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The Hardy-Weinberg Equilibrium

The Hardy-Weinberg Equilibrium If we mate two individuals that are heterozygous (e.g., Bb ) for a trait, we find that : 25% of their offspring are homozygous for the dominant allele ( BB ) 50% are heterozygous like their parents ( Bb ) and

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The Hardy-Weinberg Equilibrium

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  1. The Hardy-Weinberg Equilibrium If we mate two individuals that are heterozygous (e.g., Bb) for a trait, we find that : 25% of their offspring are homozygous for the dominant allele (BB) 50% are heterozygous like their parents (Bb) and 25% are homozygous for the recessive allele (bb) and thus, unlike their parents, express the recessive phenotype. (p+q)2 = p2 + 2pq + q2 Let p represent the frequency of one gene in the pool and q the frequency of its single allele. So, p + q = 1 p2 = the fraction of the population homozygous for p q2 = the fraction homozygous for q 2pq = the fraction of heterozygotes

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