1 / 15

Course 2: Inequalities

Course 2: Inequalities. Solving Inequalities by Adding or Subtracting (SOL 7.15). Key Concept. Addition Property of Inequalities Words: If any number is added to each side of a true inequality, the resulting inequality is also true.

bowie
Download Presentation

Course 2: Inequalities

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Course 2: Inequalities Solving Inequalities by Adding or Subtracting (SOL 7.15)

  2. Key Concept • Addition Property of Inequalities • Words: If any number is added to each side of a true inequality, the resulting inequality is also true. • Symbols: For all numbers a, b, and c, the following are true; • If a > b, then a + c > b + c • If a < b, then a + c < b + c

  3. Key Concept • Subtraction Property of Inequalities • Words: If any number is subtracted from each side of a true inequality, the resulting inequality is also true. • Symbols: For all numbers a, b, and c, the following are true; • If a > b, then a - c > b - c • If a < b, then a - c < b - c

  4. Addition and Subtraction Rules

  5. Addition and Subtraction Properties • Examples: • 2 < 4 6 > 3 2 + 5 < 4 + 5 6 – 2 > 3 – 2 7 < 9 4 > 1

  6. Solve an Inequality Using Subtraction • Solve y + 5 > 11 y + 5 – 5 > 11 – 5 (Subtract 5 from both sides) y > 6 (Simplify) Check: y + 5 > 11 7 + 5 > 11 (Replace y with 7 – a number > 6) 12 > 11 (This statement is true.)

  7. Try it! • Solve 9 + a < 3 a + 9 < 3 (You can rewrite the inequality.) a + 9 – 9 < 3 – 9 a < -6 • Check: 9 + a < 3 9 + -6 < 3 (Replace “a” with -6 or less) 3 < 3 Why can you replace a with -6?

  8. Solve an Inequality Using Addition • Solve x – 23 < 12 x – 23 + 23 < 12 + 23 (Add 23 to both sides) x < 35 (This means all numbers less than or equal to 35) Check: x – 23 < 12 35 -23 < 12 (Replace x with 35) 12 < 12 (This statement is true.)

  9. Solve an Inequality Using Addition • Solve -21 > d – 8 -21 + 8 > d – 8 + 8 (Add 8 to each side) -13 > d OR d < -13 • Check -21 > d – 8 -21 > -13 – 8 -21 > -21 Why can you use -13?

  10. Try It! • Solve a – 5 > 6 a – 5 + 5 > 6 + 5 a > 11 Can you use 11 to check your solution? • Check: a – 5 > 6 12 – 5 > 6 7 > 6

  11. Graph Solutions of Inequalities • Solve h – 1.5 < 5 h – 1.5 + 1.5 < 5 + 1.5 (Add 1.5 to each side) h < 6.5 (Simplify) • Graph the solution on a number line 5 6 7 8 • If your variable is on the left, the inequality will point in the direction you should shade

  12. Try It! • Solve 33 < m – (-6) 33 < m + 6 (Simplify) m + 6 > 33 (You can rewrite it with the variable on the left.) m + 6 – 6 > 33 – 6 (Subtract 6 from each side) m > 27 • Graph the solution on a number line. • Place a closed circle on the number line on the number 27 • Shade to the right (positive) side

  13. Graph Solutions of Inequalities • Solve 33 < m – (-6) 33 < m + 6 (Simplify) m + 6 > 33 (You can rewrite it with the variable on the left.) m + 6 – 6 > 33 – 6 (Subtract 6 from each side) m > 27 • Graph the solution on a number line 26 27 28 29

  14. Use an Inequality to Solve a Problem • Katya has $12 to take to the bowling alley. If the shoe rental costs $3.75, what is the most she can spend on games and snacks? • “The most” means “no more than” or “less than or equal to” • Cost of shoe rental + games and snacks must be less than or equal to $12. • $3.75 + c < $12 $3.75 + c - $3.75 < $12 - $3.75 c < $8.25 Katya can spend no more than $8.25.

  15. Try It! • Chris is saving money for a ski trip. He has $62.50, but his goal is to save at least $100. What is the least amount Chris needs to save to reach his goal? • Current amount + money saved must be greater than or equal to $100 • $62.50 + s > $100 $62.50 + s - $62.50 > $100 - $62.50 s > $37.50 Chris must save at least $37.50.

More Related