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Using enthalpies changes of formation, calculate the enthalpy change of combustion of benzene as shown by the equation below C 6 H 6 ( l ) + 7½O 2 ( g )  6CO 2 ( g ) + 3H 2 O ( l )  H reaction  =  a  H  f (products) -  b  H  f (reactants)

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  1. Using enthalpies changes of formation, calculate the enthalpy change of combustion of benzene as shown by the equation below C6H6(l) + 7½O2 (g)  6CO2 (g) + 3H2O (l) Hreaction = aHf (products) - bHf (reactants) aHf (products) = [6 Hf(CO2 (g)) + 3Hf (H2O (l))] = [6 mol (-393.5 kJ mol-1) + 3 mol (-285.8 kJ mol-1)] = -3218.4 kJ bHf (reactants) = [7½ Hf (O2 (g)) + 1Hf (C6H6 (l)) ] = [7½mol (+0 kJ mol-1) +1mol (+49 kJ mol-1)] = + 49 kJ Hreaction = -3218.4 – (+49 kJ) = - 3267.4 kJ

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