1 / 23

baøi 14:

baøi 14:. Caùc sô ñoà phaûn öùng vaø ñieàu cheá. Caùch trình baøy:. Vieát laïi sô ñoà cuï theå. Caàn nhôù :. - Moãi muõi teân : 1 phaûn öùng. - Moãi kyù hieäu chöa bieát : 1chaát hoaù hoïc. Vieát caùc phaûm öùng. +HCl. A 2 . CO 2. +H 2 O. A 1. NH 3. A. t o ,xt,P. +NaOH. A 3 .

sammy
Download Presentation

baøi 14:

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. baøi 14: Caùc sô ñoà phaûn öùng vaø ñieàu cheá

  2. Caùch trình baøy: • Vieát laïi sô ñoà cuï theå Caàn nhôù: - Moãi muõi teân : 1 phaûn öùng - Moãi kyù hieäu chöa bieát : 1chaát hoaù hoïc • Vieát caùc phaûm öùng

  3. +HCl A2 CO2 +H2O A1 NH3 A to,xt,P +NaOH A3 +HCl CO2 +H2O CO2 (NH2)2CO (NH4)2CO3 NH3 to,xt,P +NaOH NH3 • Caùc ví duï Caâu I: Bieát A chöùa C,H,O,N coù: mC:mH:mO:mN=3:1:4:7 vaø MA<Mbenzen Gôïi yù -Töø gôïi yù cuûa A , ta deã daøng suy ñöôïc A: ureâ -Sô ñoà vieát laïi:

  4. Caâu II: A+HCl  B+D+E B+O2 P+H2O B + P  D + ? E+Cl2 G G + NaOH  I + J to I  H+K to H+CO  M+L M+HCl  G+……... Hoaøn thaønh caùc phaûn öùng theo sô ñoà: Bieát A laø quaëng trong ñoù coù 46,67% Fe, coøn laïi laø S

  5. FeS2+ 2HCl  H2S + S + FeCl2 H2S+O2 SO2+H2O H2S + SO2 S + H2O FeCl2+Cl2 FeCl3 FeCl3 + NaOH  Fe(OH)3 + NaCl to 2Fe(OH)3 Fe2O3+3H2O to Fe2O3+CO  Fe3O4+ Fe3O4+HCl  FeCl3+…H2O + Cl2 • Gôïi yù:

  6. FeS2+H2SO4(l) X + Y + Z to X + O2 A A + Y  X + H2O Z + Cl2 D + P B+KOH  E + F to E  I + J to E+H2 L + ? L+HCl  D+……... • Caâu III: Hoaøn thaønh phaûn öùng theo sô ñoà sau:

  7. FeS2+H2SO4(l) S + H2S + FeSO4 to S + O2 SO2 SO2 + 2H2S  3S + 2H2O 3FeSO4 + Cl2 FeCl3 + Fe2(SO4)3 Fe2(SO4)3 + 6KOH  2Fe(OH)3 + 3K2SO4 to 2Fe(OH)3 Fe2O3 + 3H2O to 3Fe2O3+ H22Fe3O4 + H2O 3 2 Fe3O4+8HCl 2FeCl3+ FeCl2 + 4H2O • Gôïi yù:

  8. +H2 SO4(l) Khí A X +H2O +HCl +NaOH Khí B ddB D Khí B to +HNO3 to E F + G + H2O • Caâu IV: Hoaøn thaønh sô ñoà : Bieát khí A duøng naïp cho bình chöõa löûa.

  9. +H2 SO4(l) CO2 (NH4)2CO3 +H2O +HCl NH3 ddNH3 NH4Cl +NaOH to +HNO3 NH3 to NH4NO3 N2 + O2 + H2O • Giaûi gôïi yù:

  10. to +ddNa2CO3 +F +A Fe3O4 D Fe E FeCl3 +B FeCl3 FeCl2 FeCl2 • Caâu V: Hoaøn thaønh phaûn öùng theo sô ñoà sau: Bieát moãi muõi teân moät phaûn öùng

