'Kj kg k' presentation slideshows

Chapter 3 The First Law of Thermodynamics: Closed System

Chapter 3 The First Law of Thermodynamics: Closed System. 3-1 Introduction To The First Law of Thermodynamics. 3-1-1 Conservation of energy principle Energy can be neither created nor destroyed;it can only change forms.

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Isentropic Efficiencies of Turbines, Compressors and Nozzles

Isentropic Efficiencies of Turbines, Compressors and Nozzles. Lecture # 28 Nov. 3, 08. Announcements. Midterm-II: Friday, Nov. 7 th , 11 am, in class 10 problems from Chapters 4,5,6 4 from Ch. 4, 2 from Ch.5, 4 from Ch. 6

1.38k views • 24 slides

Isentropic Efficiencies of Turbines, Compressors and Nozzles

Isentropic Efficiencies of Turbines, Compressors and Nozzles. Lecture # 28 Nov. 3, 08. Announcements. Midterm-II: Friday, Nov. 7 th , 11 am, in class 10 problems from Chapters 4,5,6 4 from Ch. 4, 2 from Ch.5, 4 from Ch. 6

1.83k views • 24 slides

Plasma gasification of Municipal Solid Waste

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ENGR 2213 Thermodynamics

ENGR 2213 Thermodynamics. F. C. Lai School of Aerospace and Mechanical Engineering University of Oklahoma. Increase-in-Entropy Principle. Closed systems. ? S total = ? S system + ? S surroundings ? 0. Example 1. Water in a tank, initially a saturated liquid at

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Entropy Change

T. S. Entropy Change. Property diagrams (T-s and h-s diagrams) from the definition of the entropy, it is known that ?Q=TdS during a reversible process. The total heat transfer during this process is given by Q reversible = ? TdS

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Entropy Change

T. S. Entropy Change. Property diagrams (T-s and h-s diagrams) from the definition of the entropy, it is known that ?Q=TdS during a reversible process. The total heat transfer during this process is given by Q reversible = ? TdS

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Heat Retention Of Liquids

Heat Retention Of Liquids. Jossette Quezada . Research.

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INTERNAL COMBUSTION ENGINES (reciprocating)

INTERNAL COMBUSTION ENGINES (reciprocating). Geometry. Four Stroke Engines. Two Stroke Engines. For Isentropic Process. Air as an ideal gas ( room temp .). PV = mRT. C p = 1.005 [kJ/kg K]. C v = 0.718 [kJ/kg K]. R = C p - C v = 0.287 [kJ/kg K]. k = (C p / C v ) = 1.4.

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Entropy of a Pure Substance

P = const. v = const. T. s (kJ/kg). Entropy of a Pure Substance. Entropy is a thermodynamic property, the value of entropy depends on the state of the system. For example: given T & P, entropy, S, can be obtained from a thermodynamic table just like v, u, h.

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