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Statistics. Inferences About Population Variances. Contents. Inference about a Population Variance. Inferences about the Variances of Two Populations. STATISTICS in PRACTICE. The U.S. General Accounting Office (GAO) evaluators studied a Department of Interior program

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Statistics

Statistics

Inferences About Population Variances


Contents
Contents

  • Inference about a Population Variance

  • Inferences about the Variances of Two Populations


Statistics in practice
STATISTICSin PRACTICE

  • The U.S. General Accounting

    Office (GAO) evaluators studied

    a Department of Interior program

    established to help clean up the

    nation’s rivers and lakes.

  • The audits reviewed sample data on the oxygen content, the pH level, and the amount of suspended solids in the effluent.


Statistics in practice1
STATISTICSin PRACTICE

  • The hypothesis test was conducted about the variance in pH level for the population of effluent. The population variance in pH level expected at a properly functioning plant.

  • In this chapter you will learn how to conduct statistical inferences about the variances of one and two populations.


Inferences about a population variance
Inferences About a Population Variance

  • Chi-Square Distribution(2)

  • Interval Estimation of 2

  • Hypothesis Testing


Chi square distribution
Chi-Square Distribution

  • The chi-square distribution is the sum of

  • squared standardized normal random

  • variables such as

  • The chi-square distribution is based on

  • samplingfrom a normal population.


Chi square distribution1
Chi-Square Distribution

  • Probability density function

  • where

  • Mean: k

  • Variance: 2k


Chi square distribution2
Chi-Square Distribution

  • The sampling distribution of (n - 1)s2/ 2

  • has a chi-square distribution whenever a simple

  • random sample of sizenis selected from a

  • normal population.

  • We can use the chi-square distribution to

  • developinterval estimates and conduct hypothesis

  • tests about a population variance.


Statistics

Examples of Sampling Distribution of (n - 1)s2/ 2

With 2 degrees

of freedom

With 5 degrees

of freedom

With 10 degrees

of freedom

0


Statistics

  • For example, there is a .95 probability of obtaining a (chi-square) value such that

Chi-Square Distribution


Chi square distribution3
Chi-Square Distribution chi-square distribution that provides an area of

  • A Chi-Square Distribution with 19 Degrees of Freedom


Chi square distribution4
Chi-Square Distribution chi-square distribution that provides an area of

  • Selected Values form the Chi-Square Distribution Table


Chi square distribution5
Chi-Square Distribution chi-square distribution that provides an area of


Statistics

Interval Estimation of chi-square distribution that provides an area of 2

.025

.025

95% of the

possible 2 values

2

0


Statistics

Interval Estimation of chi-square distribution that provides an area of 2

  • There is a (1 –a) probability of obtaining a c2value such that

  • Substituting (n– 1)s2/s 2 for the c2 we get

  • Performing algebraic manipulation we get


Interval estimation of 2
Interval Estimation of chi-square distribution that provides an area of 2

  • Interval Estimate of a Population Variance

where thevalues are based on a chi-square

distribution withn - 1 degrees of freedom and

where 1 -is the confidence coefficient.


Interval estimation of
Interval Estimation of chi-square distribution that provides an area of 

  • Interval Estimate of a Population Standard Deviation

Taking the square root of the upper and lower

limits of the variance interval provides the

confidenceinterval for the population standard

deviation.


Interval estimation of 21
Interval Estimation of chi-square distribution that provides an area of 2

  • Example: Buyer’s Digest (A)

Buyer’s Digest rates thermostats manufactured

for home temperature control. In a recent test, 10

thermostats manufactured by The rmoRitewere

selected and placed in a test room that

was maintained at a temperature of 68oF.

The temperature readings of the ten thermostats

are shown on the next slide.


Statistics

Interval Estimation of chi-square distribution that provides an area of 2

  • Example: Buyer’s Digest (A)

We will use the 10 readings below to

develop a 95% confidence interval

estimate of the population variance.

Thermostat1 2 3 4 5 6 7 8 9 10

Temperature 67.4 67.8 68.2 69.3 69.5 67.0 68.1 68.6 67.9 67.2


Statistics

Our value chi-square distribution that provides an area of

Interval Estimation of 2

For n - 1 = 10 - 1 = 9 d.f. and a = .05

Selected Values from the Chi-Square Distribution Table


Statistics

Interval Estimation of chi-square distribution that provides an area of 2

For n - 1 = 10 - 1 = 9 d.f. and a =.05

.025

Area in

Upper Tail

= .975

2

0

2.700


Statistics

Our value chi-square distribution that provides an area of

Interval Estimation of 2

For n - 1 = 10 - 1 = 9 d.f. and a = .05

Selected Values from the Chi-Square Distribution Table


Statistics

Interval Estimation of chi-square distribution that provides an area of 2

n - 1 = 10 - 1 = 9 degrees of freedom and a = .05

Area in Upper

Tail = .025

.025

2

0

19.023

2.700


Interval estimation of 22
Interval Estimation of chi-square distribution that provides an area of 2

  • Sample variance s2 provides a point estimate of  2.

