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What is the coefficient for CO when the following equation is balanced with the smallest whole number coefficients? Fe2O

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## What is the coefficient for CO when the following equation is balanced with the smallest whole number coefficients? Fe2O

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**What is the coefficient for CO when the following equation**is balanced with the smallest whole number coefficients? Fe2O3 + CO {image} CO2 + Fe • 5 • 6 • 3 • 4 • 1**Balance the following equation with the smallest whole**number coefficients. Choose the answer that is the sum of the coefficients in the balanced equation. Do not forget coefficients of "one". C5H6NS + O2 {image} CO2 + H2O + NO2 + SO2 • 33 • 35 • 37 • 39 • 41**Balance the following equation with the smallest whole**number coefficients. Choose the answer that is the sum of the coefficients in the balanced equation. Do not forget coefficients of "one". Cr2(SO4)3 + RbOH {image} Cr(OH)3 + Rb2SO4 • 10 • 12 • 13 • 14 • 15**How many moles of CO2would be produced from 56 moles of O2**according to the following balanced equation? 2C2H6 + 7O2 {image} 4CO2 + 6H2O • 16 • 32 • 224 • 48 • 8**What mass of SnCl4 must react with excess FeCl2 to produce**70.0 grams of SnCl2? SnCl4 + 2FeCl2 {image} SnCl2 + 2FeCl3 • 76.1 g • 96.2 g • 99.2 g • 106 g • 110 g**What is the maximum amount of Ca3(PO4)2 that can be prepared**from 9.8 g of Ca(OH)2 and 9.8 g of H3PO4?3Ca(OH)2 + 2H3PO4 {image} Ca3(PO4)2+ 6H2O • 6.8 g • 8.6 g • 10.3 g • 13.7 g • 15.5 g**If a reaction of 27.5 g of Fe with 63.1 g Cl2produced 60.4 g**of FeCl3, what was the limiting reactant and the percent yield? 3Cl2+ 2Fe {image} 2FeCl3 • Fe, 75.6% • Fe, 62.8% • Cl2, 41.8% • Cl2,63.0% • Fe, 37.8%**If 23.0 g of NaCl is dissolved in 300. g of H2O, what is the**percent by mass of NaCl in the resulting solution? • 0.080% • 0.767% • 7.67% • 7.12% • 21.4%**The density of a 34.0% solution of NaBr is 1.33 g/mL. What**volume of the solution contains 25.7 g of NaBr? • 101 mL • 6.57 mL • 32.8 mL • 105 mL • 56.8 mL**What mass of CaCl2 must be dissolved in enough water to**produce 2000. mL of 1.25 M CaCl2? • 174 g • 277 g • 90.7 g • 81.1 g • 310 g**How many mL of 18.4 M H2SO4 are needed to prepare 600. mL of**0.10 M H2SO4? • 1.8 mL • 2.7 mL • 3.3 mL • 4.0 mL • 4.6 mL**What volume of 3.00 molar sulfuric acid, H2SO4, is required**to react with 250. grams of calcium carbonate, CaCO3? CaCO3 + H2SO4 {image} CaSO4 + CO2+ H2O • 208 mL • 462 mL • 767 mL • 833 mL • 946 mL**What volume of 0.385 molar nitric acid, HNO3, is required to**react with 48.0 mL of 0.0770 M calcium hydroxide, Ca(OH)2, according to the following equation? 2HNO3 + Ca(OH)2 {image} Ca(NO3)2 + 2H2O • 24.8 mL • 9.62 mL • 38.4 mL • 19.2 mL • 45.0 mL