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Lecture 3. Demand for junctions. Domestic Demand:. Domestic Demand:. For the 1 st junction : P domestic = Area*Population Density = 3256.82* 0.05= 163 Q domestic = P domestic *150 *1.35 /1000 = 32.98 m³/d
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Lecture 3 Demand for junctions
Domestic Demand: For the 1st junction : • P domestic = Area*Population Density = 3256.82* 0.05= 163 • Q domestic = P domestic*150 *1.35 /1000 = 32.98 m³/d • Average Demand for capita / day =150 L/c/d • The value 1.35 = 25% loses in the network and the equivalent commercial demand which was taken 10% domestic demand.
Public Demand: For public demand: • Average Demand for capita / day = 40 L/c/d • Q public = # employee * 40 * 1.25 (25% UFW)
Public Demand: For junction 4 which has a public demand, • Area = 548.38 m² , • Let # of employee = 0.2*Area =109.68 =110 person • Q public =110*40*1.25/1000 = 5.5 m³ /day
Commercial Demand: For junction which has a commercial demand, • Let # of = 1200 person/day • Average Demand for capita / day = 30 L/c/d • Q Commercial = 1200*30*1.25/1000 = 45 m³ /day • (25% UFW)
Industrial Demand: For junction which has an industrial demand, • Let # of workers = 850 person • Average Demand for capita / day = 30 L/c/d • Add 30% for cleaning works.. etc • Q Industrial = 850*30*1.55/1000 = 40 m³ /day • (25% UFW, 30% Others)
School Demand: For junction which has a school demand, • # of pupils/school = 1200 pupil • Average Demand for capita / day = 10 L/c/d • Q school = 1200*10*1.25/1000 = 15 m³ /day • (25% UFW)
Hospital Demand: For junction which has a hospital demand, • Let # of beds = 160 • Average Demand for capita / day = 300 L/c/d • Q Hospital = 160*300*1.25/1000 = 60 m³ /day • (25% UFW)
Mosque Demand: For junction which has a mosque demand, • # of prayers/day =500 person • Average Demand for capita / day = 25 L/c/d • Q Mosque = 500*25*1.25/1000 = 15.7 m³ /day • (25% UFW)
Agricultural Demand: For junction which has a agricultural demand, • Agricultural demand varies according to the type of trees. • Demand for Green areas = 5 m3/Donum/Week • Average Demand / day = ??? m3/d • Don’t Forget (25% UFW)
Tourist Demand: For junction which has a tourist demand, • Demand for Hotels = 180 L/C/d • Average Demand / day = ??? m3/d • Don’t Forget (25% UFW)
Total Demand: Qtotal of network = ∑ Qnodes m3/day Average Demand: For each type of demand Qavg_i = ∑ Qnodes / 24 m3/hr Where (i) is the type of demand
Example.. Qtotal of network (m3/day)