1 / 5

AI’s

AI’s. Chapter 7. 7.11. Given:. f = 9192631770 s -1. c =  f. c = 3.00 x 10 8 m/s. = 3.26 x 10 7 nm. 7.12. = 6.05780211 x 10 -7 m. = 4.95 x 10 14 Hz.

yanka
Download Presentation

AI’s

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. AI’s Chapter 7

  2. 7.11 Given: f = 9192631770 s-1 c =  f c = 3.00 x 108 m/s = 3.26 x 107 nm

  3. 7.12 = 6.05780211 x 10-7m = 4.95 x 1014Hz

  4. 7.34 An electron in the hydrogen atom makes a transition from an energy state of principal quantum numbers ni to the n =2 state. If the photon emitted has a wavelength of 434 nm, what is the value of ni? = -4.58 x 10-19 J

  5. 7.102 a. First, we can calculate the energy of a single photon with a wavelength of 633 nm. = 3.14 x 10-19 J The number of photons produced in a 0.376 J pulse is: = 1.20 x 1018 photons b. Since a 1 W = 1 J/s, the power delivered per 1.00 x 10-9 s pulse is:

More Related