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a[(sD an[ b[ez

a[(sD an[ b[ez. a[(sD-b[ez tTAY)krN bfr a[(sD-b[ez an&mipn. tTAY)krNn) p(kyi. jyir[ a[(sD an[ b[ezmi> a[ksrKi pmiNmi hieD^i[jn aiyn H + an[ hieD^i[ksieD aiyn OH - B[gi krvimi> aiv[ C[ Ryir[ mLt&> WivN tTAY hi[y C[. NaOH (aq) + HCl(aq) NaCl + H 2 O

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a[(sD an[ b[ez

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  1. a[(sD an[ b[ez a[(sD-b[ez tTAY)krN bfr a[(sD-b[ez an&mipn

  2. tTAY)krNn) p\(k\yi jyir[ a[(sD an[ b[ezmi> a[ksrKi p\miNmi hieD^i[jn aiyn H+an[ hieD^i[ksieD aiyn OH- B[gi krvimi> aiv[ C[ Ryir[ mLt&> WivN tTAY hi[y C[. NaOH (aq) + HCl(aq) NaCl + H2O b[eza[(sDxirpiN) Ca(OH)2 + 2 HCl CaCl2 + 2H2O b[eza[(sDxirpiN)

  3. tTAY)krN • H3O+an[ OH- aiyni[ B[gi Yen[ piN) bniv[ C[. H3O+ + OH- 2 H2O a[(sD mi>Y) b[ez mi>Y)tTAY a>(tm aiyn)k sm)krN: H+ + OH- H2O

  4. tTAY)krN miT[n& aiyn)k sm)krN aiyn Av$p[ p\bL a[(sD, b[ez an[ xir lKi[ H+ + Cl- + Na+ + OH- Na+ + Cl- + H2O a[k srKi aiyni[n[ bid kri[. H+ + Cl-+ Na+ + OH-Na+ + Cl- + H2O a>(tm aiyn)k sm)krN H+ + OH-H2O

  5. tTAY)krNni sm)krNn&> s>t&ln m[³n[S)ym hieD^i[ksieD an[ nieT^)k a[(sD vµc[ Yti tTAY)krN miT[n&> sm)krN lKi[. 1. a[(sD an[ b[ez ni s*#i[i lKi[. Mg(OH)2 + HNO3 2.OH-an[ H+ aiynn) s>²yi a[ksrK) Yiy t[ r)t[ s>t&(lt kri[ Mg(OH)2 + 2 HNO3

  6. 3. upj lKi[ : Mg(OH)2 + 2HNO3 Mg(NO3)2 + H2O xirpiN) (Fit& an[ aFit&) 4. upjn[ s>t&(lt kri[ Mg(OH)2 + 2 HNO3 Mg(NO3)2 + 2 H2O

  7. udihrN - 1 yi[³y g&Ni>k vD[ n)c[ aip[l tTAY)krNni sm)krNi[n[ s>t&(lt kri[. A. __ HCl + __ Al(OH)3 __AlCl3 + __ H2O 1) 1, 3, 3, 1 2) 3, 1, 1, 1 3) 3, 1, 1 3 B.__ Ba(OH)2 + __H3PO4 __Ba3(PO4)2 + __ H2O 1) 3, 2, 2, 2 2) 3, 3, 1, 6 3) 2, 3, 1, 6

  8. uk[l - 1 A. 3HCl + 1Al(OH)31AlCl3 + 3H2O B. 3Ba(OH)2 + 2H3PO41Ba3(PO4)2 + 6H2O

  9. udihrN - 2 s>t&l)t sm)krN lKi[ an[ 50.0 mL ni 1.00 M KOH n[ tTAY krvi miT[ k[Tli m)l) l)Tr 2.00 M H2SO4ji[ea[ t[ gNi[. ___H2SO4 + ___KOH ___K2SO4 + H2O 1) 12.5 mL 2) 50.0 mL 3) 200. mL

  10. uk[l -2 50.0 mL 1.00 M KOH n[ tTAYkrvimiT[ k[Tli m)l). 2.00 M H2SO4 ji[ea[? H2SO4 + 2KOH K2SO4 + 2H2O 0.0500 L x 1.00 mole KOH x 1 mole H2SO4 x 1 L 2 mole KOH 1 L x 1000 mL = 12.5 mL 2 mole KOH 1 L

  11. udihrN -3 25 mL fi[Afi[r)k a[(sD n[ 40. mL ni 1.5 M NaOH vD[ tTAY krvimi> aiv[ C[. ti[ fi[Afi[r)k a[(sD ni WivNni[ aN&Bir Si[Fi[. 3NaOH + H3PO4 Na3PO4 + 3H2O 1) 0.45 M 2) 0.80 M 3) 7.2 M

  12. uk[l - 3 0.040 L x 1.5 mole NaOH x 1 mole H3PO4 1 L3 mole NaOH x 1 = 0.80 mol/L = 0.80 M 0.025 L

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