'2x 1 5' presentation slideshows

5.1 and 5.2 Midsegments and Bisectors of Triangles

5.1 and 5.2 Midsegments and Bisectors of Triangles. Lets look at some formulas first. Slope:. y 2 -y 1. x 2 -x 1. Midpoint:. Distance:. Find the midpoint between two points. (0.45,7) and (-0.3,-9). (. ). -0.3. + 0.45. + 7. -9. ,. 2. 2. (0.075,-1).

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5.1 Midsegments of Triangles

5.1 Midsegments of Triangles. Chapter 5 Relationships Within Triangles. 5.1 Midsegments of Triangles. Theorem 5-1 Triangle Midsegment Theorem If a segment joins the midpoints of two sides of a triangle, then the segment is parallel to the third side, and is half of its length. Midsegment.

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Inverse of Functions

Inverse of Functions. Finding the inverse of functions Finding the inverse function. Inverse Functions. Functions f and g are inverse functions if: - f(g(x)) = x - g(f(x)) = x For all values of x in the domain of f and g. Finding the Inverse of a Function by Reversing Operations.

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LATIHAN SOAL & PENYELESAIANNYA (Persamaan dan Pertidaksamaan di Ruang Satu dengan Satu Variabel)

LATIHAN SOAL & PENYELESAIANNYA (Persamaan dan Pertidaksamaan di Ruang Satu dengan Satu Variabel). Disusun oleh : KARLINA SARI (4101412031) ALIFA MUHANDIS S A (4101412084) RIA WINARTI NINGRUM (4101412180) TASBIATUN (4101412 ). -5. 5. 0.

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LATIHAN SOAL & PENYELESAIANNYA (Persamaan dan Pertidaksamaan di Ruang Satu dengan Satu Variabel)

LATIHAN SOAL & PENYELESAIANNYA (Persamaan dan Pertidaksamaan di Ruang Satu dengan Satu Variabel). Disusun oleh : KARLINA SARI (4101412031) ALIFA MUHANDIS S A (4101412084) RIA WINARTI NINGRUM (4101412180) TASBIATUN (4101412 ). -5. 5. 0.

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1-4 Solving Inequalities

1-4 Solving Inequalities. Big Idea: -Solve equations and inequalities. Solving and Graphing Inequalities. As with an equation, the solutions of an inequality are the numbers that make it true. The properties for solving inequalities are similar to the properties for solving equations.

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Chapter 27

? ? ? ?. Chapter 27. ????? Unsteady-state Mass Transfer. ? ? ? ?. Unsteady-state Mass Transfer. ??? ( ? x* ? y* ? z ) ???? ??? t ??? C A ??? dt ? ?? t+dt ??? C A +dC A ??????? = ? x* ? y* ? z = ( N A in - N A out )* ? y* ? z. Fick ????. A.

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