'Hg2br2 g' presentation slideshows

In the same manner g AlCl 3 = g Al ( FW AlCl 3 /at wt Al) g FeCl 3 + g AlCl 3 = 5.95

What weight of sulfur (FW = 32.064) ore which should be taken so that the weight of BaSO 4 (FW = 233.40) precipitate will be equal to half of the percentage sulfur in the sample. Solution S D BaSO 4 mmol S = mmol BaSO 4 mg S/at wt S = mg BaSO 4 /FW BaSO 4

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