120 likes | 283 Views
The action potential: a review in 12 slides. A neuronal cell at rest. _-60_ mV. Ligand -gated Na + channel (for example). Voltage -gated Ca ++ channel. Ligand binds to the receptor and opens the channel. Sodium rushes in Close to the receptor.
E N D
The action potential: a review in 12 slides A neuronal cell at rest _-60_ mV Ligand-gated Na+ channel (for example) Voltage-gated Ca++ channel Ligand binds to the receptor and opens the channel Sodium rushes in Close to the receptor
K+ Cl- Na+ Cl- K+ Cl- Na+ Cl- Cl- K+ Cl- Na+ Cl- K+ Cl- Na+ Stage 1: an equal distribution of + and - ions across the membrane. Lipid bilayer 0 mV K+ Cl- Na+ Cl- K+ Cl- Na+ Cl- Cl- K+ Cl- Na+ Cl- K+ Cl- Na+ Na+ Cl- Na+ Cl- Na+ Cl- Na+ Cl- Cl- Na+ Cl- Na+ Cl- K+ Cl- Na+ Stage 2: The Na+/K+ antiporter kicks in and exchanges Na for K (assume 1:1 for demonstration purposes here). Na+/K+ 0 mV K+ Cl- K+ Cl- K+ Cl- Na+ Cl- Cl- K+ Cl- K+ Cl- K+ Cl- K+ This runs continuously
Na+ Cl- Na+ Cl- Na+ Cl- Na+ Cl- Cl- Na+ Cl- Na+ Cl- K+ Cl- Na+ Stage 3a: K+ leak channels open up and potassium flows outside the cell (before view). Na+/K+ K+ 0 mV K+ Cl- K+ Cl- K+ Cl- K+ Cl- Cl- K+ Cl- K+ Cl- Na+ Cl- K+ Na+ Cl- Na+ Cl- Na+ Cl- Na+ Cl- Cl- Na+ Cl- Na+ Cl- K+ Cl- Na+ K+ K+ K+ K+ K+ K+ Stage 3b: K+ leak channels open up and potassium flows outside the cell (after view). Na+/K+ K+ -60 mV Cl- Cl- Cl- Cl- Cl- Cl- Cl- K+ Cl- K+ Cl- K+ Cl- K+ This runs continuously
Na+ Cl-Na+ Cl- K+ Cl-Na+ Cl- Cl-Na+ Cl-Na+ Cl- Na+ Cl-Na+ K+ K+ K+ K+ K+ K+ Stage 4a: Ligand-gated sodium channel opens when ligand binds; Na+ flows into cell near the receptor site Na+/K+ K+ -60 mV Cl- Cl- Cl- Cl- Cl- Cl- Cl- K+ Cl-Na+ Cl- K+ Cl- K+ Cl- Cl- Cl- Cl- Cl-Na+ Cl-Na+ Cl- K+ Cl-Na+ K+ K+ K+ K+ K+ K+ Stage 4b: Na+ influx depolarizes the cell (more positive on the inside now) Na+/K+ K+ +40 mV Cl-Na+ Cl- Na+ Cl-Na+ Cl- Cl- Na+ Na+ Na+ Na+ Na+ Na+ Na+ Cl- K+ Cl- K+ Cl-Na+ Cl- K+
Cl- Cl- Cl- Cl- Cl-Na+ Cl-Na+ Cl- K+ Cl-Na+ K+ K+ K+ K+ K+ K+ Stage 4b: Remember that the Na/K anti- porter is on the job!!! what happens? Why is the voltage now positive? Na+/K+ K+ +40 mV Cl-Na+ Cl- Na+ Cl-Na+ Cl- Cl- Na+ Na+ Na+ Na+ Na+ Na+ Na+ Cl- K+ Cl- K+ Cl-Na+ Cl- K+ Stage 2: The Na+/K+ antiporter kicks in and exchanges Na for K (actually moves 3Na+ out to 2K+ in) (ACTIVE transport) K+ leak channel re-sets the voltage (-60 mV) Na+ Cl- Na+ Cl- Na+ Cl- Na+ Cl- Cl- Na+ Cl- Na+ Cl- K+ Cl- Na+ Na+/K+ K+ Cl- K+ Cl- K+ Cl- Na+ Cl- Cl- K+ Cl- K+ Cl- K+ Cl- K+ This runs continuously
