'Finite languages' presentation slideshows

Proof . To prove subset relation we need to show that

Theorem 2 . Let A , B and C be sets of strings. Then ( A ? B )? C ? A ? C ? B ? C. Proof . To prove subset relation we need to show that for any string w, w ? ( A ? B )? C ? w ? A ? C ? B ? C. Why not to prove A ? C ? B ? C ? ( A ? B )? C as well?.

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Complexity and Computability Theory I

Complexity and Computability Theory I. Lecture #7 Instructor: Rina Zviel-Girshin Leah Epstein. Overview. Nonregular languages The pumping lemma Examples. Are all languages regular?. No. Most of the languages are not regular. Why? A finite automaton has limited memory. Example.

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Strings

Strings. A string over a set A is a finite sequence of elements from A. The set of elements from which the strings are built is called an alphabet. Definition . An alphabet is a nonempty, finite set of indivisible symbols. We are going to denote it by ?.

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MA/CSSE 474

MA/CSSE 474. Theory of Computation. Languages, prefixes, sets, cardinality, functions. Your Questions?. Syllabus Tuesday's discussion Reading Assignments HW1 or HW2 Anything else. Must not be a FSM. More about Languages and Strings.

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Lecture 3

Lecture 3. Topics Languages Language classes Closure properties. In class reading assignment. Read Section 1.5 (pages 27-30) and answer the following questions What is a language? What is L ? What is {aa,bb}{cc,dd}? What is {aa,bb} 2 ? What are the five shortest strings in {aa,bb} * ?

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Chapter 4: Regular Expressions

Chapter 4: Regular Expressions. A new method to define languages alphabet  language S = {x} S* = { Λ , x, xx, xxx, …} or directly {x}* = { Λ , x, xx, xxx, …} language  language S = {xx, xxx} S * = { Λ , xx, xxx, xxxx, …}

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Non-Regular Languages

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Regular Languages and Finite Automata

Regular Languages and Finite Automata. Devising DFAs/NFAs. Devise DFAs/NFAs for the following languages:. True or False?. If L is a nonregular language and M is a regular language then their concatenation LM is not regular. All finite languages L are regular. Closure Properties.

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Recap lecture 6

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