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Balancing Chemical Reactions. Why?. There are laws!!!!. Matter cannot be created or destroyed only changed. So if you start with 20 hydrogen, you end up with 20 hydrogen. HC 2 H 3 O 2 + NaHCO 3. NaC 2 H 3 O 2 + H 2 O + CO 2. Equations. Vinegar + Baking Soda. Products. Word Equation.

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Balancing chemical reactions

BalancingChemical Reactions

Why?


There are laws
There are laws!!!!

  • Matter cannot be created or destroyed only changed. So if you start with 20 hydrogen, you end up with 20 hydrogen


Equations

HC2H3O2 + NaHCO3

NaC2H3O2 + H2O + CO2

Equations

Vinegar + Baking Soda

Products

Word Equation

Reactants

White Powder + Clear Liquid + Bubbles

Formula Equation


Balancing a formula

HC2H3O2 + NaHCO3

NaC2H3O2 + H2O + CO2

HCCHHHOO + NaHCOOO

NaCCHHHOO + HHO + COO

(5H, 3C, 5O, Na)

(5H, 3C, 5O, Na)

14 atoms

14 atoms

Balancing a Formula


Balanced

Ag + H2S

Ag2S + H2

2Ag, 2H, S

2Ag, 2H, S

Balanced?

Ag2S + H2

Ag + H2S

Ag, 2H, S

2Ag, 2H, S

If not….The ONLY thing you can do is multiply the number of MOLECULES you have. You do this by putting a coefficient in front of the MOLECULE.

The 2 multiplies everything after it until you have a different molecule.

2


Balance the following

Step 1: list all the elements underneath the reactants and products

Step 2: Count how many atoms of each element are on the reactant side and the product side

Balance the following

3rd Step: Put numbers (coefficients like 1, 2, 3, 4, 5 etc..) in front of the compounds that you are short on. This multiplies all of the atoms in the compound. When you do that, you may have to change the other side as well.

2

2

2

Why is it 4? Because 2 H from NaOH and 2 H from H2 are added

1

2

1

2

Na + H2O NaOH + H2

Na= Na=

H = H =

O = O =

2

4

3

4

1

2

1

2

BALANCED

So what do we need to do?


Balance the following1

3 productsrd Step: Put numbers (coefficients like 1, 2, 3, 4, 5 etc..) in front of the compounds that you are short on. This multiplies all of the atoms in the compound. When you do that, you may have to change the other side as well.

Step 2: Count how many atoms of each element are on the reactant side and the product side

Step 1: list all the elements underneath the reactants and products

Balance the following

Why did I put the 2 in front of H2O instead of O2?

2

2

H2O + O2 H2O2

H = H =

O = O =

2

4

2

4

Because only changing O2 would not help me with the H.

3

4

2

4

So what do we need to do?

BALANCED


Balancing chemical reactions

2 products

2

2

1

2

2

4

2

4

CaCl2 Ca2 + Cl2

Ca= Ca=

Cl = Cl =

BALANCED


Balancing chemical reactions

6 products

4

3

2

3

2

2

2

1

1

2

Al + NaOH Na3AlO3 + H2

Al= Al=

Na= Na =O = O =

H = H =

1

3

4

6

6

3

1

3

4

6

3

6

2

4

6

1

3

4

6

BALANCED


Now you do some at your desk
Now you do some at your desk products

Zn + HCl ZnCl2 + H2

Al + O2 Al2O


Balancing chemical reactions

2 products

1

1

Zn + HCl ZnCl2 + H2

Zn= Zn=

H= H =

Cl = Cl =

2

1

2

2

1

2

BALANCED


Balancing chemical reactions

4 products

2

1

4

2

4

Al + O2 Al2O

Al= Al=

O = O =

2

1

2

BALANCED


Balancing chemical reactions

  • Zn + products2HCl  ZnCl2 + H2

  • 12Al + 3O26Al2O