1 / 16

Mastering Scientific Notation in Essential Chemistry Math

Understand how scientific notation works in chemistry, express very large or small numbers and precision. Learn to convert numbers to standard form and use scientific notation effectively. Practice calculations and ensure correct significant figures in your answers. Discover the right way to use the Exponent Key (EE, EXP) on your calculator. Dive into essential math concepts for chemistry, including units, separation of variables, and solving equations. Hone your skills through numerical examples and practical problem-solving scenarios.

tashya-mckenzie
Download Presentation

Mastering Scientific Notation in Essential Chemistry Math

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Essential Math of Chemistry

  2. Scientific Notation -- used to express very large or very small numbers, and/or to indicate precision Form: (# from 1 to 9.999) x 10exponent 800 = 8 x 10 x 10 = 8 x 102 2531 = 2.531 x 10 x 10 x 10 = 2.531 x 103 0.0014 = 1.4 101010 = 1.4 x 10–3 (i.e., to maintain the correct number of significant figures)

  3. Put in standard form. 1.87 x 10–5 = 0.0000187 3.7 x 108 = 370,000,000 7.88 x 101 = 78.8 2.164 x 10–2 = 0.02164 Change to scientific notation. 12,340 = 1.234 x 104 0.369 = 3.69 x 10–1 0.008 = 8 x 10–3 1,000,000,000 = 1 x 109 6.02 x 1023 = 602,000,000,000,000,000,000,000

  4. Using the Exponent Key EE EXP

  5. The EE or EXP or E key means “times 10 to the…” 6 6 6 6 6 1 1 0 0 0 0 0 0 0 x x y x EE EE EE y x 2 2 2 2 2 2 2 2 2 2 3 3 3 3 3 . . . . . How to type out 6.02 x 1023: How to type out 6.02 x 1023: not… WRONG! WRONG! or… and not… TOO MUCH WORK.

  6. Also, know when to hit your (–) sign. (before the number, after the number, or either one)

  7. Type this calculation in like this: 1.2 x 105 2.8 x 1019 1 2 Calculator gives… 4.2857143 –15 9 1 8 2 5 or… 4.2857143 E–15 EE EE This is NOT written… 4.3–15 . . = 4.3 x 10–9 or 4.3 E –9 But instead is written…

  8. 5.76 x 10–16 9.86 x 10–4 = –6.5 x 10–19 7.5 x 10–6 (–8.7 x 10–14) = 5.35 x 103 or 5350 4.35 x 106 (1.23 x 10–3) = 5.84 x 10–13 8.8 x 1011 x 3.3 x 1011 = 2.9 x 1023

  9. Essential Mathof Chemistry

  10. Units must be carried into the answer, unless they cancel. 5.2 kg (2.9 m) 4.8 kg (23 s) kg-m = = (18 s)(1.3 s) (18 s)(37 s) s2 kg s 0.64 0.57

  11. Solve for x. x + y = z x and y are connected by addition. Separate them using subtraction. In general, use opposing functions to separate things. x + y = z – y – y The +y and –y cancel on the left, x = z – y leaving us with…

  12. Solve for x. Numerical Example x – 24 = 13 x and 24 are connected by subtraction. Separate them using the opposite function: addition. x – 24 = 13 +24 +24 The –24 and +24 cancel on the left, x = 37 leaving us with…

  13. Solve for x. F = k x __ F x = k k k (or) F = k x ( ( ) ) __ __ 1 1 k k F = k x x and k are connected by multiplication. Separate them using the opposite function: division. The two k’s cancel on the right, leaving us with…

  14. Numerical Example Solve for x. 8 = 7 x 7 7 (or) 8 = 7 x __ 8 ( ( ) ) __ __ 1 1 x = 7 7 7 8 = 7 x x and 7 are connected by multiplication. Separate them using the opposite function: division. The two 7’s cancel on the right, leaving us with…

  15. Solve for x. ( ( ) ) BAH ___ ___ BA ___ ___ 1 1 ___ TR x = = x TR TR TR H One way to solve this is to cross-multiply. BAH = xTR Then, divide both sides by TR. BAH = xTR The answer is…

  16. Solve for T2, where… P1 = 1.08 atm P2 = 0.86 atm V1 = 3.22 L V2 = 1.43 L T1 = 373 K P1V1 P2V2 ____ = ____ T1 T2 P2V2T1 ______ T2 = P1V1 ( ( ) ) ____ ____ 1 1 (0.86 atm)(1.43 L)(373 K) _____________________ T2 = P1V1 P1V1 = (1.08 atm)(3.22 L) P1V1T2 = P2V2T1 132 K

More Related