1 / 41

p*Ni><k s>²yin) smj

p*Ni><k s>²yin) smj. p*Ni<>k s>²yini[ p(rcy. p*Ni<>k s>²yini[ p(rcy. ki[e pN Fn k[ äN s>²yin[ p*Ni<>k s>²yi kh[ C[. …, -6, -5, -4, -3, -2, -1, 0, +1, +2, +3, +4, +5, +6, … s>²yir[Ki pr dr[k äN p*N<ik an[ Fn p*Ni<k s>²yin) ji[D Y) 0 Y) srKi a>tr[ aiv[l) C[. 0. 1. 2. -3. -2. 3.

sanam
Download Presentation

p*Ni><k s>²yin) smj

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. p*Ni><k s>²yin) smj

  2. p*Ni<>k s>²yini[ p(rcy

  3. p*Ni<>k s>²yini[ p(rcy • ki[e pN Fn k[ äN s>²yin[ p*Ni<>k s>²yi kh[ C[. …, -6, -5, -4, -3, -2, -1, 0, +1, +2, +3, +4, +5, +6, … • s>²yir[Ki pr dr[k äN p*N<ik an[ Fn p*Ni<k s>²yin) ji[D Y) 0 Y) srKi a>tr[ aiv[l) C[. 0 1 2 -3 -2 3 -1

  4. p*Ni<>k s>²yini[ p(rcy • aipN[ p*Ni<k s>²yin[ lil an[ p)Li (cM oiri dSi<v)S&>. • lil vt&<L äN p*Ni<k s>²yi dSi<v[ C,[ jyir[ p)L& vt&<L Fn p*Ni<k s>²yi dSi<v[ C[. Fn p*Ni<>k äN p*Ni<>k

  5. p*Ni<>k s>²yini[ p(rcy • n)c[n) aikZ(t -3 n[ 2 r)t[ dSi<vvin) r)t btiv[ C[. • -3 n[ 2 Y) vFir[ r)t[ pN dSi<v) Skiy. -3 -3

  6. p*Ni<>k s>²yini[ p(rcy • dr[k vt&<Lni[ sm&h kyi[ p*Ni<k dSi<v[ C[ t[ khi[? +1 -2 +2 jvib

  7. p*Ni<>k s>²yini[ p(rcy • ji[ lil an[ p)Li vt&<Ln) s>²yi a[k srK) hi[y ti[ t[ ke s>²yi dSi<v[ C[? • t[ 0 {S*ºy} dSi<v[ C[.

  8. srviLi[ an[ bidbik)

  9. p*Ni<>k s>²yini[ srviLi[ • aipN[ p*Ni<>k s>²yini srviLin[ vt&<Lni nm&ni Wiri smJa[. • -2 n[ ai[Ci mi ai[Ci vt&<L vD[ dSi<vi[. • +5n[ ai[Cimi> ai[Ci vt&<L vD[ dSi<vi[.

  10. p*Ni<>k s>²yini[ srviLi[ • 2 r>gni vt&<Lni sm&hi[n[ B[gi krviY) t[ ke s>²yi dSi<v[ C[? • n)c[n&> viky j[ s>²yi dSi<v[ C[ t[ lKi[. • -2 + +5 = +3 +3

  11. p*Ni<>k s>²yini[ srviLi[ • dr[k diKlini[ jvib Si[Fvi miT[ lil an[ p)Li vt&<Lni[ upyi[g kri[. -2 + -3 = ? jvib = -5 + -2 + -3 = -5

  12. p*Ni<>k s>²yini[ srviLi[ -6 + +2 = ? jvib + - 4 = -6 + +2 = -4 -3 + +4 = ? jvib +1 = + -3 + +4 = +1

  13. p*Ni<>k s>²yin) bidbik) • aipN[ GN)vir bidbik) n[ “d*r le jv&>” a[m gN)a[ C)a[. • gNtr) miT[ ke aikZ(t upyi[g) YS[? +3 - +5 = ? +3 +3

