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# 独山子第一中学 古丽米热 - PowerPoint PPT Presentation

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## 独山子第一中学 古丽米热

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Presentation Transcript

—毕达哥拉斯

1.同类项的概念：

(1) 同类项与系数无关，

（2）几个常数项也是同类项。

3.完成下面的解题过程：

左边＝＝

所以x＝是方程的解.

-3x+2-2=8-2

-3x=6

-3x÷(-3)=6÷(-3)

x＝-2

-2

-3x+2

8

8

-2

2x

4x

x+2x+4x=140

x+2x+4x=140

7x=140

x=20

=- xy2

(1)3x3+x3; (2) xy2 - xy2。

=4x3

（３）x+2x-4x

=-x

（4）4z-2z-z

＝z

（1）5x-2x=9

（3）-3x+0.5x=10

（4）16y-2.5y-7.5y=10

1.解一元一次方程有两步是哪两步?

(1) 先合并同类项

(2)未知数的系数化为1

2.怎么把未知数的系数化为1?

3.这样做的根据是什么?

4.总量=各部分量的和

(作业本）

再见!