1 / 17

Chemistry 1011

Chemistry 1011. Introductory Chemistry II http://www.mi.mun.ca/~pfisher/chemistry.html. Chemistry 1011. TOPIC Rate of Reaction TEXT REFERENCE Masterton and Hurley Chapter 11. 11.1 Meaning of Reaction Rate. YOU ARE EXPECTED TO BE ABLE TO:

willsg
Download Presentation

Chemistry 1011

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Chemistry 1011 Introductory Chemistry II http://www.mi.mun.ca/~pfisher/chemistry.html Chemistry 1011 Slot 5

  2. Chemistry 1011 TOPIC Rate of Reaction TEXT REFERENCE Masterton and Hurley Chapter 11 Chemistry 1011 Slot 5

  3. 11.1 Meaning of Reaction Rate YOU ARE EXPECTED TO BE ABLE TO: • Define the average rate and instantaneous rate of a chemical reaction in terms of reactant and/or product concentration. • Sketch a concentration vs time curve for a reactant of product in a reaction given experimental data. • Calculate average rate or instantaneous rate of reaction from concentration vs time data. • State the qualitative effects of changes in concentration, temperature, surface area of solid reactants and the presence of a catalyst on rate of reaction. Chemistry 1011 Slot 5

  4. Rate of Reaction – What is it? • Some exothermic reactions proceed very quickly at room temperature P4(s) + 5O2(g) P4O10(s) • Other exothermic reactions proceed very slowly at room temperature C6H12O6(s) + 5O2(g) 6CO2(g) + 6H2O(l) • Other reactions, such as the burning of a match after striking, require an initial input of energy Chemistry 1011 Slot 5

  5. Rate of Reaction – What is it? • The rate of a reaction is a measure of how fast a reaction proceeds • The rate of a reaction is a measure of how fast a reactant is used up or how fast a product is formed • The rate is a measure of the change in concentration of reactant or product with time Chemistry 1011 Slot 5

  6. Determining the Average Rate • For the reaction A  B Time (min) [A] (mol.L-1) [B] (mol.L-1) 0.0 1.00 0.00 3.0 0.40 0.60 6.0 0.25 0.75 Average rate = Change in concentration of product Time elapsed = (0.60 – 0.00) mol.L-1 (3.0 – 0.0) min = 0.20 mol.L-1.min-1 for 1st 3 minutes Chemistry 1011 Slot 5

  7. Determining the Average Rate • For the next three minutes: Average rate = Change in concentration of product Time elapsed = (0.75 – 0.60) mol.L-1 (6.0 – 3.0) min = 0.05 mol.L-1.min-1 for 2nd 3 minutes Chemistry 1011 Slot 5

  8. Determining the Average Rate – Some Notes • The average rate for the second period is less that that for the first period. The average rate depends on when you take the measurements. • The decreasing concentration of reactant A could also be used to determine the rate. In this case, by convention, change in concentration of a reactant is negative so that the overall rate is positive. Chemistry 1011 Slot 5

  9. Decomposition of N2O5 N2O5(g) 2NO2(g) + 1/2O2(g) When 1 mole of N2O5 decomposes, 2 moles of NO2 and ½ mole of O2 are formed The rate of decomposition of N2O5 is ½ the rate of production of NO2 and 2x the rate of production of O2. In any given time, D[N2O5] = D[NO2] = D[O2] 2 1/2 D[ ] refers to the change in concentration in moles per litre Chemistry 1011 Slot 5

  10. Concentration of N2O5, 2NO2, and 1/2 O2 over time Chemistry 1011 Slot 5

  11. Decomposition of N2O5 For the time interval Dt , Average rate = -D[N2O5] = D[NO2] = D[O2] Dt 2 Dt 1/2Dt Chemistry 1011 Slot 5

  12. Average Rate for N2O5 • Choose time interval to be 0.0min to 4.0min Dt = 4.0min • For N2O5 D[N2O5] = 0.04mol/L - 0.16mol/L = -0.12mol/L Rate = -D[N2O5] = -(-0.12mol/L) = 0.03mol/L/min Dt 4.0min Repeat for NO2 andO2 • In each case, average rate is the same Chemistry 1011 Slot 5

  13. Average Rate in General In general, for the reaction: aA + bB  cC + dD Rate = -D[A] = -D[B] = D[C] = D[D] a Dt b Dt c Dt d Dt Chemistry 1011 Slot 5

  14. Instantaneous Rate • Instead of the average rate over a period of time, it is possible to determine the instantaneous rate. • This can be done by determining the slope of the tangent to the concentration vs time curve at the desired point • For N2O5 at t = 2 minutes, the rate is 0.28 mol/L/min Chemistry 1011 Slot 5

  15. Determining the rate of decomposition of N2O5 Chemistry 1011 Slot 5

  16. Sketching a Concentration vs Time Curve • Textbook p332 Q7 • For A  B + C Time (sec) 0 2 4 6 8 10 [B] 0 0.100 0.130 0.150 0.165 0.175 • Sketch the curve • Find instantaneous rate at t = 4 seconds Chemistry 1011 Slot 5

  17. Factors Affecting the Rate • Concentration of reactants • Higher concentrations  faster rates • Surface area of solid reactants • More surface area  faster rates • Temperature • Higher temperatures  faster rates • Catalysts • Speed up reactions without being consumed Chemistry 1011 Slot 5

More Related