1 / 25

Solving Quadratics by Completing the Square & Quadratic Formula

Solving Quadratics by Completing the Square & Quadratic Formula. By: Jeffrey Bivin Lake Zurich High School jeff.bivin@lz95.org. Last Updated: October 24, 2007. X 2 + 6x + 9. x. 1. 1. 1. 1. 1. 1. x. x + 3. Now, complete the square. 1. + 9. 1. 1. x + 3. Jeff Bivin -- LZHS.

tpirkle
Download Presentation

Solving Quadratics by Completing the Square & Quadratic Formula

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Solving QuadraticsbyCompleting the Square&Quadratic Formula By: Jeffrey Bivin Lake Zurich High School jeff.bivin@lz95.org Last Updated: October 24, 2007

  2. X2 + 6x + 9 x 1 1 1 1 1 1 x x + 3 Now, complete the square 1 + 9 1 1 x + 3 Jeff Bivin -- LZHS

  3. X2 + 4x + 4 x 1 1 1 1 x x + 2 Now, complete the square 1 4 1 x + 2 Jeff Bivin -- LZHS

  4. X2 + 5x + 25/4 x 1 1 .5 1 1 1 x x + 5/2 Now, complete the square 1 + 25/4 1 .5 x + 5/2 Jeff Bivin -- LZHS

  5. X2 - 6x + 9 x 1 1 1 1 1 1 1 1 1 x - 3 x 1 + 9 1 1 turn 1 square over x - 3 turn 1 square over turn 2 squares over turn 2 squares over turn 3 squares over Jeff Bivin -- LZHS

  6. Solve by Completing the Square x2 + 10x + 8 = 0 (x2 + 10x ) = -8 (x2 + 10x + (5)2) = -8 + 25 (5)2 = 25 (x + 5)2 = 17 Jeff Bivin -- LZHS

  7. Solve by Completing the Square 3x2 + 24x + 12 = 0 3 x2 + 8x + 4 = 0 (x2 + 8x ) = -4 (x2 + 8x + (4)2) = -4 + 16 (4)2 = 16 (x + 4)2 = 12 Jeff Bivin -- LZHS

  8. Solve by Completing the Square 2x2 + 5x - 12 = 0 2 Jeff Bivin -- LZHS

  9. Solve by Completing the Square 2x2 - 12x - 11 = 0 2 Jeff Bivin -- LZHS

  10. Solve by Completing the Square -5x2 + 12x + 19 = 0 -5 Jeff Bivin -- LZHS

  11. Solve by Completing the Square 5x2 - 30x + 45 = 0 5 Jeff Bivin -- LZHS

  12. Solve by Completing the Square 5x2 - 30x + 75 = 0 5 Jeff Bivin -- LZHS

  13. Convert to vertex form y = x2 + 10x + 8 y - 8 = (x2 + 10x ) (5)2 = 25 y - 8 + 25 = (x2 + 10x + (5)2) y + 17 = (x2 + 10x + (5)2) y + 17 = (x + 5)2 - 17 x + 5 = 0 Axis of symmetry: x = -5 Vertex: (-5, -17) Jeff Bivin -- LZHS

  14. Convert to vertex form y = 5x2 - 30x + 46 y - 46 = 5(x2 - 6x ) 5(-3)2 = 45 y - 46 + 45 = 5(x2 - 6x + (-3)2) y - 1 = 5(x2 - 6x + (-3)2) y - 1 = 5(x - 3)2 + 1 x - 3 = 0 Axis of symmetry: x = 3 Vertex: (3, 1) Jeff Bivin -- LZHS

  15. Solve by Completing the Square ax2 + bx + c = 0 a The Quadratic Formula Jeff Bivin -- LZHS

  16. Solve using the Quadratic Formula 3x2 + 7x - 4 = 0 a = 3 b = 7 c = -4 Jeff Bivin -- LZHS

  17. Solve using the Quadratic Formula 6x2 + 9x + 2 = 0 a = 6 b = 9 c = 2 Jeff Bivin -- LZHS

  18. Solve using the Quadratic Formula 5x2 - 8x + 1 = 0 a = 5 b = -8 c = 1 Jeff Bivin -- LZHS

  19. Solve using the Quadratic Formula 6x2 - 17x - 14 = 0 a = 6 b = -17 c = -14 Jeff Bivin -- LZHS

  20. Solve using the Quadratic Formula x2 + 6x + 9 = 0 a = 1 b = 6 c = 9 Jeff Bivin -- LZHS

  21. Solve using the Quadratic Formula 3x2 + 7x + 5 = 0 a = 3 b = 7 c = 5 Two Imaginary Solutions Jeff Bivin -- LZHS

  22. Why do some quadratic equations have 2 real solutionssome have 1 real solution and some have two imaginary solutions?

  23. Now Consider ax2 + bx + c = 0 Discriminant 89 0 -11 If discriminant > 0, then 2 real solutions If discriminant = 0, then 1 real solution If discriminant < 0, then 2 imaginary solutions Jeff Bivin -- LZHS

  24. That's All Folks Jeff Bivin -- LZHS

More Related