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Understand thermodynamics by learning about heat transfer and specific heat capacity. Discover how temperature changes, heat is involved, and specific heat capacity is calculated for different materials. Dive into practical examples about water, clay, and marble.
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Thermodynamics If there was a thermometer attached to the rubber band, what would you observe?
Thermodynamics If there was a thermometer attached to the rubber band, what would you observe? The temperature goes up
Thermodynamics If there was a thermometer attached to the rubber band, what would you observe? The temperature goes up ∆Q α ∆T ∆Q is the heat involved
Thermodynamics Heat ∆Q α ∆T
Thermodynamics Heat ∆Q α ∆T
Thermodynamics Heat ∆Q α ∆T or ∆Q = (slope) m ∆T ∆Q m∆T
Thermodynamics Heat ∆Q α ∆T or ∆Q = (slope) m ∆T ∆Q Water NOTE: Equal masses Iron m∆T
Thermodynamics Heat ∆Q = (slope) m ∆T The slope of this graph is called the specific heat capacity. For water, the specific heat capacity is 4.2 kj/kg-oC
Thermodynamics Heat ∆Q = (4.2 kj/kg-oC ) m ∆T How much heat is required to raise the temperature of 10 kg of water by 20 oC?
Thermodynamics Heat ∆Q = (4.2 kj/kg-oC ) m ∆T How much heat is required to raise the temperature of 10 kg of water by 20 oC? Heat = (4.2 kj/kg-oC ) (10 kg) (20 oC) = 840 kj
Thermodynamics Heat ∆Q = (slope) m ∆T ∆Q Water NOTE: Equal masses Clay, Marble m∆T
Thermodynamics Heat ∆Q = (slope) m ∆T ∆Q Water NOTE: Equal masses Clay, Marble m∆T
Thermodynamics Heat ∆Q = (slope) m ∆T ∆Q Water NOTE: Equal masses Clay, Marble m∆T
Thermodynamics Heat ∆Q = (slope) m ∆T ∆Q Water NOTE: Equal masses Clay, Marble m∆T
Thermodynamics Heat ∆Q = (slope) m ∆T ∆Q Water NOTE: Equal masses Clay, Marble m∆T Small change Large change
Thermodynamics Heat ∆Q = (slope) m ∆T The variation in temperature between day and night on mars can be as much as 150 degree Fahrenheit, while the variation in temperature on the earth is far smaller. Why?