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Table of Content. ReviewObjectivesDefinitionsExpected ValueNormal DistributionDistribution of MeanCentral Limit TheoremStandard Normal Distribution. Use of Z ValuesConfidence Interval HypothesisTwo Types of ErrorOne-tailed TestsSteps in Testing a HypothesisWhen to Assume Normal Distribution for MeansUse t-distribution.

Analysis of Means

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**1. **Analysis of Means Farrokh Alemi, Ph.D.
Kashif Haqqi M.D.

**2. **Table of Content Review
Objectives
Definitions
Expected Value
Normal Distribution
Distribution of Mean
Central Limit Theorem
Standard Normal Distribution
Use of Z Values
Confidence Interval
Hypothesis
Two Types of Error
One-tailed Tests
Steps in Testing a Hypothesis
When to Assume Normal Distribution for Means
Use t-distribution

**3. **Review Frequency distribution
Mean, median, and mode
Standard deviation and range

**4. **Objectives Describe different distributions, including normal, and t-distributions.
Calculate and interpret confidence intervals using normal distributions.
Understand types of errors that occurs with hypothesis testing.
Hypothesis testing using t-distribution.

**5. **Example You Should Be Able to Answer at the End The cost of rehabilitation in the industry is $25,000, with a standard deviation of 3000.
Assume that the average cost in our hospital is $30,000.
With 95% confidence, would you say that our cost is different than the industry?

**6. **Definitions A random variable is a variable whose values are determined by chance.
A probability distribution is the probability with which values of a random variable can or are observed.
Probability of a value is the frequency of occurrence of that value divided by the frequency of occurrences of all values.

**7. **Example of Probability Estimates We examined the waiting time of 50 people at our emergency room and found that 10 people waited up to 5 minutes, 20 people waited 5.001 to 10 minutes, 13 people waited 10.001 to 15 minutes and 7 people waited 15.001to 20 minutes.
What is the probability of waiting 5 minutes?
What is the probability of waiting up to 10 minutes?

**8. **Example of Probability Estimates (Continued) The probability of waiting up to 5 minutes is the number of times people waited up to 5 minutes divided by the total number of people: 10/50=.20.
The probability of waiting up to 10 minutes is the number of people who waited up to 10 minutes divided by the total number of people: (10+20)/50=0.6.

**9. **Expected Value Expected value of a distribution is the mean of the distribution.
It represents our long run expectations about the distribution.
The expected value of X is given by summing the product of each value of X, referred to as “i”, times its probability of occurring, referred to as p(X=i).
Expected value = mean = ? p(X=i) * i.

**10. **Example Calculation of Expected Value or Mean We examined the waiting time of 50 people at our emergency room and found that 10 people waited up to 5 minutes, 20 people waited 6 to 10 minutes, 13 people waited 11 to 15 minutes and 7 people waited 16-20 minutes.
What is the mean waiting time at our emergency room?

**11. **Example Calculation of Expected Value or Mean (Continued)

**12. **Normal Distribution A symmetric distribution, meaning that data are evenly distributed about the mean.
Mean, median and mode are the same value.
It has one mode and looks like a bell shaped curve.

**13. **Normal Distribution Continued The curve is continuous, there are no gaps or holes.
The curve never touches the X-axis as any value is possible but with infinitely small probabilities.
99.7% of values are within 3 standard deviations of mean.

**14. **Distribution of Mean If you take a repeated sample of some observations and average them, then you have a distribution for the mean.
The distribution of the mean has the same mean as the distribution of the observations.
Standard deviation of the mean = Standard error = Standard deviation of the observations / Square root of the sample size.

**15. **Example What is the mean, standard deviation and standard error for the following data: 4, 5, 6?
Mean = 5
Standard deviation = 1
Standard error = 1 / 1.7 = 0.58

**16. **Central Limit Theorem For any distribution of n observations with mean of ? and standard deviation ?.
As n increases, the sample means will have a Normal distribution of mean ? and standard deviation ? / square root (n).

**17. **Standard Normal Distribution A Normal distribution.
Mean of zero.
Standard deviation of 1.
Z = (Observed value – mean) / standard deviation of average.
Where standard deviation of mean = standard error = standard deviation of observations divided by square root of sample size.

**18. **Example Calculation of Z What is the Z value for the observed mean of 16, if the average mean is 10 and the standard error is 2?
Z = (16-10) / 2 = 3.

**19. **Another Example What is the Z value for the mean 16 of 4 observations, if the average of repeated sample of means is 10 and the standard deviation of the observations is 2?
Standard deviation of mean = 2 / 4^0.5 = 2/2 =1
Z value for 16 = (16-10)/1 = 6

**20. **Use of Z Values 99.7% of data are between z=3 and z=-3.
Z is the number of standard deviations that X is away from the mean.
0.15% of data are below z=-3.
0.15 % of data are above z=3.

