1 / 24

§11.1 The Constant e and Continuous Compound Interest .

§11.1 The Constant e and Continuous Compound Interest . The student will be able to work with problems involving the irrational number e The student will be able to solve problems involving continuous compound interest. e is also defined as one of the following limits:. The Constant e. .

zander
Download Presentation

§11.1 The Constant e and Continuous Compound Interest .

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. §11.1 The Constant e and Continuous Compound Interest. • The student will be able to work with problems involving the irrational number e • The student will be able to solve problems involving continuous compound interest.

  2. e is also defined as one of the following limits: The Constant e. Reminder Definition: e = 2.718 281 828 459 … Do you remember how to find this on a calculator?

  3. CompoundInterest Let P = principal, r = annual interest rate, t = time in years, n = number of compoundings per year, and A = amount realized at the end of the time period. • Simple Interest A = P ( 1 + r )t • Compound interest • Continuous compounding A = P e rt.

  4. Example: Generous Grandma Your Grandma puts $1,000 in a bank at 5% for you. Calculate the amount after 5 and 20 years. Simple interest A = 1000 ( 1 + .05) 5 = $1,276.28 A = 1000 ( 1 + .05) 20 = $2,653.30 Compound interest (daily) $1,284.00 $2,718.09 Continuous compounding A = 1000 e (.05)(5) = $1,284.03 A = 1000 e (.05)(20) = $2718.28

  5. Example IRA After graduating from Barnett College, Sam Spartan landed a great job with Springettsbury Manufacturing, Inc. His first year he bought a $3,000 Roth IRA and invested it in a stock sensitive mutual fund that grows at 12% a year. He plans to retire in 35 years. a. What will be its value at the end of the time period? A = P e rt = 3000 e (.12)(35) = $200,058.99 b. The second year he repeats the purchase of a Roth IRA. What will be its value in 34 years? $177,436.41 Show how to become a millionaire!!

  6. Example - Doubling Your Money After graduating from Barnett College, Sam Spartan landed a great job with Springettsbury Manufacturing, Inc. His first year he bought a $3,000 Roth IRA and invested it in a stock sensitive mutual fund that grows at 12% a year. How long will it take for that investment to double? A = P e rt OR 6000 = 3000 e 0.12t AND solve for t. 6000/3000 = e 0.12t or 2 = e 0.12t Take the ln of both sides yielding - But ln 2 = 0.12 t so t = ln 2/ .12 = 5.776 years Remind the students of the “Rule of 72”.

  7. Summary. • The constant e occurs in natural situations. • There are three different interest formulas. • These applications can be of interest.

  8. §11.2 Exponential Functions and Their Derivatives The student will learn about: the composite functions, the derivative of the exponential function, graphing strategies for these functions, and applications.

  9. The Derivative of ex We will use (without proof) the fact that We now apply the four-step process from a previous section to the exponential function. Step 1: Find f (x+h) Step 2: Find f (x+h) –f (x+h)

  10. The Derivative of ex(continued) Step 3: Find Step 4: Find

  11. The Derivative of ex (continued) Result: The derivative of f (x) = ex is f ’(x) = ex. This result can be combined with the power rule, product rule, quotient rule, and chain rule to find more complicated derivatives. Caution: The derivative of ex is not xex-1 The power rule cannot be used to differentiate the exponential function. The power rule applies to exponential forms xn, where the exponent is a constant and the base is a variable. In the exponential form ex, the base is a constant and the exponent is a variable.

  12. Examples Find derivatives for f (x) = ex/2 f (x) = ex/2 f (x) = 2ex +x2 f (x) = -7xe– 2ex + e2

  13. Examples (continued) Find derivatives for f (x) = ex/2 f ’(x) = ex/2 f (x) = ex/2f ’(x) = (1/2) ex/2 f (x) = 2ex +x2f ’(x) = 2ex + 2x f (x) = -7xe– 2ex + e2f ’(x) = -7exe-1 – 2ex Remember that e is a real number, so the power rule is used to find the derivative of xe. The derivative of the exponential function ex, on the other hand, is ex. Note also that e2 7.389 is a constant, so its derivative is 0.

  14. The Natural Logarithm Function ln x We summarize important facts about logarithmic functions from a previous section: Recall that the inverse of an exponential function is called a logarithmic function. For b > 0 and b 1 Logarithmic form is equivalent to Exponential form y = logbxx = by Domain (0, ) Domain (- , ) Range (- , ) Range (0, ) The base we will be using is e. ln x = logex

  15. The Derivative of ln x We are now ready to use the definition of derivative and the four step process to find a formula for the derivative of ln x. Later we will extend this formula to include logbx for any base b. Let f (x) = ln x, x > 0. Step 1: Find f (x+h) Step 2: Find f (x+h) –f (x)

  16. The Derivative of ln x (continued) Step 3: Find Step 4: Find . Let s = x/h.

  17. Examples Find derivatives for f (x) = 5ln x f (x) = x2 + 3 ln x f (x) = 10 – ln x f (x) = x4 – ln x4

  18. Examples (continued) Find derivatives for f (x) = 5ln xf ’(x) = 5/x f (x) = x2 + 3 ln xf ’(x) = 2x + 3/x f (x) = 10 – ln xf ’(x) = – 1/x f (x) = x4 – ln x4f ’(x) = 4 x3 – 4/x Before taking the last derivative, we rewrite f (x) using a property of logarithms: ln x4 = 4 ln x

  19. Other Logarithmic and Exponential Functions Logarithmic and exponential functions with bases other than e may also be differentiated.

  20. Examples Find derivatives for f (x) = log5x f (x) = 2x – 3x f (x) = log5x4

  21. Examples (continued) Find derivatives for f (x) = log5xf ’(x) = f (x) = 2x – 3xf ’(x) = 2x ln 2 – 3x ln 3 f (x) = log5x4f ’(x) = For the last example, use log5x4 = 4 log5x

  22. Example Barnett/Ziegler/Byleen Business Calculus 11e

  23. Example (continued)

  24. Summary For b > 0, b 1 Exponential Rule Log Rule

More Related