  11. +ddNa2CO3 +Cl2 Fe Fe(OH)3 to FeCl3 Fe2O3 +Cu Fe3O4 FeCl2 FeCl2 FeCl3 2FeCl3+3Na2CO3+3H2O=2Fe(OH)3+6NaCl+3CO2 Fe3O4 + 8HCl + Fe = 4FeCl2 + 4H2O Fe3O4 + 8HCl + Cl2 = 3FeCl3 + 3H2O • Gôïi yù: • phaûn öùng:

  12. Caâu VI : Hoaøn thaønh phaûn öùng: to A + O2 B B + D  E + F + G E + NaOH  I + ? F + KOH  J + ? I + O2 + G  J E + Cl2 H + F F + Ba(NO3)2  M + L Bieát M : Khoâng tan trong axit maïnh

  13. Giaûi: to Fe + O2 Fe3O4 Fe3O4 + H2SO4 FeSO4 + Fe2(SO4)3 + H2O FeSO4 + 2NaOH  Fe(OH)2 + Na2sO4 Fe2(SO4)3 + 6KOH  2Fe(OH)3 + 3K2SO4 Fe(OH)2 + O2 + H2O  Fe(OH)3  3FeSO4 + Cl2  FeCl2 + Fe2(SO4)3 Fe2(SO4)3 + Ba(NO3)2 BaSO4 + Fe(NO3)3

  14. X + A +D E +F + ? Fe G E +I + ? J L X + B to (muøi tröùng thoái)+ ? + D +K X G+…..… Caâu VII :hoaøn thaønh sô ñoà sau : Bieát A,B ñieàu ñôn chaát,moãi muõi teân 1 phaûn öùng

  15. +HCl Fe3O4 + H2 FeCl2 +Cl2 +Fe FeCl2 FeCl3 Fe +HCl +S FeCl2 + H2S FeS to Fe3O4 + C +O2 +HCl Fe3O4 FeCl3+FeCl2+H2O Giaûi

  16. Caâu VIII : Hoaøn thaønh caùc phaûn öùng theo sô ñoà sau: to KClO3 A + B ñpnc B  D + E D + H2O  dd F to E + F  ?

  17. to KClO3 O2 + KCl ñpnc 2KCl 2K + Cl2 K + H2O  ddKOH to Cl2 +2KOH  KClO + KCl + H2O tocao KClO3 + KCl + H2O Cl2 +KOH tothöôøng KClO + KCl +H2O Giaûi Caàn nhôù :

  18. X + Y  A + B + D A + KMnO4 + Y  B + G +H + D MnO2 + Y  G + D + E Caâu IX: Hoaøn thaønh caùc phaûn öùng Bieát E coù maøu vaøng

  19. Giaûi: Fe3O4 + HCl  FeCl3 + FeCl2 + H2O 5FeCl2+ KMnO4+ 8HCl  5FeCl3+ MnCl2+ KCl+ 4H2O MnO2 + 4HCl  MnCl2 + 2H2O + Cl2

  20. +B +G I + B + L FeCl3 +E +D FeCl3 Khí A J + B + M ñpnc A +E M Caâu X: Bieát I: maøu vaøng; J: maøu tím ñen vaø coù aùnh kim. Ñoát E cho ngoïn löûa maøu tím

  21. Giaûi: +H2S +FeCl2 S + FeCl2 + HCl FeCl3 +Fe(OH)3 +KI FeCl3 Cl2 I2 + FeCl2 + KCl +KI ñpnc Cl2 KCl

  22. +H2O +O2 +O2 A C D + B B to,Pt +A +F A + G + H2O E to Caâu XI: Hoaøn thaønh phaûn öùng theo sô ñoà sau: Bieát: A, B, C, D, E, G ñeàu chöùa nguyeân toá X, vôùi X laø phi kim coù soá oxi hoaù cao nhaát baèng 5/3 soá oxi hoaù aâm thaáp nhaát, vaø F laø hôïp chaát cuûa K. (ÑH Kinh teá TP HCM)

  23. +H2O +O2 +O2 N2H3 NO2 HNO3 + NO NO to,Pt +N2H3 +KOH NH4NO3 N2H3 + KNO3 + H2O to Gôïi yù:

More Related