  14. p*Ni<>k s>²yin) bidbik) • ai aikZ(t +3 dSi<v[ C[ an[ aipN[ t[mi>Y) +5 ai[Ci kr) Sk)a[ C)a[ • jyir[ aipN[ 5 p)Li vt&<Ln[ ai[Ci kr)a[ , Ryir[ aipN) pis[ 2 lil vt&<L bik) rh[S[. aipN[ ai aikZ(t mi>Y) 5 p)Li vt&<L n[ d*r nh)> kr) Sk)a [, kirN k[ vt&<L ai[Ci C[.

  15. p*Ni<>k s>²yin) bidbik) • aip[l bidbik)ni diKli lil an[ p)Li vt&<L vipr)n[ kri[. -2 - -4 = ? jvib

  16. p*Ni<>k s>²yin) bidbik) hv[ tm[ 4 lil vt&<Ln[ d*r le je ai[Ci kr)Ski[ 2 p)Li vt&<L bik) rh[S[ t[Y) jvib....2 ai dSi<v[ C[ k[ -2 vt&<Lmi>Y) -4 vt&<L le jvi miT[ p&rti nY) hv[ ji[ tm[ 2 lil an[ 2 p)Li vF& vt<L um[rSi[ {S*ºy um[rv&>} ti[ tmir) pis[ k&l 4 lil vt&<L YS[ an[ hj& s&F) -2 vt&<L dSi<vS[. -2 - -4 = +2

  17. p*Ni<>k s>²yin) bidbik) ai diKli[ gNi[. +3 - -5 = ? jvib

  18. p*Ni<>k s>²yin) bidbik) • p*rti p\miNmi> lil an[ p)Li vt&<Ln) ji[D um[rviY) tm[ 5 lil vt&<Ln[ ai[Ci kr) SkSi[ • 5 lil vt&<L ai[Ci krviY) tmir) pis[ 8 p)Li vt&<L bik) rh[S[. +3 - -5 = +8

  19. p*Ni<>k s>²yin) bidbik) ai diKli[ gNi[. -3 - +2 = ? ANSWER

  20. p*Ni<>k s>²yin) bidbik) • b[ lil an[ p)Li vt&<Ln) ji[D um[ri[ j[Y) tm[ 2 p)Li vt&<Ln[ ai[Ci kr) Ski[. • 2 p)Li vt&<L ai[Ci krviY) tmir) pis[ 5 lil vt&<L rh[S[. -3 - +2 = -5

  21. p*Ni<>k s>²yin) bidbik) 3 a[k srK) s>²yini[ upyi[g kr)n[ viAt(vk s>²yi vD[ 4 sici sm)krNi[ mL[ C[. u.di. tr)k[ 7 + 8 = 15 8 + 7 = 15 15 – 7 = 8 15 – 8 = 7 ai bFij vikyi[ sici C[.

  22. p*Ni<>k s>²yin) bidbik) aipN[ viAt(vk s>²yigNn[ pN p*Ni<>k s>²yi siY[ upyi[g kr) Sk)a[ C)a[ ai viAt(vk s>²yin) ckisN) miT[ tmiri lil an[ p)Li vt&<Lni[ upyi[g kri[ -3 + +8 = +5 +8 + -3 = +5 +5 - + 8 = -3 +5 - - 3 = +8

  23. p*Ni<>k s>²yiai[ni[[ g&Nikir

  24. g&Nikir • lil an[ p)Li vt&<L ni[ nm&ni tr)k[ upyi[g kr)n[ g&Nikir kr) Skiy. • yid riKi[ g&Nikirn[ vir>vir Yt) srviLin) (k\yi tr)k[ vN<v) Skiy C[. • t[Y) 2 x 3 = ? 3vt&<Lni 2 sm&h = 6 vt&<L

