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About galaxy NGC 7083, redshift and dark matter

Comenius UPMC Paris Juin 2011. Dancing with a galaxy. About galaxy NGC 7083, redshift and dark matter. Measuring Edwin Hubble’s redshift and Vera Rubin’s dark matter. Suzanne FAYE, Lycée Chaptal, Paris, France Michel FAYE, Lycée Louis-le-Grand, Paris, France mfaye2@wanadoo.fr.

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About galaxy NGC 7083, redshift and dark matter

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  1. Comenius UPMC Paris Juin 2011 Dancing with a galaxy About galaxy NGC 7083, redshift and dark matter Measuring Edwin Hubble’s redshift and Vera Rubin’s dark matter Suzanne FAYE, Lycée Chaptal, Paris, France Michel FAYE, Lycée Louis-le-Grand, Paris, France mfaye2\@wanadoo.fr

  2. Is my cat a star? Preliminary : SalsaJ colors, pixels and slices Ready now to visit galaxy NGC 7083 !!

  3. I - About galaxy NGC 7083 Where? in Indus Constellation (Southern hemisphere) Why Southern hemisphere? Because of very performant telescope ESO – VLT (Chili) Internet: Ask NGC 7083

  4. NGC 7083 1 - About Indus Constellation southern hemisphere (visible with VLT, Chili) http://www.starrynightphotos.com/constellations/indus.htm The constellation was one of twelve constellations created by Pieter DirkszoonKeyser and Frederick de Houtman between 1595 and 1597, and itfirst appeared in Johann Bayer's Uranometria of 1603.Since Indus was introduced in the 17th century, and lies in the south, it was notknown to classical or early cultures thus they produced no mythology concerning it.

  5. 2 – Angular dimensions of galaxy NGC 7083 1 - Open Google Earth 2 - Affichage/ Explorer / Ciel (Sky) 3 – Look for : NGC 7083: we obtain Right Ascension and Declinaison 4 – Zoom to have full galaxy 5 – Outils (Tools) / Regle (secondes d’arc) 6 – Make measures (in two perpendicular directions) Answer for the angular sizes of the galaxy: 3,5’ long; 2,0’ wide

  6. Towards observation (p/ 2) - i 3 – What is the orientation of the galaxy disc plane; angle i ? . We see as an ellipse what is in fact a circle i length i width i Answer for angle i : cos(i) = width/length = 2,0 / 3, 5 => i = 55°; sin(i) = 0,82

  7. 4 – What is redshift of a galaxy? Sun Galaxy Absorption lines in the optical spectrum of a distant galaxies (right), as compared to absorption lines in the optical spectrum of the Sun (left). Arrows indicate redshift. Wavelength increases up towards the red and beyond (frequency decreases). See Doppler-Fizeau effect Dl / l = v /c

  8. 5 – Part of NGC 7083 spectrum, by VLT - ESO Lines emitted by atoms from the disk of the galaxy Continuum emitted by the core of the galaxy

  9. 6- Have a look at Image/ Informations

  10. lines Core of the galaxy Ha 7 – Which lines did VLT astronomers have sent to us? N nitrogen H hydrogen S sulfur • (pixel) = a*(pixel-reference) + b = CDELT1 * (pixel+ 1559) + 4937 (Å) Image Information: CRPIX1 = - 1559. / Reference pixel CRVAL1 = 4937. / Coordinate at reference pixel CDELT1 = 0.986999988556 / Coordinate increment per pixel CTYPE1 = 'Angstrom ' / Units of coordinate Be careful: 1 Å = 0.1 nm

  11. 8- How can we get the exact number of pixels? « Plot Profile! » or ZOOM and count pixels Raie N II a : X = 140, So λ (nm) = (140 + 1559) x 0,09870 + 493,7 → λ = 661,39 nm

  12. 9 – Calculate redshift for each line • (pixel) = CDELT1*(pixel-reference) + b = 0,09870 * (pixel+ 1559) + 493,7 (nm) Let us keep VNGC7083 = 3.06*103 km/s Good measurement!

  13. 10 – What is the distance D of galaxy NGC 7083? Let us use Hubble law : Vgalaxie = H * D , with H ≈ 73 km.s-1.Mpc-1 1pc = 3,26 a.l. et 1a.l. ≈ 9,47.1015 m D = VNGC7083 /H = 3060/73 = 42 Mpc = 4,2 x107 pc D = 1.4 x108 a.l. D = 1,3 x1024 m

  14. 11 - Measuring the size dNGC7083 of the galaxy dgalaxy = α(en radians) * D αNGC 7083 ≈ 3,5’= 1,02. 10-3 rad D = 4,23 x107 pc Our Galaxy, Milky Way : dMilky Way = 25 000 pc NGC 7083: dNGC7083 = 4,2 . 104 pc = 1,7 * dMilky Way

  15. 12- Have sizes of the galaxy with Image/ Informations and apparent diameters acore≈ 16 pixels = 13’’ Width of the picture ≈289 pixels = 237’’ αNGC 7083 ≈ 3,5’ = 210’’= 256 pixels

  16. 12bis- Another way to measure the size dcore of the core of the galaxy : Plot « vertical »profile. The core ! Let us evaluate: dcore = 16 pixels; dNGC7083≈ 256 pixels => dcore / dgalaxy = 16/256 et dNGC7083 = 4,3. 104 pc ; so dcore ≈ 2,7.103pc= 8,3.1019 m

  17. Redshift II – Dancing with a galaxy Redshift of the core + « Relative » Doppler shift by rotating around the core

  18. Dark matter bounded? 2 R Dark matter bounded? Turning around the core 1 – Why is the shift of the spectrum constant for r > R ? Vera Rubin (born 1928) is an astronomer who has done pioneering work on galaxy rotation rates. Her discovery of what is known as "flat rotation curves" is the most direct and robust evidence of dark matter.

  19. 2 – What is a flat rotation curve? Let us watch Doppler shift ! * Doppler shift Dl is constant for r > R, which means that the relative speed is then constant * Because of the inclination i of the galaxy plane, Dl / l = Vrelative * sin(i) /c ) Let us imagine that the arms of the dancer are blocked by ???Dark Matter!!! V rotation

  20. 3 – How can we measure Dl / l ? You can either use quotient in pixel, or use CDELT1: 1 pixel ≈ 1 Å or 0,1 nm; remember sin(i); i = 55 degrees Vrotation = [Dl/l] * c / sin (55) We use line Ha , with rotation shift l (Ha /core)≈ 6630Å So: Vrotation ≈ (4/6630)* c/0.82 Vrotation≈ 2,21. 105m/s Around the core of the galaxy: mV² / r = G m M/ r² so Mcore= V² R / G G=6,67. 10-11 SI R= dcore/2 ≈(see slide16) 4,15.1019 m Mcore = 3. 1040 kg agalaxy = 256 pixels Ha : the brightestline acore = 16 pixels 2 Dl = 8 pixels ≈ 8 Å or 0,8 nm

  21. Bright galaxies, dark matters, by Vera Rubin

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