Stoichiometry Georgia ChaseWehner Prd.8 4/25/11 - PowerPoint PPT Presentation

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Stoichiometry Georgia ChaseWehner Prd.8 4/25/11

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  1. Stoichiometry Georgia ChaseWehner Prd.8 4/25/11 Start

  2. How many grams of ammonia can be produced in a reaction of 52 grams of hydrogen? First step

  3. How many grams of ammonia can be produced in a reaction of 52 grams of hydrogen? What is the first step? Create the equation Start DA Balance the equation

  4. How many grams of ammonia can be produced in a reaction of 52 grams of hydrogen? Yippy! You got it right! N2 + H2 NH3 Now What? Start DA GFMs Balance the equation

  5. How many grams of ammonia can be produced in a reaction of 52 grams of hydrogen? Correct!  N2 + 3H2 2NH3 Next we… Start DA with 52g N2 Start DA with 52g H2 Make GFMs

  6. How many grams of ammonia can be produced in a reaction of 52 grams of hydrogen? Right O! 52g H2X 1 1mole H2 1g H2 1mole H2 2g H2 1g H2 1mole H2

  7. How many grams of ammonia can be produced in a reaction of 52 grams of hydrogen? Bingo! 52g H2 X 1mole H2 1 2g H2 2mole NH3 3mole H2 3mole H2 2mole NH3 1mole N2 3mole H2

  8. How many grams of ammonia can be produced in a reaction of 52 grams of hydrogen? Amazing! 52g H2 X 1mole H2 X 2mole NH3 1 2g H2 3mole H2 Now we go to… 28g N2 1mole NH3 1mole NH3 17g NH3 17g NH3 1mole NH3

  9. How many grams of ammonia can be produced in a reaction of 52 grams of hydrogen? You’re so smart. 52g H2 X 1mole H2 X 2mole NH3 X 17g NH3 1 2g H2 3mole H2 1mole NH3 What now? Find the answer Go to the next tutorial. That’s the end!

  10. How many grams of ammonia can be produced in a reaction of 52 grams of hydrogen? An the answer is… 52g H2 X 1mole H2 X 2mole NH3 X 17g NH3 = 1 2g H2 3mole H2 1mole NH3 294 1/3g NH3 294.66667g NH3 290g NH3

  11. How many grams of ammonia can be produced in a reaction of 52 grams of hydrogen? 52g H2 X 1mole H2 X 2mole NH3 X 17g NH3 = 290g NH3 1 2g H2 3mole H2 1mole NH3 Congrats you got it right! Your prize…

  12. Tadaaaaa!!!

  13. WRONG! Grrr I thought you were smarter than that, go back and try again. 