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# Starter - PowerPoint PPT Presentation

Starter. 1. T = 4.00 sec. 2. f = 1/T = .250 Hz. 3. 2.00 Volts. What is the period of the AC voltage? What is the frequency? What is the amplitude? What is the Peak-to-Peak voltage?. 4. 4.00 Volts. AC Waveform. V(t) = V max sin(2 p ft) . f = 1/T. AC Waveforms.

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Presentation Transcript

1. T = 4.00 sec

2. f = 1/T = .250 Hz

3. 2.00 Volts

What is the period of the AC voltage?

What is the frequency?

What is the amplitude?

What is the Peak-to-Peak voltage?

4. 4.00 Volts

V(t) = Vmaxsin(2pft)

f = 1/T

The form for an AC voltage is given by:

V(t) = Vmaxsin(2pft)

where: f = frequency in Hz, and Vmax = the amplitude.

Example: An AC voltage is given by : V(t) = 25V sin(500t)

What’s the frequency?

What’s the period?

What is the Peak-to-Peak Voltage?

1. 500 = 2pf so f = 500/(2p) = 79.6Hz

2. T = 1/f = 1/79.6 = .0126 sec

3. Peak-to-Peak Voltage = 2 x Vmax = 50V

Find the frequency of this waveform.

f = 1/T = 1/.4 = 2.5 Hz

For AC , Ohm’s Law becomes:

Imax = Vmax/R

Example: What’s the maximum current in this circuit?

Imax = Vmax/R = 50/100 = .500Amps

For DC, the power in a resistor is I2R.But for AC, I2 looks like this:

So we use the average value of I2 which turns out to be ½

of the maximum value of I2.

Average of I2 = ½ of maximum value of I2

Average of I2 = ½ of maximum value of I2

Take the square root of each side:

IRMS = Imax/

Also: VRMS = Vmax/

All the power formulas still work – just use RMS values.

P = (IRMS)2R = (IRMS)( VRMS) = (VRMS)2/R

What’s the power sent to the resistor?

VRMS = Vmax/ = 50/

P = (VRMS)2/R = (2500/2) / 100 = 12.5 Watts

Imax = Vmax/R

IRMS = Imax/VRMS = Vmax/

P = (IRMS)2R = (IRMS)( VRMS) = (VRMS)2/R

V(t) = Vmaxsin(2pft)

T = 1/f

A diode bridge is used to convert the output of an AC generator to

D.C. What application would this have in an automobile?

Draw an AC waveform and label the

peak-to-peak voltage, the amplitude, and the period.