  • A 95% confidence interval for the population variance is given by:

.33 <2 < 2.33


Hypothesis testing about a population variance

where chi-square distribution that provides an area of is the hypothesized value

for the population variance

Hypothesis TestingAbout a Population Variance

  • Left-Tailed Test

  • Hypotheses

  • Test Statistic


Statistics

Reject chi-square distribution that provides an area of H0if

whereis based on a chi-square

distribution withn- 1 d.f.

Hypothesis TestingAbout a Population Variance

  • Left-Tailed Test (continued)

  • Rejection Rule

Critical value approach:

p-Value approach:

Reject H0if p-value<a


Statistics

where chi-square distribution that provides an area of is the hypothesized value

for the population variance

Hypothesis TestingAbout a Population Variance

  • Right-Tailed Test

  • Hypotheses

  • Test Statistic


Statistics

Reject chi-square distribution that provides an area of H0if

whereis based on a chi-square

distribution withn - 1 d.f.

Hypothesis TestingAbout a Population Variance

  • Right-Tailed Test (continued)

  • Rejection Rule

Critical value approach:

RejectH0if p-value<a

p-Value approach:


Statistics

where chi-square distribution that provides an area of is the hypothesized value

for the population variance

Hypothesis TestingAbout a Population Variance

  • Two-Tailed Test

  • Hypotheses

  • Test Statistic


Statistics

Reject chi-square distribution that provides an area of H0if

whereandare based on a

chi-square distribution withn - 1 d.f.

Hypothesis TestingAbout a Population Variance

  • Two-Tailed Test (continued)

  • Rejection Rule

Critical value approach:

p-Valueapproach:

RejectH0ifp-value<a


Hypothesis testing about a population variance1
Hypothesis Testing chi-square distribution that provides an area of About a Population Variance

  • Example: Buyer’s Digest (B)

Recall that Buyer’s Digest is rating

ThermoRite thermostats. Buyer’s Digest

gives an “acceptable” rating to a thermo-

stat with a temperature variance of 0.5

or less.

We will conduct a hypothesis test (with

a= .10) to determine whether the ThermoRite

thermostat’s temperature variance is “acceptable”.


Statistics

Hypothesis Testing chi-square distribution that provides an area of About a Population Variance

  • Example: Buyer’s Digest (B)

Using the 10 readings, we will

conduct a hypothesis test (witha= .10)

to determine whether the ThermoRite

thermostat’s temperature variance is

“acceptable”.

Thermostat1 2 3 4 5 6 7 8 9 10

Temperature67.4 67.8 68.2 69.3 69.5 67.0 68.1 68.6 67.9 67.2


Hypothesis testing about a population variance2
Hypothesis Testing chi-square distribution that provides an area of About a Population Variance

  • Hypotheses

  • Rejection Rule

RejectH0ifc 2>14.684


Statistics

Our value chi-square distribution that provides an area of

Hypothesis TestingAbout a Population Variance

For n - 1 = 10 - 1 = 9 d.f. and a = .10

Selected Values from the Chi-Square

Distribution Table


Statistics

Hypothesis Testing chi-square distribution that provides an area of About a Population Variance

  • Rejection Region

Area in Upper

Tail = .10

2

14.684

0

Reject H0


Hypothesis testing about a population variance3
Hypothesis Testing chi-square distribution that provides an area of About a Population Variance

  • Test Statistic

The sample variances2= 0.7

  • Conclusion

Becausec2= 12.6 is less than 14.684, we cannotrejectH0. The sample variances2= .7 is insufficientevidence to conclude that the temperature variancefor ThermoRitethermostats is unacceptable.


Using excel to conduct a hypothesis test about a population variance
Using Excel to Conduct a Hypothesis Test chi-square distribution that provides an area of about a Population Variance

  • Using the p-Value

  • The rejection region for the ThermoRite

  • thermostat example is in the upper tail; thus, the

  • appropriate p-value is less than .90 (c2 = 4.168)

  • and greater than .10 (c2 = 14.684).

  • Because the p –value > a = .10, we cannot

  • reject the null hypothesis.

  • The sample variance of s2 = .7 is insufficient

  • evidence to conclude that the temperature

  • variance is unacceptable (>.5).


Hypothesis testing about a population variance4
Hypothesis Testing chi-square distribution that provides an area of About a Population Variance

  • Summary


Statistics

Hypothesis Testing About the chi-square distribution that provides an area of Variances of Two Populations

  • One-Tailed Test

  • Hypotheses

Denote the population providing the

larger sample variance as population 1.

