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Algebra menu. Order of operations. Formulae. Removing brackets. Factorising. Equations. Inequations. Smithycroft Mathematics. Algebra Menu. Presents. Order of operations. Hands up!. 3 + 5 x 2 ?. 13. B. O. M. D. A. S. A bit of order please!. Brackets. ( 3 + 4 ) x 3. = 7 x 3.

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## Algebra menu

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**Algebra menu**Order of operations Formulae Removing brackets Factorising Equations Inequations**Smithycroft Mathematics**Algebra Menu Presents Order of operations**Hands up!**3 + 5 x 2 ? 13**B**O M D A S A bit of order please! Brackets ( 3 + 4 ) x 3 = 7 x 3 = 21 ( 3 + 4 ) x 3 Of 5 + ½ of 8 = 5 + 4 = 9 5 + ½ of 8 Multiply 3 + 5 x 2 = 3 + 10 = 13 3 + 5 x 2 Divide 18 - 12 ÷ 3 = 18 - 4 = 14 18 - 12 ÷ 3 Add These are the very last things you do! Subtract BOMDAS**BOMDAS Practice**• 3 + 7 x 6 • (2) (3 + 7) x 6 • (3) 32 – 24 ÷ 4 • (4) 5 + 6 x 3 - 1 • (5) 5 + 6 x (3 – 1) = 3 + 42 = 45 = 10 x 6 = 60 = 32 - 6 = 26 = 5 + 18 – 1 = 22 = 5 + 6 x 2 = 5 + 12 = 17**Smithycroft Mathematics**Algebra Menu Presents Formulae**e**f means Algebra Short hand 3a means 3timesa btimesc bc means x² means xtimesx m/k means mdivided byk edivided byf**Formulae (1)**Given that C = s + nr, calculate C when s=12, n=5 and r=8. C = s + nr s n r BOMDAS C = 12 + 5 x 8 5 x 8 M = 52 C = 12 + 40**d**m Given that p = as + d m p = as + Formulae (2) calculate p when a=5, s=9, d=18 and m=6. d m as 18 6 18 6 BOMDAS D M + p = 5 x 9 5 x 9 = 48 p = 45 + 3**Formulae (3)**Given that s = 3t² - 6t + 5 calculate s when t=4. s = 3t² - 6t + 5 3t² 6t BOMDAS 6 x 4 6 x 4 s = 3 x 4 x 4 3x 4 x 4 + 5 - M = 29 s = 48 - 24 + 5**Now do Exercise 1**(HSDU Support Materials))**Smithycroft Mathematics**Algebra Menu Presents Removing Brackets**Removing brackets (1)**b 3(b + 5) = 3b 3 This means 3 times b**Removing brackets (1)**+ 5 3(b + 5) = + 3b 3 15 This means 3 times 5**Removing brackets (2)**5 8 5(8 - f) = 40**Removing brackets (2)**5 - f 5(8 - f) = - 40 5f Tip: Draw lines to keep you right. - 5f 5(8 – f) = 40**Algebra Menu**Now do Exercise 2 Question 1 (HSDU Support Materials))**Removing brackets (3)**3b 4(3b + 2) = 12b 4 4 x 3b = 4 x 3 x b = 12 x b = 12b**Removing brackets (3)**+ 2 4(3b + 2) = + 12b 4 8**Removing brackets (4)**3 7a 3(7a – 2b) = 21a**Removing brackets (4)**- 3 2b 3(7a – 2b) = - 21a 6b**Removing brackets (5)**c 3c c(3c + b) = 3c² c x 3c = 3c x c = 3c²**Removing brackets (5)**c + b c(3c + b) = + 3c² bc Tip: Remember to draw lines to keep you right. + bc c(3c + b) = 3c²**Removing brackets (6)**6 5e 6(5e + 3f - 2) = 30e**Removing brackets (6)**6 + 18f 3f 6(5e + 3f - 2) = 30e**Careful!**Removing brackets (6) 6 + 18f - 12 2 6(5e + 3f - 2) = 30e Tip: Remember to draw lines to keep you right. + 18f - 12 6(5e + 3f -2) = 30e**Algebra Menu**Now do Exercise 2 Questions 2 & 3 (HSDU Support Materials))**Simplifying (1)**4 3a 4(3a + 5) - 8 = 12a**This is not inside the brackets**So don’t multiply! Simplifying (1) 4 +20 5 -8 4(3a + 5) - 8 = 12a**Simplifying (1)**+20 -8 4(3a + 5) - 8 = 12a This can be tidied up = 12a + 12**This is not inside the brackets**So don’t multiply! Simplifying (2) 2 5b 3b + 2(5b – 6) = 3b + 10b**Careful!**Simplifying (2) 2 6 -12 3b + 2(5b – 6) = 3b + 10b**Simplifying (2)**-12 3b + 2(5b – 6) = 3b + 10b This can be tidied up = 13b - 12**Algebra Menu**Now do Exercise 2 Questions 4, 5. (HSDU Support Materials))**Smithycroft Mathematics**Algebra Menu Presents Factorising**Factorising (1)**? 2 4 4a – 6b = 6 What’s the highestnumber that will divide into both 4 and 6? This is called the highest common factor**Factorising (1)**( ) ? 2a 2 2 4a 4a – 6b =**Factorising (1)**( ) ? 2a 3b - 2 2 6b 4a – 6b =**Factorising (1)**( ) 2a 3b - 2 4a – 6b =**Factorising (2)**? b b 3b + bc = b What’s the highestcommon factor? This time it’s the letter b that they have in common.**Factorising (2)**( ) ? 3 b b 3b 3b + bc =**Factorising (2)**( ) ? 3 c + b b bc 3b + bc =**Factorising (2)**( ) ? 3 c + b 3b + bc =**Factorising (3)**f ? 3 6f 6 6f + 9gf = 9gf 9 What’s the highestcommon factor? 3 divides into 6 and 9. Notice that the letter f is also common to both.**Factorising (3)**( ) f ? 2 3 6f 6f + 9gf =**Factorising (3)**( ) f ? + 3g 2 3 9gf 6f + 9gf =**Factorising (3)**( ) f + 3g 2 3 6f + 9gf =**Algebra Menu**Now do Exercise 3 (HSDU Support Materials))**Smithycroft Mathematics**Equations Algebra Menu Presents

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