problem.
  • 2) A 125 pound person uses 4.4 calories per minute when walking. How many minutes will it take this person to use 44 calories?
  • Write an equation:
    • 4.4m = 44
  • Solve the equation:
    • 4.4m = 44

4.4 4.4

m = 10

  • A 125 pound person must walk for 10 minutes to use 44 calories.
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