  25. g&Nikir • 2 x -3 a[Tl[ -3 ni 2 sm&h 2 x -3 = -6

  26. g&Nikir • jyir[ 2 x 3 = 6 an[3 x 2 = 6 hi[y ti[ S&> a[ sic& C[ k[ -3 x 2 = -6 ? • -3 x 2 = -6 sic& C[ • +2 x -3 = -6 an[-3 x +2 = -6 a[ viAt(vk s>²yism&hni s¿yi[ C[. +2 x -3 = -6 -3 x +2 = -6 -6 ÷ +2 = -3 -6 ÷-3 = +2

  27. g&Nikir • aip[l dr[k g&Nikirni diKli vt&<Ln[ nm*ni tr)k[ upyi[g kr)n[ kri[. • +2 x +4 = ? +4 ni 2 sm*h jvib +2 x +4 = +8

  28. g&Nikir • +3 x -3 = ? jvib -3 ni 3 sm&h +3 x -3 = -9

  29. g&Nikir jvib • -2 x +4 = ? -2ni 4 sm&h -2 x +4 = -8 viAt(vk s>²yiai[ni[ upyi[g kr)n[ dSi<vi[ -2 x +4 = ?  aipN[ -2 ni +4 sm&h ni dSi<v) Sk)a[. +4 x -2 = ?  aipN[ 4 ni -2 sm&h dSi<v) Sk)a[.

  30. g&Nikir • +1, -1 (v@¹F s>²yi C[. jvib (v@¹F s>²yi aivS[. • +2 an[-2 a[ b>ºn[ a[kb)jin) (v@¹F s>²yi C[. • +2 x -3 an[ -2 x -3 b>n[ ni[ jvib (vri[F) s>²yi C[. +1 x +3 = +3 -1 x +3 = -3

  31. g&Nikir • -2 x -3 n[ dSi<vvi miT[ -3 n) (v@¹F s>²yi ni 2sm&hni[ upyi[g krvi[. -2 x -3 = +6

  32. g&Nikir • -3 x -4 ni[ S&> jvib aivS[ t[ dSi<vvi miT[ vt&<Lni[ upyi[g kri[ jvib +4 ni 3 sm&h {-4 ni (vr[iF)} -3 x -4 = +12

  33. p*Ni<>k s>²yini Bigikir

  34. Bigikir • +12 ÷ +3 ni[ jvib vt&<Lni[ upyi[g kr) Si[Fi.[ dr[k sm*hmi> 4 p)Li vt&<L C[. 12 p)Li vt&<Ln[ 3 a[k srKi sm*hmi> (vBiJt kri[ +12 ÷+3 = +4

  35. Bigikir • -15 ÷ +5 ni[ jvib vt&<Lni[ upyi[g kr) Si[Fi.[ -15 n[ 5 a[k srKi sm&hmi> (vBiJt kri[. -15 ÷+5 = -3

  36. Bigikir • viAt(vk s>²yism&h lKi[. • -4 x +2 = -8 • tmiri jvib srKivi[. • +2 x -4 = -8 • -8 ÷ +2 = -4 • -8 ÷ -4 = +2

  37. Bigikir • n)c[ni dr[k jvib Si[Fvi miT[ lil an[ p)Li vt&<Lni[ upyi[g kri[. 1) -2 + -8 5) +3 x -4 2) +6 + -4 6) -5 x -2 3) -5 - +4 7) -12 ÷ +6 4) -6 - -7 8) -8 ÷ +2 jvib

  38. Bigikir 1) -2 -8 = -10 + 2) +6 -4 = +2 +

  39. Bigikir 3) -5 +4 = -9 - 4) -6 -7 = +1 -

  40. Bigikir 5) +3 x -4 = -12 6) -5 x -2 = +10 -2 n)(v@´F s>²yini 5 sm*h C[.

  41. Bigikir -12 n[ 6 a[k srKi sm*hmi> vh[>cvimi> aiv[l C[. 7) -12 ÷+6 = -2 8) -8 ÷+2 = -4 4 a[k srKi sm*hmi> vh[cvimi> aiv[l C[.

More Related