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Gauss’s Law. What does it mean?. How do we use it?. Dominic Berry University of Waterloo. Griffith University 8 February, 2011. What does it mean?. First we need the concept of flux. Area A. Electric field. Area A. What does it mean?. First we need the concept of flux.
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Gauss’s Law What does it mean? How do we use it? Dominic Berry University of Waterloo Griffith University 8 February, 2011
What does it mean? • First we need the concept of flux. Area A
Electric field Area A What does it mean? • First we need the concept of flux.
What does it mean? • First we need the concept of flux. Electric field Area A Flux is just electric field times area
What does it mean? • First we need the concept of flux. If electric field does not pass through the area, flux is zero.
What does it mean? • First we need the concept of flux. In general we use a normal vector to the plane, .
What does it mean? • First we need the concept of flux. For more general angles the flux varies as cos.
What does it mean? • First we need the concept of flux. For more general angles the flux varies as cos.
What does it mean? • The total flux through a closed surface.
What does it mean? • The total flux through a closed surface. • We use the convention that the normal always points outward.
What does it mean? • The total flux through a closed surface. • We use the convention that the normal always points outward.
What does it mean? • The total flux through a closed surface. • We use the convention that the normal always points outward. • For the four sides,
What does it mean? • The total flux through a closed surface. • We use the convention that the normal always points outward. • For the four sides, • For the top,
What does it mean? • The total flux through a closed surface. • We use the convention that the normal always points outward. • For the four sides, • For the top, • For the bottom,
What does it mean? • The total flux through a closed surface. • We use the convention that the normal always points outward. • For the four sides, • For the top, • For the bottom, • The total flux is
What does it mean? • What does the integral mean? • The circle indicates an integral over the closed surface.
What does it mean? • What does the integral mean? • The circle indicates an integral over the closed surface. • In practice we will not have to evaluate the interval.
What does it mean? • What does the integral mean? • The circle indicates an integral over the closed surface. • In practice we will not have to evaluate the interval. • We break the surface up into sections where the flux is easy to calculate.
What does it mean? • What does the integral mean? • The circle indicates an integral over the closed surface. • In practice we will not have to evaluate the interval. • We break the surface up into sections where the flux is easy to calculate. In principle sum over infinitesimal elements .
What does it mean? • The full Gauss’s law. • The left side is the total flux out through the surface.
What does it mean? • The full Gauss’s law. • The left side is the total flux out through the surface. • The right side is proportional to the charge, q, inside the surface. +q
What does it mean? • The full Gauss’s law. • The left side is the total flux out through the surface. • The right side is proportional to the charge, q, inside the surface. • The constant, 0, is the usual vacuum permittivity. +q
How do we use it? • For example, consider a charge +q. +q r
How do we use it? • For example, consider a charge +q. • We choose a spherical surface. +q r
How do we use it? • For example, consider a charge +q. • We choose a spherical surface. • By spherical symmetry the electric field must be directed radially outwards. +q r
How do we use it? • For example, consider a charge +q. • We choose a spherical surface. • By spherical symmetry the electric field must be directed radially outwards. • The magnitude of the electric field must be constant on the surface. +q r
How do we use it? • For example, consider a charge +q. • We choose a spherical surface. • By spherical symmetry the electric field must be directed radially outwards. • The magnitude of the electric field must be constant on the surface. • The flux is just EA. +q r
How do we use it? • For example, consider a charge +q. • We choose a spherical surface. • By spherical symmetry the electric field must be directed radially outwards. • The magnitude of the electric field must be constant on the surface. • The flux is just EA. • Gauss’s law gives +q r
How do we use it? • For example, consider a charge +q. • We choose a spherical surface. • By spherical symmetry the electric field must be directed radially outwards. • The magnitude of the electric field must be constant on the surface. • The flux is just EA. • Gauss’s law gives +q r
How do we use it? • For example, consider a charge +q. • We choose a spherical surface. • By spherical symmetry the electric field must be directed radially outwards. • The magnitude of the electric field must be constant on the surface. • The flux is just EA. • Gauss’s law gives +q r
How do we use it? • Consider a shell of charge +q. • We choose a spherical surface. • By spherical symmetry the electric field must be directed radially outwards. • The magnitude of the electric field must be constant on the surface. • The flux is just EA. • Gauss’s law gives +q r
How do we use it? • Consider a shell of charge +q. • We choose a spherical surface. • By spherical symmetry the electric field must be directed radially outwards. • The magnitude of the electric field must be constant on the surface. • The flux is just EA. • Gauss’s law gives +q r
How do we use it? General procedure: • Choose a surface corresponding to the symmetry of the problem. • Break the surface up into subsurfaces where the electric field is either • constant and parallel to the normal, or • perpendicular to the normal. • Evaluate the total flux using the electric field as a free parameter. • Solve Gauss’s law for E. +q r http://www.dominicberry.org/presentations/gauss.ppt