90 likes | 215 Views
Learn how to handle noncircular conduits in fluid mechanics by modifying the head loss formula and applying the Manning Equation for uniform flow in open channels. Calculate velocity and flow rate in specific scenarios.
E N D
CE 230-Engineering Fluid Mechanics Lecture # 33-34 Noncircular conduits Uniform flow in open channels
If the conduit is not circular then we should do the following Replace D in head loss formula by 4A/P=4Rh Relative roughness = ks/4Rh Re=V(4Rh)/ν Then continue as before
Uniform flow in open channels • For this flow the deriving force is gravity which means that the channel has to be sloping in the flow direction • An empirical equation is used to analyze this type of flow which is called the MANNING EQUATION
terminology A area P wetted perimeter Hydraulic radius = A/P Manning Equation SI units B. units
10.128 Find average velocity in the shown concrete lined channel if the Slope is 1 ft in 2000 ft. The depth of flow is 6 ft.
Example 10.21 “modified” Determine Q if D= 5 ft, slope =0.001, flow depth = 4 ft Concrete sewer