  • Test Statistic


Statistics

Hypothesis Testing About the chi-square distribution that provides an area of Variances of Two Populations

  • One-Tailed Test (continued)

  • Rejection Rule

Critical value approach:

Reject H0if F>F

where the value ofFis based on an

Fdistribution withn1- 1 (numerator)

andn2 - 1 (denominator) d.f.

p-Valueapproach:

RejectH0 ifp-value<a


Statistics

Hypothesis Testing About the chi-square distribution that provides an area of Variances of Two Populations

  • Two-Tailed Test

  • Hypotheses

Denote the population providing the

larger sample variance as population 1.

  • Test Statistic


Statistics

Hypothesis Testing About the chi-square distribution that provides an area of Variances of Two Populations

  • Two-Tailed Test (continued)

  • Rejection Rule

Critical value approach:

RejectH0if F>F/2

where the value ofF/2 is based on an

Fdistribution withn1- 1 (numerator)

andn2 - 1 (denominator) d.f.

p-Valueapproach:

RejectH0ifp-value<a


Statistics

F Distribution chi-square distribution that provides an area of


Statistics

F Distribution chi-square distribution that provides an area of

  • Probability density function

  • where


Statistics

F Distribution chi-square distribution that provides an area of

  • mean

  • for d2 > 2

  • Variance

  • ford2 > 2


F distribution with 20 20 degrees of freedom
F chi-square distribution that provides an area of Distribution with (20, 20) Degrees of Freedom


F distribution
F chi-square distribution that provides an area of Distribution

  • Selected Values From the F Distribution Table


F distribution table
F chi-square distribution that provides an area of Distribution Table


Statistics

Hypothesis Testing About the chi-square distribution that provides an area of Variances of Two Populations

  • Example: Buyer’s Digest (C)

Buyer’s Digest has conducted the

same test, as was described earlier, on

another 10 thermostats, this time

manufactured by TempKing. The

temperature readings of the ten

thermostats are listed on the next slide.


Statistics

Hypothesis Testing About the chi-square distribution that provides an area of Variances of Two Populations

  • Example: Buyer’s Digest (C)

We will conduct a hypothesis test with= .10 to see if the variances are equal for ThermoRite’s thermostats and TempKing’s thermostats.


Statistics

Hypothesis Testing About the chi-square distribution that provides an area of Variances of Two Populations

  • Example: Buyer’s Digest (C)

ThermoRite Sample

Thermostat 1 2 3 4 5 6 7 8 9 10

Temperature 67.4 67.8 68.2 69.3 69.5 67.0 68.1 68.6 67.9 67.2

TempKing Sample

Thermostat 1 2 3 4 5 6 7 8 9 10

Temperature 67.7 66.4 69.2 70.1 69.5 69.7 68.1 66.6 67.3 67.5


Statistics

Hypothesis Testing About the chi-square distribution that provides an area of Variances of Two Populations

  • Hypotheses

(TempKing and ThermoRite

thermostats have thesame

temperature variance)

(Their variances are not equal)

  • Rejection Rule

  • TheFdistribution table (on next slide) shows that withwith= .10, 9 d.f. (numerator), and 9 d.f. (denominator),F.05= 3.18.

Reject H0 if F> 3.18


Statistics

Hypothesis Testing About the chi-square distribution that provides an area of Variances of Two Populations

Selected Values from the F Distribution Table


Statistics

= 1.768/.700 = 2.53 chi-square distribution that provides an area of

Hypothesis Testing About theVariances of Two Populations

  • Test Statistic

  • TempKing’s sample variance is 1.768

  • ThermoRite’s sample variance is .700


Statistics

Hypothesis Testing About the chi-square distribution that provides an area of Variances of Two Populations

  • Conclusion

  • We cannot rejectH0. F= 2.53 < F.05= 3.18.

  • There is insufficient evidence to conclude that

  • the population variances differ for the two

  • thermostat brands.


Statistics

Hypothesis Testing About the chi-square distribution that provides an area of Variances of Two Populations

  • Determining and Using the p-Value

Area in Upper Tail .10 .05 .025 .01

FValue (df1 = 9, df2 = 9) 2.44 3.18 4.03 5.35

  • BecauseF= 2.53 is between 2.44 and 3.18, the area

  • in the upper tail of the distribution is between .10

  • and .05.

  • But this is a two-tailed test; after doubling the

  • upper-tail area, thep-valueis between .20 and .10.

  • Becausea= .10, we have p-value > aand therefore

  • we cannot reject the null hypothesis.


Hypothesis testing about the variances of two populations
Hypothesis Testing About the chi-square distribution that provides an area of Variances of Two Populations

  • Summary