1 / 11

Solutions

Solutions. IB Chemistry. A solution is a homogeneous mixture of 2 or more substances . It is made of a solvent and a solute. SOLUTE – the part of a solution that is being dissolved (usually the lesser amount)

ziven
Download Presentation

Solutions

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Solutions IB Chemistry

  2. A solution is a homogeneous mixture of 2 or more substances . It is made of a solvent and a solute.

  3. SOLUTE – the part of a solution that is being dissolved (usually the lesser amount) • SOLVENT – the part of a solution that dissolves the solute (usually the greater amount) • Solute + Solvent = Solution

  4. moles solute ( M ) = Molarity liters of solution Concentration of Solution The amount of solute in a solution is given by its concentration. M = n/V mol dm-3

  5. Concentration • If something is concentrated it has more moles/grams of solute per amount of solvent. • Ex: 12 M HCl • If something is dilute it has less moles/grams of solute per amount of solvent Ex: 0.10 M HCl

  6. PROBLEM: Dissolve 5.00 g of NiCl2 in enough water to make 250 mL of solution. Calculate the Molarity. Step 1: Calculate moles of NiCl2•6H2O Step 2: Calculate Molarity

  7. PROBLEM: Dissolve 5.00 g of NiCl2 in enough water to make 250 mL of solution. Calculate the Molarity. Step 1: Calculate moles of NiCl2•6H2O Step 2: Calculate Molarity [NiCl2•6 H2O] = 0.0841 M

  8. What mass of oxalic acid, H2C2O4, is required to make 250. mL of a 0.0500 M solution?

  9. Dilutions M1 V1 = M2 V2 Where:M1 = concentration of the first solutionV1 = volume of the first solutionM2 = concentration of the second solutionV2 = volume of the second solution Examples: 1.Howmanymililitersof a solution of 4M KI are needed to prepare 400 mL of a 0.76 M ?

  10. 1.Howmanymililitersof a solution of 4M KI are needed to prepare 400 mL of a 0.76 M ?

  11. IB Note • Square brackets [0.60] means • 0.60 M or • 0.60 mol/L or • 0.60 mol dm-3 This is what IB uses!

More Related