Voltage redux: assume 1+ unit here = 10 mV K+ Cl- Na+ Cl- K+ Cl- Na+ Cl- Cl- K+ Cl- Na+ Cl- K+ Cl- Na+ Stage 1: an equal distribution of + and - ions across the membrane. Lipid bilayer 0 mV K+ Cl- Na+ Cl-K+Cl-Na+ Cl- Cl- K+ Cl- Na+ Cl- K+ Cl- Na+ K+ Cl- Na+ Cl- K+ Cl- Na+ Cl- Cl- K+ Cl- Na+ Cl- K+ Cl- Na+ K+ Stage 2: A single K+ Moves outside with No accompanying Cl- Lipid bilayer -10 mV Cl- K+ Cl- Na+ Cl-Na+ Cl- Cl- K+ Cl- Na+ Cl- K+ Cl- Na+
Voltage redux: assume 1+ unit here = 10 mV K+ Cl- Na+ Cl- K+ Cl- Na+ Cl- Cl- K+ Cl- Na+ Cl- K+ Cl- Na+ K+K+ Stage 3: a second K+ moves outside the cell without an accompanying charge. -20 mV Lipid bilayer Cl- Cl- K+ Cl- K+ Cl-Na+ Cl- Cl- K+ Cl- K+ Cl- Na+ K+ Cl- Na+ Cl- K+ Cl- Na+ Cl- Cl- K+ Cl- Na+ Cl- K+ Cl- Na+ K+K+K+K+K+K+K+ Stage 4: A six K+ move outside with no accompanying Cl- -60 mV Lipid bilayer Cl-Cl-Cl-Cl-Cl-Cl-Cl- Na+ Cl- Cl- Na+
Voltage redux: assume 1+ unit here = 10 mV K+ Cl-Na+ Cl- K+ Cl-Na+ Cl- Cl-Na+ Cl-Na+Cl- K+ Cl-Na+ K+K+K+K+K+K+K+ Stage 5: Note the Na+ gradient. Opening a ligand-gated sodium channel can destroy the voltage (and beyond) (Does K+ move?) -60 mV Lipid bilayer Cl-Cl-Cl-Cl-Cl-Cl-Cl- Na+ Cl- Cl- Na+ Under this scheme, how many Na+ must enter the cell to make it 0 mV? make it +40 mV? What would happen to the above diagram if 3 Cl- moved in? if 1 Cl- moved out?
Voltage redux: assume 1+ unit here = 10 mV K+ Cl-Na+ Cl- K+ Cl-Na+ Cl- Cl-Na+ Cl-Na+Cl- K+ Cl-Na+ K+K+K+K+K+K+K+ Stage 5: Note the Na+ gradient. Opening a ligand-gated sodium channel can destroy the voltage (and beyond) (Does K+ move?) -60 mV Lipid bilayer Cl-Cl-Cl-Cl-Cl-Cl-Cl- Na+ Cl- Cl- Na+ Under this scheme, how many Na+ must enter the cell to make it +40 mV? Ten! Six would make it zero mV, while four more get you to +40 mV What would the voltage become if 3 Cl- moved in? -90 mV if 1 Cl- moved out? -50 mV
A neuronal cell at rest _-60_ mV Ligand-gated Na+ channel Voltage-gated Ca++ channel Ligand binds to the receptor and opens the channel Sodium rushes in near the receptor
Propagation of a voltage along the axon as a function of time The -60 mV resting potential is destroyed directionally from the site of the input signal to the end of the neuron.