EQUIVALENT FORCE-COUPLE SYSTEMS. Section’s Objectives : Students will be able to: 1) Determine the effect of moving a force. 2) Find an equivalent force-couple system for a system of forces and couples. In-Class Activities : Check homework, if any Reading quiz

ByProblem 5.147. y. 20 mm. 30 mm. Locate the centroid of the plane area shown. 36 mm. 24 mm. x. y. Problem 5.147. 20 mm. 30 mm. Locate the centroid of the plane area shown. 36 mm. 24 mm. x. 1. Decide how to construct the given area from common shapes .

ByREDUCTION OF DISTRIBUTED LOADING (Section 4.10). Today’s Objectives : Students will be able to determine an equivalent force for a distributed load. In-Class Activities : Check homework, if any Reading quiz Applications Equivalent force Concept quiz Group problem solving

ByC. b. B. P. a. 300 mm. A. 200 mm. Problem 3.154. The force P has a magnitude of 250 N and is applied at the end C of a 500 mm rod AC attached to a bracket at A and B . Assuming a = 30 o and b = 60 o , replace P with (a) an equivalent force-couple

ByPosition Vectors. The position vector r is defined as a fixed vector which locates a point in space relative to another point. r = x i + y j + z k. z. zk. P(x,y,z). r AB A = from point B = to point r OA =r A. r. yj. y. O. xi. x. Position Vectors. r A + r = r B

ByForce-Couple Systems. Force – Couple Systems = Reduction of a Force to an Equivalent Force and Moment (Moving a Force to Another Point) The force acting on a body has two effects:

ByRESULTANTS. Force – Couple Systems = Reduction of a Force to an Equivalent Force and Moment (Moving a Force to Another Point) The force acting on a body has two effects:

ByRigid Bodies: Equivalent Systems of Forces. Introduction. Treatment of a body as a single particle is not always possible. In general, the size of the body and the specific points of application of the forces must be considered.

ByENGI 1313 Mechanics I . Lecture 22: Equivalent Force Systems and Distributed Loading. Lecture 22 Objective. to demonstrate by example equivalent force systems to determine an equivalent force for a distributed load. Example 22-01.

ByREDUCTION OF A SIMPLE DISTRIBUTED LOADING. Today’s Objectives : Students will be able to determine an equivalent force for a distributed load. In-Class Activities : Check Homework Reading Quiz Applications Equivalent Force Concept Quiz Group Problem Solving Attention Quiz. =.

ByLecture #8. Distributed Loads Reference Chapter 4, Section 9. 1. The resultant force (F R ) due to a distributed load is equivalent to the _____ under the distributed loading curve, w = w(x). A) Centroid B) Arc length C) Area D) Volume. Distributed load curve. w. x. F. R.

ByRESULTANTS. Force – Couple Systems = Reduction of a Force to an Equivalent Force and Moment (Moving a Force to Another Point) The force acting on a body has two effects:

ByRigid Bodies: Equivalent Systems of Forces. Introduction. Treatment of a body as a single particle is not always possible. In general, the size of the body and the specific points of application of the forces must be considered.

ByForces and Moments MET 2214. Moments and Forces. Part 5. Equivalent system. An equivalent system is: A system in which forces and couple moments acting on a body are simplified to a single resultant force and couple moment acting at a specified point O.

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