**21. **Use of Z Value (Continued) 95% of data are within z=1.96 and z=-1.96
5% are outside z=1.96 and z=-1.96
2.5% of data are below z=-1.96
2.5% of data are above z=1.96

**22. **Confidence Interval For Normal distributions, the 95% two tailed confidence interval corresponds to observations where z=1.96 and z=-1.96.

**23. **Example What is the 95% confidence interval for mean of 10 and standard deviation of 2?
Lower limit = 10-1.96*2 = 6.08.
Upper limit = 10+1.96*2 =13.92.
At 13.92, Z value is (13.92-10)/2=1.96.
At 6.08 , Z value is (6.08-10) / 2=-1.96.
95% of data fall within these limits.

**24. **Two Tailed Confidence Interval What percentage of data are between z=1.96 and Z=-1.96. Answer: 95%. Often referred to as two-tailed confidence interval.
What percentage of data are below z=1.96?
Answer = 97.5. Often referred to as one tailed-confidence interval.
What percentage of data are above Z=-1.96. Answer =97.5. Often referred to as one tailed confidence interval.

**25. **Hypothesis A statistical hypothesis is a conjecture about population parameter.
The null hypothesis is that there is no difference between the parameter and a value.
The alternative hypothesis states there is a specific difference.

**26. **Possible Outcomes of Hypothesis Test There are four possible outcomes:
We reject a hypothesis that is true.
We reject a hypothesis that is false.
We do not reject a hypothesis that is true.
We do not reject a hypothesis that is false.

**27. **Two Types of Error

**28. **Type 1 Error The level of significance is the maximum probability of type 1 error, symbolized by alpha, ?.
When we base our decision on 95% confidence intervals, 5% of the data are ignored at the two tails of the distribution. Therefore, there is 5% chance that we will reject a hypothesis that is true.
Type one error= 5%, ? = 0.05.

**29. **One-tailed Tests In a two-tailed test, the hypothesis is rejected when the value is above higher limit and below the lower limit.
In a one-tailed test that a parameter is larger than a particular value, the hypothesis is rejected when the value is above higher limit.

**30. **One-tailed Tests (Continued) When we base our decision on 95% confidence intervals, 2.5% of the data are ignored at one tail of the distribution. Therefore, there is 2.5% chance that we will reject a hypothesis that is true.
?=0.025.

**31. **Steps in Testing a Hypothesis State the null hypothesis.
Identify the alternative hypothesis.
Is this a one tailed or two tailed test?
Decide the critical Z value above or below which the hypothesis is rejected, usually 1.96.
Calculate the Z value corresponding to the observation.
Reject or do not reject the hypothesis by comparing the calculated Z to the critical values.

**32. **Example The cost of rehabilitation in the industry is $25,000, with a standard deviation of 3000.
In our hospital, the average cost is $30,000.
With 95% confidence, would you say that our cost is different than the industry?

**33. **Steps in Testing Example Hypothesis The null hypothesis: Our cost is higher or lower than average.
Alternative hypothesis: Our costs are the same as the industry.
This is a two tailed test.
The critical Z is +1.96 or –1.96.
Observed Z = (30000-25000)/3000 = 1.66.
Do not reject the hypothesis.

**34. **When to Assume Normal Distribution for Means When the population variance is known and observations have a Normal distribution.
When the population variance is unknown and there are more than 30 observations.
Otherwise use t-distribution an approximation for Normal distribution.

**35. **Use t-distribution If the values in the population is Normal.
If we have less than 30 observations.
If we have to estimate the standard deviation from the sample and variance of the population is not known.
The t-distribution is used as an approximation for near Normal data.

**36. **Calculating t Statistic t= (observed average – mean) / standard deviation of the average.
Critical value of t depends on sample size.
For one tail test of alpha = 0.025 and two tailed test of alpha =0.05.
The critical t value for sample size of 10 is 2.22 and for sample size of 20 is 2.08.

**37. **Calculating t Statistic (Continued) If we are examining sample size of 10, 95% of data are within t=2.22 and t=-2.22.
If we are examining sample size of 10, 97.5% of data are below t=2.22.

**38. **Testing With t-distribution State the null hypothesis.
Identify the alternative hypothesis.
Is this a one tailed or two tailed test?
Decide the critical t value above or below which the hypothesis is rejected, the value depends on sample size.
Calculate the t value corresponding to the observation.
Reject or do not reject the hypothesis by comparing the calculated t to the critical values.

**39. **Example Data

**40. **Selecting Data Analysis

**41. **Select Descriptive Statistics

**42. **Enter Data Range

**43. **Result