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pirmyX ivAMjk

pirmyX ivAMjk. jmwq : dsvIN AiDAwie: qIjw ivSw:gixq. iqAwr krqw :. nSIr,jsivMdr , suKivMdr,cmkOr inrml,rmn,hrpRIq ggn,Amn,mndIp. srkwrI sInIAr sYkMfrI skUl is`DUvwl, pitAwlw. ivSw sUcI. bhupd dI pRIBwSw pirmyX ivAMjk bwry jwxkwrIpirmyX ivAMjkW nUM inmnqm rUp ivc drswauxw

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pirmyX ivAMjk

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  1. pirmyXivAMjk jmwq : dsvIN AiDAwie: qIjw ivSw:gixq iqAwrkrqw: • nSIr,jsivMdr, • suKivMdr,cmkOr • inrml,rmn,hrpRIq • ggn,Amn,mndIp srkwrI sInIAr sYkMfrI skUl is`DUvwl, pitAwlw

  2. ivSw sUcI • bhupd dI pRIBwSw • pirmyX ivAMjk bwry jwxkwrIpirmyX ivAMjkW nUM inmnqm rUp ivc drswauxw • pirmyX ivAMjkW dw joV Aqy Gtwau • pirmyX ivAMjkW dw guxW Aqy Bwg

  3. bhupd dIpRIBwSw a 0 +a 1x 1+a 2x 2+a 3x 3+……a nxn nUM n GwqvwlIbhupdAwKdyhn[ jdoik a 0,a 1,a 2…… vwsqivksMiKAwvWhn [ bhupdleIGwqpUrnhoxIjrUrIhY[

  4. pirmyX ivAMjkW bwry jwxkwrI jykrp(x)Aqyq(x) do bhupdwNhoxqWp(x)/q(x) nUMpirmyXivAMjkikhwjWdwhY[ie`Qyq(x) ≠0,p(x) nUM AMS Aqyq(x)nUM hr ikhwjWdwhY[AMS Aqy hr dwbhupdhoxwjrUrIhuMdwhYY[

  5. audwhrx:- svwl:-x 2-√¯ 3x+5 bhupdhYjWnhI, jynhIqWikauN? h`l:-ikauikie`QyxdIGwq 2 hY [ BwvGwqpUrnsMiKAwhY[ iesleIiehivAMjkbhupdnhIhY[

  6. pirmyX ivAMjkW dw inmnqm rUp pirmyX ivAMjkW dy guxnKMf bxwky guxnKMf nUM ktw dyx nwl inmnqm rUp pRwpq kIqw jw skdw hY[

  7. audwhrx : Svwl: x 2-5x+6/x 2-7x+12nUM inmnqm rUp ivc drswau[ h`l: ie`Qy x 2-5x+6=(x-3)(x-2) Aqy x 2-7x+12=(x-3)(x-4) ies leI x 2-5x+6 / x 2-7x+12 =(x-3)(x-2) /(x-3) (x-4) =(x-2) /(x-4)

  8. pirmyX ivAMjkw dw joV Aqy Gtwau pirmyX ivAMjkw dy hrw dw l.s.vlY ky l.s.v nUM hr nwl Bwg dy ky AMS nwl guxw krky h`l kIqw jWdw hY[

  9. audwhrx : svwl: srl kro =3 /x-1 -2 /x+1 h`l:-hrw dw l.s.v (x-1) (x+1) =(x-1)(x+1)=x 2-1 l.s.v nUM (x-1)nUM Bwg dy ky ,au`qr (x+1) nUM AMS 3 nwl guxw krky , iesy qrHw l.s.v nUM(x+1) nwl Bwg dy ky (x-1) nMU 2 nwl guxw krky 3(x+1)-2 (x-1) /x 2-1 =3x+3-2x+2 /x 2-1 X+5 /x 2-1

  10. pirmyX ivAMjkw dw guxnPl guxnPl ivco sWJy guxnKMf k`ty jWdy hn Aqy bwkI nMU AMSW nUM AMSW nwl Aqy hrW nUM hrW nwl guxw kIqw jWdw hY[

  11. audwhrx:- =svwl :- 2x /x-3 ×x-1 /x+4 h`l:-ie`Qy sWJw guxnKMf (k`tx) vwlw koeI nhI ies leI AMSW dI Awps ivc Aqy hrW dI Awps ivc guxw hovygI[ =2x(x-1) /(x-3)(x+4) =2x 2-2x /x 2-3x+4x-12 2x 2-2x / x 2+x-12 Ans

  12. pirmyX ivAMjkwN dw BwgPl Aijhy svwlw ivc Bwg nMU guxw bxw ky dUsry pirmyX ivAMjkw nUM aultw ilAw jWdw hY[

  13. auudwhrx: svwl: x 2-1 /x-4 ÷x+5 /x-4 h`l: =x 2-1 /x-4 ×x+4 /x+5 = x 2-1 / x+5 ans

  14. audySW dI pRwpqI ividAwrQIAW nUM bhupd ,pirmyX ivAMjkW bwry pqw c`ilAw [ pirmyX ivAMjkW nUM inmnqm rUp ivc drswauxw AwieAw, pirmyX ivAMjkW dw joV, Gtwau,guxw,Bwg krn dI jwxkwrI pRwpq hoeI[

  15. AiBAws: Coty auqrW vwly pRSn kI x 3-5√¯x+2 bhupd hY? kI x /x 2-5x+2 pirmyX ivAMjk hY? x 3+8 /x 2-2x-8 nMU inmnqm rUp ivc drswau[

  16. v`fy au`qrW vwly pRSn- • x 2+x-1 / x 2-1Aqy x+1 / x-1dw joVpqwkro[ 2. (x-3) / (x+4) Aqy(x+1) / (x-3)dwguxnPlpqwkro[

  17. DMnvwd

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