1 / 16

PRIMITIVE NAVIGATION PROJECT

PRIMITIVE NAVIGATION PROJECT. By Alper Can Yildirim. Aim : To find the latitude and longitude of Cambridge by tracking the shadows of a stick during different time periods of the same day. Equipments. Foot long stick CfA’s roof A digital watch Tape Measure. a straight wooden stick. .

bruce-ellis
Download Presentation

PRIMITIVE NAVIGATION PROJECT

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. PRIMITIVE NAVIGATION PROJECT By Alper Can Yildirim

  2. Aim : To find the latitude and longitude of Cambridge by tracking the shadows of a stick during different time periods of the same day.

  3. Equipments • Foot long stick • CfA’s roof • A digital watch • Tape Measure

  4. a straight wooden stick.  The shadow of the stick The surface

  5. How do we calculate θ ? tan θ = length of the stick / length of the shadow So; θ = tan-1 ( Lstick / Lshadow)

  6. Vertical Angle vs. Time of the Day Vertical Angle Time of the day (hours)

  7. Local Area Noon (LAN) and Meridian Height (MH) MH LAN

  8. Taking the derivative y = -1.286x2 + 29.82x – 147.4 y’ = 2*(-1.286) x + 29.82 = 0 (setting it equal to zero to find the x and y coordinates of the vertex) x = LAN = 11.59 hours  11:35 AM Y= MH = 25.49°

  9. Latitude from meridian height of sun Meridian height Latitude = 90o+Decl-Meridian height Due South

  10. Latitude of Cambridge Latitude experiment = 90° - 21.87° - 25.49° = 42.64° Cambridge = 42.38° Error = 0.26° = 15.6’ Declination value for December 2 is taken from the website http://www.wsanford.com/~wsanford/exo/sundials/DEC_Sun.html Declination of sun @ December 2 = -21°52’ = -21.87°

  11. Conversion to UTC • LAN = 11:35 • LAN + 5 hours + EoT = UTC • We need to find the EoT for December 2. from the equation of time graph.

  12. Longitude of Cambridge • The difference between UTC and 12:00 will give us the longitude. • LAN + 5 hours + EoT = 11:35 + 5h + 10’= 16:45 • 16:45 – 12:00 = 4h 45’ = 4.75 h • 1 h = 15° • Therefore 4.75h = 71.25° • Cambridge = 71.11° • ERROR = 71.25°-71.11° = 0.14° = 8.4’

More Related