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Perilune altitude - PowerPoint PPT Presentation

Sketch the parabola. 4y + x 2 = 0

1. 2. 3. 4. Sketch the parabola. 4y + x 2 = 0. {applet} {applet} {applet} {applet}. 1. 2. 3. 4. Find an equation for the conic that satisfies the given conditions. Parabola, vertical axis, passing through ( - 2, 3), (0, 3), and (1, 12). x 2 + y 2 = 3y 3x 2 + 6x + 3 = y y 2 = - 6x

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Perilune altitude - PowerPoint PPT Presentation

Sketch the parabola. 4y + x 2 = 0