Course 1
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Course 1. 2-5. Addition Equations. Warm Up. Problem of the Day. Lesson Presentation. Course 1. Warm Up Determine whether each value is a solution. 1. 86 + x = 102 for x = 16 2. 18 + x = 26 for x = 4 3. x + 46 = 214 for x = 168 4. 9 + x = 35 for x = 26. yes. no. yes.

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Course 1

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Course 1

Course 1

2-5

Addition Equations

Warm Up

Problem of the Day

Lesson Presentation

Course 1


Course 1

Warm Up

Determine whether each value is a solution.

1. 86 + x = 102 for x = 16

2.18 + x = 26 for x = 4

3.x + 46 = 214 for x = 168

4.9 + x = 35 for x = 26

yes

no

yes

yes


Course 1

Problem of the Day

After Renee used 40 m of string for her kite and gave 5 m to her sister for her wagon, she had 8 m of string left. How much string did she have to start with?

53 m


Course 1

Learn to solve whole-number addition equations.


Course 1

h + 14

82

h + 14

82

h

h

68

?

The equation h + 14 = 82 can be represented as a balanced scale.

To find the value of h, you need h by itself on one side of the scale.

To get h by itself, first take away 14 from the left side of the scale. Now the scale is unbalanced.

To rebalance the scale, take away 14 from the other side.


Course 1

Taking away 14 from both sides of the scale is the same as subtracting 14 from both sides of the equation.

h + 14 = 82

–14

–14

h = 68

Subtraction is the inverse, or opposite, of addition. If an equation contains addition, solve it by subtracting from both sides to “undo” the addition.


Course 1

?

65 + 87 = 152

?

152 = 152

Additional Example 1A: Solving Addition Equations

Solve the equation. Check your answer.

x + 87 = 152

x + 87 = 152

87 is added to x.

– 87

– 87

Subtract 87 from both sides to undo the addition.

x = 65

Check x + 87 = 152

Substitute 65 for x in the equation.

65 is the solution.


Course 1

?

72 = 18 + 54

?

72 = 72

Additional Example 1B: Solving Addition Equations

Solve the equation. Check your answer.

72 = 18 + y

72 = 18 + y

18 is added to y.

–18

–18

Subtract 18 from both sides to undo the addition.

54 = y

Check 72 = 18 + y

Substitute 54 for y in the equation.

54 is the solution.


Course 1

?

35 + 43 = 78

?

78 = 78

Check It Out: Example 1A

Solve the equation. Check your answer.

u + 43 = 78

u + 43 = 78

43 is added to u.

– 43

– 43

Subtract 43 from both sides to undo the addition.

u = 35

Check u + 43 = 78

Substitute 35 for u in the equation.

35 is the solution.


Course 1

?

68 = 24 + 44

?

68 = 68

Check It Out: Example 1B

Solve the equation. Check your answer.

68 = 24 + g

68 = 24 + g

24 is added to g.

–24

–24

Subtract 24 from both sides to undo the addition.

44 = g

Check 68 = 24 + g

Substitute 44 for g in the equation.

44 is the solution.


Course 1

Additional Example 2: Social Studies Application

Johnstown, Cooperstown, and Springfield are located in that order in a straight line along a highway. It is 12 miles from Johnstown to Cooperstown and 95 miles from Johnstown to Springfield. Find the distance d between Cooperstown and Springfield.

distance between Johnstown and Springfield

distance between Johnstown and Cooperstown

distance between Cooperstown and Springfield

=

+

95 = 12 + d

95 = 12 + d

12 is added to d.

Subtract 12 from both sides to undo the addition.

–12

–12

83 = d

It is 83 miles from Cooperstown to Springfield.


Course 1

Check It Out: Example 2

Patterson, Jacobsville, and East Valley are located in that order in a straight line along a highway. It is 17 miles from Patterson to Jacobsville and 35 miles from Patterson to East Valley. Find the distance d between Jacobsville and East Valley.

distance between Patterson and East Valley

distance between Patterson and Jacobsville

distance between Jacobsville and East Valley

=

+

35 = 17 + d

35 = 17 + d

17 is added to d.

Subtract 17 from both sides to undo the addition.

–17

–17

18 = d

It is 18 miles from Jacobsville to East Valley.


Course 1

Lesson Quiz

Solve each equation.

1.x + 15 = 72

2. 81 = x + 24

3.x + 22 = 67

4. 93 = x+ 14

x = 57

x = 57

x = 45

x = 79

5. Kaitlin is 2 inches taller than Reba. Reba is 54 inches tall. How tall is Kaitlin?

56 inches


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