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AI’s. Chapter 7. 7.11. Given:. f = 9192631770 s -1. c = f. c = 3.00 x 10 8 m/s. = 3.26 x 10 7 nm. 7.12. = 6.05780211 x 10 -7 m. = 4.95 x 10 14 Hz.
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AI’s Chapter 7
7.11 Given: f = 9192631770 s-1 c = f c = 3.00 x 108 m/s = 3.26 x 107 nm
7.12 = 6.05780211 x 10-7m = 4.95 x 1014Hz
7.34 An electron in the hydrogen atom makes a transition from an energy state of principal quantum numbers ni to the n =2 state. If the photon emitted has a wavelength of 434 nm, what is the value of ni? = -4.58 x 10-19 J
7.102 a. First, we can calculate the energy of a single photon with a wavelength of 633 nm. = 3.14 x 10-19 J The number of photons produced in a 0.376 J pulse is: = 1.20 x 1018 photons b. Since a 1 W = 1 J/s, the power delivered per 1.00 x 10-9 s pulse is: