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## PowerPoint Slideshow about ' 13-3 Volume of Spheres' - rudolpho-calvey

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Why You Ask?!!

- Imagine that we have a disco ball.
- Now imagine that we cut one of the squares (mirrors) of the disco ball out all the way to the center, narrowing down until it comes to a point.
- We now have a pyramid.
- Just like a sphere has an infinite amount of great circles, they have an infinite amount of these pyramids.

Height=Radius of Sphere

Why Does the Height of the Pyramid=The Radius of the Sphere?

l

- The lateral height of the pyramid cannot be the radius of the sphere because we cannot solve for an actual sphere. Instead we search for a shape that is close to a sphere (like a disco ball) and solve for that. If we try to solve for an actual sphere, we wouldn’t have a pyramid, but a curved shape, which isn’t a pyramid.
- This shape has a base that curves inward with the surface of the sphere. With a pyramid, which we CAN solve for, the lateral height would actually be longer than the radius. The height of the pyramid would be the only segment that goes from the center of the sphere to the surface of the sphere. So, we get the radius. THE END

h

l

h

Back to the equation

- V=1/3B¹h¹+B²h²+B³h³+. . . +Bªhª
- V=1/3B¹r+B²r+B³r+. . . +Bªr
- V=1/3r(B¹+B²+B³+. . . +Bª)
- V=1/3r(4)
- V=4/3

- Volume of Infinite Pyramids
- H can be replaced with the radius
- Distributive Property
- All the bases added together would be the surface area, which is 4
- Simplify

Steps

- V= 4/3r³
- 4/3(11)³
- 4/3(1331)
- 4/3(4181.4598)
- 16725.8393/3
- 5575.2798
- V=5575.3m³

Steps

- 1/2(4/3)
- 1/2(4/3)
- 1/2(4/3125)
- 1/2(166.6667)
- 1/2(523.5988)
- V=261.8

Steps

- 1/2(4/3)
- 1/2(4/3)
- 1/2(4/364)
- 1/2(85.3333)
- 1/2(268.0825)
- V=134

Find the volume of the hemisphere with a circumference of 37.68 m. Use 3.14 for .Here’s a nasty one!... Well, not really...

C=37.68m

Steps

- 37.68
- 37.68/
- r=6
- 1/2(4/3)
- 1/2(4/3216)
- 1/2(288)
- 1/2(904.7786842)
- V=452.4

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